Given that the function f (x) = MX times x + NX + 3M + n is even, and its domain of definition is [m-1,2m], then 2m + n?

Given that the function f (x) = MX times x + NX + 3M + n is even, and its domain of definition is [m-1,2m], then 2m + n?

If f (x) is an even function, then the domain of definition is symmetric about the origin, so M-1 = - 2m, and the solution is m = 1 / 3
From F (- x) = f (x), we get f (- 1) = f (1)
M-N + 3M + n = m + N + 3M + N, the solution is n = 0
So m + n = 1 / 3

Given that even function f (x) satisfies f (x + 1) = f (x-1), and X ∈ [0,1], f (x) = (x-1) &# 178;, then f (7 / 2)=

f(x+1)=f(x-1)
Then f (x + 2) = f (x)
So t = 2
So f (7 / 2) = f (7 / 2-4)
=f(-1/2)
Even function
=f(1/2)
=(1/2-1)²
=1/4

Simple calculation of 56 × 7.25 + 3.75 × 4.56-4.56

4.56×7.25+3.75×4.56-4.56
=4.56×（7.25+3.75-1）
=4.56×10
=45.6

In the following expressions, what does not satisfy the requirement of "when the value of X is even, the value is true, and when x is odd, the value is false" is:
A.x%2==0
B.x%2!=0
C.(x/2*2-x)==0
D.(x%2)

This is a matter of operator priority
A. . x% 2 = = 0, that is. (x% 2) = = 0, X is even, the result of X% 2 is 0, 0 = = 0, the result is true
B. .! X% 2! = 0, i.e. (! X)% 2)! = 0. Since the operation is! X first, the result has nothing to do with whether x is even or not
C. Because x is an integer, the result of X / 2 is also an integer. For example, 9 / 2 = 4. When x / 2 * 2 = x is even, the result is true. When x / 2 * 2 is odd, it is not equal to X
D. It should be easy to understand

39 degrees 38 minutes 9 seconds - 21 degrees 56 minutes 25 seconds

One degree equals 60 minutes, one minute equals 60 seconds
39 degrees 38 minutes 9 seconds - 21 degrees 56 minutes 25 seconds = 17 degrees 41 minutes 44 seconds

What is 0.24 times 1.25

0.3

What is 3.14 times the square of (0.8 divided by 2)

0.5024

The domain of function f (4x + 3) is the domain of (- 1,1) finding function f (x-1) - f (x + 1)

The domain of F (4x + 3) is (- 1,1)
4x+3∈(-1,7)
Then the domain of F (x) is (- 1,7)
f（x-1)-f(x+1)
Then (x-1) ∈ (- 1,7) and (x + 1) ∈ (- 1,7)
The solution is x1 ∈ (0,8), X2 ∈ (- 2,6)
Then x ∈ (0,6)
The domain is (0,6)

There are two primes, the first prime plus 2 and prime factor 3; the second prime plus 3 and prime factor 2. These two primes are () and ()

7 3

It is known that the square of a + the square of B - 17 / 4 of a + 4B + 4 = 0. To find the value of the square of a + the square of B! To process! O (∩)_ ∩)o