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If f (x) defined on R satisfies f (x + y) = f (x) + F (y) + 2XY (x, y ∈ R), f (1) = 2, then f (- 3) is equal to () A. 2B. 3C. 6D. 9
Let x = y = 0 {f (0) = 0, x = y = 1 {f (2) = 2F (1) + 2 = 6; let x = 2, y = 1 {f (3) = f (2) + F (1) + 4 = 12, then let x = 3, y = - 3 get 0 = f (3-3) = f (3) + F (- 3) - 18 {f (- 3) = 18-f (3) = 6, so choose C
The function f (x) defined on R satisfies that f (x + y) = f (x) + F (y) + 2XY (x, y belongs to R). If f (1) = 2, then f (- 3) =?
From the meaning of the title
f(1+1)=f(1)+f(1)+2=2+2+2=6=f(2)
f(-1+2)=f(-1)+f(2)-4 f(-1)=0
f(-1-1)=f(-1)+f(-1)+2=2=f(-2）
f(-1-2)=f(-1)+f(-2)+4=6
So f (- 3) = 6
The function f (x) defined on R satisfies f (x + y) = f (x) * f (y) + 2XY (x, y belongs to R). If f (1) = 2, then f (- 2) =?
In this paper, we (1) let x = 0, let x = x = 0, Let f (0) = f (0) (f (0) = (0): (0) = (0)) = = (f (0) (0)) = = (f (0) [f (0) - 1] = 0. If f (0) = 0, if f (0) = 0, then f (1) = f (1) f (1 + 0) = f (1) f (1) f (1) = 0, which is f (1) = 0, and f (1) = 1 (1) = 1, and f (1) let x (2) let x (2) let x (2) let x (2) let x (2) let x (2) let x = 1 (2) let x (2) let x (2) let x = 1 (2) x (2) let x (2) let x (2) let x (2) x (2) x (2) let x (2) let x (2) x (2) x (2) x (x if x = 1, then f (1) f (- 1) = 2 + 1 = 3. = = = > F (- 1) = 3 / 2. = = = > F (- 2) = f [(- 1) + (- 1)] = f (- 1) f (- 1) + 2 = (3 / 2) & sup2; +2 = 17 / 4, that is, f (- 2) = 17 / 4
Given a ^ 2 + B ^ 2-A + 4B + 17 / 4 = 0, find the value of a and B
Such as the title
^How many = how many power
The following four cases are the points on the function image where the first derivative of F (x) is equal to zero and the first derivative of F (x) does not exist
What are the following four situations on the function image
The first derivative of F (x) is equal to zero
The first derivative of F (x) does not exist
The second derivative of F (x) is equal to zero
The second derivative of F (x) does not exist
This is very uncertain. The first derivative of 0 may or may not be the extreme point
Who knows the simple operation of 9 / 17 × (11 / 14 + 11 / 17) × 8 / 11 + 5 / 14
Simple operation of 9 / 17 × (11 / 14 + 11 / 17) × 8 / 11 + 5 / 14
9/17×(11/14+11/17)×8/11+5/14
1. Extract the 11 in brackets into
9/17×(1/14+1/17)×8+5/14
2. Open the brackets
72/17×1/14+5/14+72/17×1/17
3. The first two items are combined, and then the third item and the last item are shared
What's the difference between one and two fifths minus its reciprocal
7/5-5/7=(49-25)/35=24/35
Solution equation: when x > 5, simplify | 15-3x | - | 2x-1 |
When x > 5, simplify | 15-3x | - | 2x-1 |
When x > 5, 15-3x is less than zero, so | 15-3x | = 3x-15
2x-1 is greater than zero, so | 2x-1 | = 2x-1
Simplify
3x-15-2x+1=x-14
4 of 17 * 1 of 7 / 1 of 17 2.4.75-9.63 + (8.25-1.37) 3.1 and 2 of 9*
1.17:4 * 7:1 / 17:12.4.75-9.63 + (8.25-1.37) 3.1 and 9:2 * 1.8 / (0.5-1 / 3) 4. (3 / 4 + 4 / 6-24:13) * 125.65 divided by 40 * 12.5% 6.8:5 * 0.25 + 37.5% * 7.75% x + 60
twenty
1.17 of 4 * 7 of 1 / 17 of 1 = 4 / 17 × 1 / 7 × 17 = 4 / 7; 2.4.75-9.63 + (8.25-1.37) = 4.75 + 8.25 - (9.63 + 1.37)] = 13-11 = 2; 3.1 and 2 of 9 * 1.8 / (0.5-1 / 3) = (11 / 9) × 1.8 △ (1 / 6) = 11 × 0.2 × 6 = 13.2; 4. (3 / 4 + 4 / 6 of 4-24)
In rational numbers, the number that is positive but not integer is (), and the number that is negative but not fraction is ()
In rational numbers, positive numbers but not integers are (positive fractions), and negative numbers but not fractions are (negative integers)
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