The integral minus - 4x equals the square of 5x - 2x - 1 is

The integral minus - 4x equals the square of 5x - 2x - 1 is

Minus - 4x equals the square of 5x - 2x - 1, the integral is: 5x & # 178; - 6x-1

Solution equation: x ^ 4-10x ^ 3 + 120x + 144 = 0

(x+2)(x-6)(x^2-6x-12)=0
The solution is that the four roots are
x=-2
x=6
or
x=3±√21

If the general term an of sequence an = 1 / n-1 / N + 1 / N, find the value of a1 + A2 + a3 + A4 + A5

an=1/n-1/(n+1)
a1+a2+a3+a4+a5
=1/1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+1/5-1/6
=1-1/6
=5/6

How to solve 1260-14x = 360 + 6x?

1260-360 = 14x+6x
900 = 20x
x = 45

min=2*x1+3*x2; x1+x2>=350; x1>=100; 2*x1+x2

At least I don't have any questions here. If you have any questions, please give me the specific prompt text

To make 4A & # 178; + Ma + 1 / 4 a complete square, then ()
A.m=-2
B.m=2
C.m=±2
D.m=±1

c
4a²+ma+1/4=﹙2a±1/2﹚²=4a²±2·2a·1/2＋1/4
∴m＝±2

AB and CD are two strings on the circle O. OM and on are the distances from the center O to them respectively. If AB is larger than CD, what is the relationship between the sizes of OM and on? Why

If AB > CD
Then om < on
Because om & sup2; = R & sup2; - (AB / 2) & sup2;, on = R & sup2; - (CD / 2) & sup2;
∵AB＞CD
∴OM＜ON

"The cube of my age is four digits, and the fourth power is six digits. They just use 0123456789

Suppose the age is X,
Cube is a four digit number range: 10

How to test whether the leakage protector works

This is too simple. After you connect the wire, you can simulate the actual leakage test. For example, wrap the bare copper wire around the zero line of the live wire with water soaked adhesive tape or tape, and put the tape tightly together. If the switch is good, it will trip. Or connecting a wire from the zero line to the ground will also trip

Find the maximum and minimum of negative integer a, so that the equation 4x / 3-A = 2x / 5 + 140 about X has positive integer solution

4x/3-a=2x/5+140
14x/15=140+a
x=150+15a/14
If x is a positive integer solution, then x > 0
150+15a/14>0
a>-140
A is a negative integer