If the sum of the maximum and minimum of the function y = log a (x + 1) on [0,1] is - 1, then the value of a is

If the sum of the maximum and minimum of the function y = log a (x + 1) on [0,1] is - 1, then the value of a is


Because y is monotone, the maximum value is at the end of the interval
So y (0) + y (1) = - 1
That is, loga (1) + loga (2) = 1
The result is: loga (2) = 1
A = 2



Ln the logarithm of B with a as the base and the LNA with B times as the base?


First of all, do you mean ln or log when you say "LN is the logarithm of B with a as the base"? If it is log and the domain is a > 0.ln, I think you are mistaken==
Then, the domain of blna is a > 0



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Why is the work of the ampere force equal to the Joule heat produced on the resistance?


The conductor bar cuts the magnetic induction line, which is equivalent to a power supply to R. according to the conservation of energy, all the electric work of the power supply is used to heat the resistance! That is, the electric work of the power supply is equal to the Joule heat on the resistance
Secondly, the conductor bar is equivalent to the power source, so the non electrostatic force of the power source is the ampere force, so the work done to overcome the ampere force is equal to the electric work of the power source
Remember: in the problem of electromagnetic induction, Ampere force is the bridge between electric energy and other forms of energy, work = energy conversion
For example, if a power supply and a guide rail are placed horizontally, and a metal bar is placed on the guide rail, regardless of all friction, the current flowing through the conductor bar is I, then the ampere force must be B I l. after the conductor bar moves for a certain distance, the electric energy consumed in the circuit is divided into two parts, one is electric heating, the other is electric heating, Part of the energy is converted into the mechanical energy of the conductor rod (only kinetic energy). The value of the mechanical energy is equal to the work done by Ampere force



Simplification [(AB + 1) (AB-1) - 2A ^ 2B ^ 2 + 1] / AB
Step formula





In the circuit shown in the figure, the power supply voltage is u = 60V, the internal resistance is ignored, the resistance R is 2 ohm, and the internal resistance R1 of the motor is 1.6 ohm
The indication of the voltmeter is 50V. Calculate the output power of the motor (R is on the trunk road, R1 is in parallel with the voltmeter, it can't be drawn, please describe it)
There is a step of 60-50 = 10V in the process of answering questions, mainly because I don't know why I need to convert to resistance R
Ladies and gentlemen, please have a clear look. I know the process of solving the problem. What I don't understand is why we can't calculate the current in the series circuit directly by using the voltage of the motor (the voltage is 50V) and the internal resistance of the motor R1 = 1.6 ohm.
Who can help me quickly answer this thinking doubt, thank you very much!


Because R and motor are connected in series, the current is the same as 10 / 2 = 5a, so the input power of motor is 5A * 50V = 250W, P output = 250w-5a * 5A * 1.6 Ω = 210 Ω



As shown in the figure is the velocity time image of a particle. It can be seen from the image that the acceleration of the particle in 0-2s is______ The acceleration in 2-3s is______ The acceleration in 4-5 seconds is______ .


Acceleration in 0 ~ 2S: a = △ V △ t = 3 − 02 = 1.5m/s2, if the slope of the line in 22 ~ 4S is zero, then the acceleration is 0. Acceleration in 4 ~ 5S: a = 0 − 35 − 4 = - 3m / S2, so the answer is: 1.5m/s2, 0, - 3m / S2



Who can help me to see what the symbols in this circuit diagram mean





An object placed on a smooth horizontal plane moves with acceleration a under the action of horizontal pulling force F. now the pulling force F is changed to 2F (still in horizontal direction), and the acceleration of the object's motion becomes a ′. Then A.A ′ = a
B.a<a′<2a
C.a′=2a
D. Why do you choose d instead of C?


If the horizontal plane is not smooth, choose D. if the horizontal plane is smooth, only C is correct
There should be a problem with the answer



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