What is ln (A-1) equal to

What is ln (A-1) equal to


Ln (A-1) is the simplest form. What else can it be equal to?
It is possible to simplify the result of calculation unless we tell the value of A



What is a equal to under a-1-2a * ln radical


a-1-aIna



What is ln (1 / E) equal to


=lne^(-1)
=-lne
=-1



What is the solution of x ^ 3-5.5x ^ 2 + 7X-2 = 0?


The equation has three solutions, which are 0.40523299, 1.300896285 and 3.793870725
The results calculated by the program are not exact solutions, but the errors are all below 0.000000001



0.15 to 0.3, 5 / 6 to 1 / 6, 7 / 12 to 3 / 8, 0.125 to 5 / 8
Like 48:40
=48/40
=Six fifths


One half
five
fourteen-ninths
fifth part



If S4, S10 and S7 are equal proportion series, A1, a7 and A4 are equal proportion series
(2) Let S3 = 3 / 2, S6 = 21 / 16, BN = x * an-n * n, if {BN} sequence is monotone decreasing sequence, find the value range of real number X


Let an = AQ ^ (n-1) Sn = a (1-Q ^ n) / (1-Q) 1. S4 = a (1-Q ^ 4) / (1-Q) S10 = a (1-Q ^ 10) / (1-Q) S7 = a (1-Q ^ 7) / (1-Q) S4 * S10 = (S7) ^ 2 [a (1-Q ^ 4) / (1-Q)]] = [a (1-Q ^ 7) / (1-Q)] ^ 2 (1-Q ^ 4) (1-Q ^ 10) = (1-Q ^ 7) ^ 21-q ^ 4-q ^ 10 + Q ^ 14 = 1-2q ^ 7 + Q ^



How to calculate 99 times 73 how to calculate 98 times 27


99×73
=(100-1)×73
=100×73-73
=7300-73
=7227
98×27
=(100-2)×27
=100×27-2×27
=2700-54
=2645



In known isosceles trapezoid ABCD (as shown in the figure), AD / / BC, diagonal AC, vertical BD, AD + BC = 10cm, calculate the area of ABCD


1. AOD triangle area: 1 / 2 * AO * OD
2. Area of BOC triangle: 1 / 2 (10-ao) (10-od) = 1 / 2 (100-10ao-10od-ao · OD)
3. Area of AOB triangle: 1 / 2 (10ao-ao · OD)
4. Triangle area of COD composition: 1 / 2 (10od-ao · OD)
5. 1234 adds up to 50



Fill in the operation symbol in o to make the equation hold. 3o3 = 2


3÷3 + 3÷3=2



It is known that the eigenvalues of the third-order matrix A are λ 1 = 1, λ 2 = - 1, and λ 3 = 2, then the eigenvalues of 2A * are


It is known that | a | = 1 * (- 1) * 2 = - 2
So the eigenvalues of a * are (| a | / λ): - 2,2, - 1
So the eigenvalues of 2A * are (2 λ): - 4,4, - 2