Quick, because 6 out of 5 times 5 out of 6 equals 1, so 6 out of 5 times 5 out of 6 is reciprocal It's a judgment question, right

Quick, because 6 out of 5 times 5 out of 6 equals 1, so 6 out of 5 times 5 out of 6 is reciprocal It's a judgment question, right

6 out of 5 × 5 out of 6 = 1, so 6 out of 5 and 5 out of 6 are reciprocal, not 6 out of 5 times 5 out of 6 are reciprocal
Are you sure you copied the title correctly? How can it be a little strange?
It seems to be a sick sentence
Anyway, I'm right

6X squared - 11xy + 3Y squared, velocity

The square of 6x - the square of 11xy + 3Y
=(3x-y)(2x-3y)

If you can calculate simply, you should simply calculate one, 50% times (20 - (2 / 7-3 / 4 divided by 45%) = 2.20% times 0.37 + 63% times 1 / 5 + 4%=

50% times (20 - (2 / 7-3 / 4 divided by 45%))
=0.5*(20-2/7+3/4*20/9)
=0.5*(20-2/7+5/3)
=10-1/7+5/6
=9 and 13 / 42
20% by 0.37 + 63% by 1 / 5 + 4%
=0.2*0.37+0.63*0.2+0.04
=0.2*（0.37+0.63）+0.04
=0.2*1+0.04
=0.24

What is the countability of rational number set

Countability is to establish a one-to-one correspondence with the set of natural numbers
Rational number set can. Irrational number set can't. real number set can't

Several problems of fraction equation in grade two of junior high school
1. 72 people are sent to a construction site to dig and transport the soil. It is known that one of the three people can just transport all the soil. How to allocate labor force to make the excavated soil be transported away in time without idling? If x people are sent to dig and other people are sent to transport the soil, how to transfer the soil?
2.4 10 14
--- + --- = -----
X X+8 X+24
3. If a commodity is sold at a price of 1375 yuan with a 20% discount, it can still make a profit of 10%. Find the equation satisfied by the purchase price x (yuan) of the commodity and the solution of X
4. When someone walks along the tram road at a constant speed, he finds that a tram comes from behind every 6 minutes, while a tram comes from the front every 30 / 7 minutes. Assuming that the tram is also at a constant speed, if a tram terminal is set up to send a car every X minutes, how about x?

72 people are sent to a construction site to dig and transport the soil. It is known that one of the three people can transport all the soil. How to deploy the soil so that the excavated soil can be transported in time without idling the work? If x people dig and others transport the soil, what kind of equation does x meet? X / 3 + x = 72, x = 54, you can't see clearly the price of a commodity is 1375 yuan, 20% discount (according to the standard)

1.9 △ () = () 5 = () 6 = 60%
2.25 more than 8 ()% and 8 less than 25 ()%
3. 20% of a number is 75% of 120. What is the number?
15% of a number is 84. What's one seventh of it?
I'm going to make money first,

1.9 △ 15 = (3) △ 5 = (6 of 10) = 60%
2.25 more than 8 (212.5)%, 8 less than 25 (68)%
3. 20% of a number is 75% of 120. What is the number?
120*75%/20%＝450
15% of a number is 84. What's one seventh of it?
84/15%*1/7＝80

An BN =? What is the n power of a minus the n power of B?
What is the n-th power of a minus the n-th power of B? The derivation process? What is the formula?

a^n-b^n=(a-b)(a^(n-1)+a^(n-2)b+a^(n-3)b^2+…… +B ^ (n - 1) and while simplifying, you name it yourself

What are the characteristics of the number divided by 2 without remainder, and what are the characteristics of the number divided by 3?
Divided by 2, there is no remainder: 40.408.274.970.466, omitted after divided by 3, there is no remainder; 15.735.630, the rest omitted

All even numbers divided by 2 have no remainder. All numbers divisible by 3 can be divided by 3

8.5 + (5.6-4.8) × 13 △ 2.5 simple calculation

8.5+(5.6-4.8)×13÷2.5
=8.5+0.8×13÷2.5
=8.5+(0.8×13×4)÷(4×2.5)
=8.5+(0.8×52)÷10
=8.5+4.16
=12.66

Differential equation homogeneous differential equation 2x ^ 3Y '= y (2x ^ 2-y ^ 2)

The original formula is: y '= (2yx ^ 2-y ^ 3) / (2x ^ 3) let u = Y / x, then: y = UX, y' = u + X * Du / DX can be obtained by substituting the above formula: X * Du / DX = - 1 / 2 * u ^ 3, that is: - 2du / u ^ 3 = DX / x, then 1 / u ^ 2 = lncx, C is constant, so: (x / y) = ± (lncx) ^ (1 / 2) (Y ≠ 0) in addition, y = 0 obviously also