What are the ways to read Luodu

What are the ways to read Luodu


It's raining, it's raining
La four, falling things
Lao four, fall ill



What kinds of pronunciation do you have? Please group words by pronunciation


Poor (CH à)
1. Mistake: bad words
Not quite: almost
3. Deficiency: ten yuan less
4. Not good, not up to standard: poor, etc
Poor (CH ā):
Difference: difference; difference; difference; difference; difference
2. Roughly OK: poor
Error: error; deviation; error
4. Mathematically, it refers to the difference in subtraction
Difference (CH ā I): 0
1. Dispatch: dispatch
2. Formerly known as the dispatched person: messenger; solution
3. What was sent to do: errand; tolerance; business trip
Poor (c)
(C ā n) difference; uneven



There are several pronunciations of and, each of which requires word formation


H é relaxation
Hu ó and noodles
H è
H ú (playing mahjong) and
Hu He thin mud
Warm



Find the value of the derivative of y = 4 * x * y + X. ^ 2 with respect to X at x = 3,4,6,8


clear;clc
syms x y
eq=4*x*y+x^2-y;
y=solve(eq,y);
dy=subs(diff(y),x,[3,4,6,8])



If a: B = 4:3, B: C = 7:5, then what is a: B: C equal to?
A simple algorithm is given,


Let's look at a: B = 4:3, that is to say, if a has 4, B must have 3, if a has 40, B must have 30, if a has 4K, B must have 3K. If a has 4 times 7, B will have 3 times 7, and then look at B: C = 7:5. Similarly, if C has 5u, B must have 7U



A parallelogram with a base of 18 cm and a height of 8 cm. Pull it into a rectangular shape with an area of 36 square cm. Find the circumference of the original parallelogram


18 * 8 = 144 square centimeter
(144 + 36) / 18 = 10 cm
(10 + 18) * 2 = 56 cm
The perimeter of the original parallelogram was 56 cm



It is known that the point P (1, m) is on the image of inverse scale function y = K / x, and the symmetric point P 'of point P about X axis is on the image of linear function y = ax + B
If the image of the first-order function y = ax + B passes through points m (3, - 1) and n (1, - 3), the expressions of the first-order function and the inverse scale function are obtained


Taking the points m (3, - 1) and n (1, - 3) into y = ax + B, we get: 3A + B = - 1, a + B = - 3, the solution is: a = 1, B = - 4, then the first-order function: y = x-4 and P (1, m) about the x-axis symmetric point P '(1, - M) is on the first-order function  1-4 = - M = = > m =



Let f (x) = x square + BX + C satisfy f (1) = - 4, f (2) = - 5 / 3f (4) to find the minimum value of this function


F (1) = - 4, f (2) = - 5 / 3f (4), B + C = - 5, 11b + 4C = - 34
We can get f (x) = x & sup2; - 2x-3 = (x-1) & sup2; - 4



Some isosceles right triangle, a waist length of 1690 decimeters, the triangle area is ()


1415671:
1690dm×1690dm÷2=1428050dm²=14280.5m²
A: the area is 1428050 square decimeters
Good luck and goodbye



The left and right focus F1, F2 of hyperbola x ^ 2-y ^ 2 = 1, a point P in the second quadrant is on double, and ∠ P = 60 ° (1) find pf1pf2 (2) find P coordinate


1. Let Pf1 = n, PF2 = m, then M-N = 2, so m ^ 2 + n ^ 2-2mn = 4, that is m ^ 2 + n ^ 2 = 4 + 2Mn,
According to the cosine theorem, m ^ 2 + n ^ 2-2mncosp = (F1F2) ^ 2 = 8, so Mn = 4, so vector Pf1, vector PF2 = mncosp = 2
2. From the focal triangle area s = B ^ 2tanp / 2 = radical 3 / 3, and S = (| F1F2 | YP |) / 2 = C | YP | = | YP | radical 2,
So root sign 3 / 3 = | YP | root sign 2, so | YP | = root sign 6 / 6, which is substituted into hyperbola to get XP = - root sign 42 / 6,
So p (- radical 42 / 6, ± radical 6 / 6)