The third power of (2x to the nth power multiplied by y to the 2n power) divided by (negative XY) to the 2n power (n is a positive integer)

The third power of (2x to the nth power multiplied by y to the 2n power) divided by (negative XY) to the 2n power (n is a positive integer)

The third power of (2x to the nth power multiplied by y to the 2n power) divided by the 2n power of (negative XY)
=The power n of 8x multiplied by the power 4N of Y

Calculate (2n power of X - 2n power of 2x + 2n power of Y) / (n power of X - n power of Y)

(2n power of x-2x-n power of Y + 2n power of Y) / (n power of X-Y) = (n power of X-Y) / (n power of X-Y) = n power of X-Y

How much is 1 + 2 + 3 + 4 + 5. + 50

1+2+3+4+5.+50
=(1+50)×50×1/2
=1275

A rectangular piece of land is 50 meters long and 3 / 5 of its length wide. How many square meters is the area of this piece of land

If the length of a rectangle is 50 meters and the width is 3 / 5 of the length, the width is 50 × (3 / 5) = 30 meters;
Available: the area of this land is 50 × 30 = 1500 square meters

Simple operation of (1 / 9 + 5 / 19) × 2 + 9 / 19

(1 / 9 + 5 / 19) × 2 + 9 / 19
=2 / 9 + 10 / 19 + 9 / 19
=One and two ninths

N is an integer, and an algebraic expression containing N is used to express that two consecutive odd numbers are integers______ Two consecutive even numbers are______ ．

If n is an integer, then the odd number is expressed by the algebraic expression of N: 2n + 1. Then two adjacent odd numbers 2n + 1, 2n + 3 or 2N-1, 2n + 1. If even number is generally expressed by 2n, then two adjacent even numbers 2n, 2n + 2 or 2n-2, 2n. So the answer is: 2n + 1, 2n + 3 or 2N-1, 2n + 1; 2n, 2n + 2 or 2n-2, 2n

What's 50 and 3 / 1 times 49 and 3 / 2?

50 and 3 / 1 times 49 and 3 / 2
=(50+1/3)(50-1/3)
=50^2-(1/3)^2
=2500-1/9
=2499 8 / 9

The area of a triangle 9 cm high is equal to that of a square 9 cm long. The bottom of the triangle is () cm

Area of triangle = (bottom × height) △ 2
Area of a square = side length × side length
----------------------
Let the base of the triangle be a
Then, the area of triangle = (a × 9) △ 2
Square area = 9 × 9 = 81
Because they are equal in area
So (a × 9) △ 2 = 81
That is, a × 9 = 162
The solution is a = 18 (CM)

78-x = 52 + X process

78-52=2× 2×=26 ×=13

The 15.42 decimeter long wire is surrounded into a semicircle with a diameter of (?) , the area is (?) ．

Let R2 π R △ 2 + 2R = 15.42 & nbsp; & nbsp; & nbsp; & nbsp; π R + 2R = 15.42 & nbsp; & nbsp; & nbsp; 5.14r = 15.42 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; R = 3 the diameter of the semicircle is: 3 × 2 = 6 (decimeter), so the area of the semicircle is: 3.14 × 32 △ 2 = 3.14 × 9 △ 14.13 (square decimeter). A: the diameter of the semicircle is 6 decimeters, and the area is 14.13 square decimeters. So the answer is: 6 decimeters; 14.13 square decimeters