log5（35）-2log5（7/3）+log5（7）-log5（1.8）

log5（35）-2log5（7/3）+log5（7）-log5（1.8）

A:
The application of the formula of changing bottom
log5（35）-2log5（7/3）+log5（7）-log5（1.8）
=log5(5)+log5(7)-2log5(7)+2log5(3)+log5(7)-log5(9/5)
=1+log5(9)-log5(9)+log5(5)
=1+1
=2

Let u be a set of real numbers R, M = {x | x ^ 2 > 4}, n = {x | log2 (x-1)

According to the theme
M=（-∞,-2）∪（2,+∞）
N=（1,3）
The overlapping part of two circles in ∩ m ∩ n = (2,3) graph
The shadow is n, and m ∩ n is removed
（1,2]
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The domain of F (x) = log2 (x ^ 2-2mx + 2m ^ 2 + 1 / m ^ 2-2) is a real number set
(1) Find all the allowed values of real number m to form a set M
(2) Proof: if all m belong to m, then f (x) > = 2

(1) Logarithmic formula x ^ 2-2mx + 2m ^ 2 + 1 / m ^ 2-2 = (x-m) ^ 2 + (m-1 / M) ^ 2 > 0
So (m-1 / M) ^ 2 > 0
The solution is m ≠ 1, m ≠ - 1, m ≠ 0
To sum up, M = {m | m ≠ 1, m ≠ - 1, m ≠ 0, m ∈ r}
(2) Prove: logarithm formula x ^ 2-2mx + 2m ^ 2 + 1 / m ^ 2-2 = (x-m) ^ 2 + (M + 1 / M) ^ 2 + 4
So the logarithm is ≥ 4
So f (x) ≥ 2

How many square centimeters has the surface area increased by cutting a cylinder with a diameter of 5cm and a height of 12cm into two parts along a straight line?
The results of the formula are all written down. Pay attention, it's vertical cutting
Another one is to make a cylindrical iron bucket without a cover. The bottom radius is 20cm and the height is 36cm. If the inside and outside of the bucket are painted, what is the area of painting? Do you still use that primer for interior and exterior painting? Is cutting two sides a cuboid

(1) Because the diameter of the bottom of the cylinder is 5cm and the height is 12cm, after cutting it into two parts along the straight line, the surface area is actually increased by the area of two rectangles with the length of 12cm and the width of 5cm. Therefore, the surface area is increased: 12 × 5 × 2 = 120 (square centimeter) (2). Make a cylindrical tin bucket without a cover, the bottom radius

If a and B are coprime numbers, what is their greatest common factor and their least common multiple?

If a and B are coprime numbers, a and B have no factors except 1;
Similarly, if a and B are coprime numbers, we can only multiply them by short division, that is, AXB = ab
answer:
If a and B are coprime numbers, a and B have large common factor (1) and small common multiple (AB)
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In the triangle ABC, ab = CD, the center line BD on AC divides the perimeter of the triangle into two parts: 12cm and 15cm, and calculates the length of each side of the triangle

Let AB = x, then ad = DC = 1 / 2Ac = 1 / 2x
(1) If AB + ad = 15, then: 1 / 2x + x = 15, the solution is x = 10,
That is ab = AC = 10, DC = 5
When BC = 12-5 = 7, the three sides of the triangle are 10,10,7, and 10 + 7 > 10, it can form a triangle;
(2) If AB + ad = 12, then 1 / 2x + x = 12, the solution is x = 8
That is ab = AC = 8, DC = 4
If BC = 15-4 = 11, then the three sides of the triangle are 8,8,11, and 8 + 8 > 11, the triangle can be formed
To sum up, the three sides of triangle are 8,8,11 or 10,10,7

The greatest common divisor of a number and 45 is 15, and the least common multiple is 180?

180÷15=12
12=3×4
3×15=45
The other is 4 × 15 = 60

Given that f (x) = (x-a) (X-B) - 2 and K1, K2 are the two zeros of F (x), then the size relation of a, B, K1, K2 is

g(x)=(x-a)(x-b)
f(x)=(x-a)(x-b)-2
The opening of G (x) is upward, and the zero point is a, B

English unit 6 words
People's education press, now

Banana banana hamburger tomato broccoli French fries French fries orange ice cream cream cream salad strawberry strawberry pear have eat Oh ah countable noun uncounta

It is known that the parabola y = AX2 + BX + C intersects the x-axis at two points a and B, and intersects the y-axis at point C, where a is on the negative half axis of x-axis and C is on the negative half axis of x-axis
It is known that the parabola y = AX2 + BX + C intersects with the X axis at two points a and B, and intersects with the Y axis at point C, where a is on the negative half axis of the X axis and point C is on the negative half axis of the Y axis. The length OA < OC of the line OA OC is the two roots of the equation x2-5x + 4 = 0, and the symmetry axis of the parabola is a straight line x = 1
1 find the coordinates of a B C 3
2. Find the analytic formula of sub parabola
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The symmetry axis X = - B / 2A = 1b = - 2A, so the original equation is transformed into: y = ax ^ 2-2ax + C, the length of OA OC ＜ OC is the two roots of equation x2-5x + 4 = 0, x2-5x + 4 = 0 (x-4) (x-1) = 0oC = 4, OA = 1, because a is on the negative half axis of X axis, and point C is on the negative half axis of Y axis, so the coordinates of point A: (- 1,0), point C coordinates (0, - 4) y = ax ^