（log2 3+log4 27）*（log3 4+log9 8）= 2 of log2 is the subscript

35/4

Log2 9 multiplied by log27 8 =? Where 9 and 8 are all above 2 and 27, eager for expert solution process

log 2 9*log 27 8=2log2 3*(3/3)log3 2=2

The value of log2 √ 2 + log9 27 + 4 Λ log4 13 is

log2 √2 +log9 27 +4^log4 13
=log2 2^(1/2) +log(3^2) (3^3) +13
=1/2+3/2+13
=15

The height of a cone is 10cm, the side view is semicircle, the side area of the cone is () and the apex angle of the isosceles triangle is ()
You don't have to do it for the first time
Is the second air 60 degrees

The second is 60 degrees

When Xiao Ming calculates the division with remainder, he wrongly writes the divisor 115 as 151, and the result quotient is 3 larger than the correct result, but the remainder is exactly the same______ ．

Because the quotient is increased by 3, the divisor (151-115) △ 3 = 36 △ 3 = 12 can be obtained 7. So the answer is: 115 △ 12 = 9 7．

The perimeter of a square and a circle is equal. Given that the side length of a square is 3.14cm, then the area of the circle is______ ．

14 × 22 = 3.14 × 4 = 12.56 square centimeter A: the area of this circle is 12.56 square centimeter. So the answer is: 12.56 square centimeter

As shown in the figure, in the pyramid p-abcd, the bottom surface ABCD is a square, and E is the midpoint of PC

This is easy to do
Connect AC and BD, set the intersection point to e, connect EP, observe the triangle APC and triangle EPC, and you will do it

The sector arc length is 18cm, the radius is 12cm, and the sector area is calculated

Sector area s = arc length l times radius r divided by 2;
Therefore, the sector area is 108 square centimeters

Let the sum of the first n terms of the arithmetic sequence an be Sn, and we know that A5 = - 3, S10 = - 40, if a (BN) is an arithmetic sequence, and B1 = 5, B2 = 8
Finding the first n terms and TN of sequence BN

a5=-3,S10=-40Sn=na1+n(n-1)d/2a5=a1+4d=-3s10=10a1+45*d=-402a1+9d=-82a1+8d=-6 (a1+4d=-3)d=-2a1=5an=5+(n-1)*(-2)=7-2na(b1)=a5=-3a(b2)=a8=-9q=3a(bn)=a(b1)q^(n-1)=-3*3^(n-1)=-3^n=7-2bnbn=(7+3^n)/2Tn=7n/2+3...

What poems are used to describe the expansion of the text

Drawing inferences from one instance
Application of synaptophysis

（log2 3+log4 27）*（log3 4+log9 8）= 2 of log2 is the subscript