The derivative of F (x ^ 3) is 3. How to find f (x)

The derivative of F (x ^ 3) is 3. How to find f (x)

A:
f'(x³)=3
Integral: F (X & # 179;) = 3x + C
So:
f(x)=3³√x+C
So:
f'(x)=x^(-2/3)

Fairy tale composition 500 words!
A story happened in a farmer's home. It makes kittens, dogs, chickens and ducklings talk, from constant quarrel to concern, reflecting the need for friendship, unity and cooperation among people

Dr. rabbit is a famous doctor with a good heart. One day, Dr. rabbit was going to an infected animal village on the opposite side to treat the animals. Dr. rabbit went to the animal village in a hurry with a big medicine box. As he walked, he came to the mountainside. Suddenly, a group of old rats tormented Dr. rabbit, some biting Dr. rabbit's hand, some biting Dr. rabbit's tail At this time, the kitten came to help. The kitten bit a mouse to pieces, and Dr. rabbit said thank you. After crossing the hill, Dr. rabbit came to the plain. It met a river. The duckling swayed and carried Dr. rabbit across the river. With the help of other residents, Dr. rabbit finally came to the animal village. He didn't even breathe, so he began to give help to the dying dog, And all the sick animals in the animal village. Village leader Ma came to thank them on behalf of all the animals. Doctor rabbit said with a smile, "friends should help and care for each other."
o(∩_ ∩)o

Given that the square difference of two consecutive odd numbers is 32, find the two numbers

(2n+1)^2-(2n-1)^2=32
8n=32
n=4
These two numbers are: 2 * 4 + 1 = 9 and 7

At least______ The length of the wire, can make a bottom area is 16 square centimeter square, height is 3 centimeter cuboid frame

4 × 4 = 16 (square centimeter), so the length and width are 4cm, (4 + 4 + 3) × 4 = 11 × 4, = 44 (centimeter); answer: at least 44cm long wire is needed

What time is it?

It should be several o'clock

The position relationship between the circle x ^ 2 + y ^ 2-4x + 4Y + 6 = 0 and the straight line x-y-5 = 0 is

X^2+Y^2-4X+4Y+6=0 =>（x-2）^2+(y+2)^2=2
The line passing through the origin and perpendicular to the given line x + y = 0
The intersection with the original line is (5 / 2, - 5 / 2)
The distance from the origin is 5 / root 2 > root 2
So we're apart

Given the nonzero vectors a and B, we prove that | a + B | = | A-B | holds if and only if the direction of a is perpendicular to that of B
Urgent. SOS!

The sufficient condition and the necessary condition should be proved separately
Sufficient condition: the square of two sides is 2Ab = - 2Ab, so AB is 0, then a and B are perpendicular to each other
Necessary condition: because a and B are perpendicular to each other, AB is 0, so 2Ab = - 2Ab, so: | a + B | = | A-B | holds

It is known that ∠ BAC = 130 ° in △ ABC, the vertical bisectors of AB and AC intersect BC at e and f respectively, then the degree of ∠ EAF is______ ．

The vertical bisectors of ∵ AB and AC intersect BC at e, F, ∵ AE = be, AF = CF, ∵ BAE = ∵ B, ∵ CAF = ∵ C, ∵ EAF = ∵ BAC - (∵ BAE + ∵ CAF) =