If a, B, LG6, LG2 + 2lg3 form an arithmetic sequence, then a + B =?

If a, B, LG6, LG2 + 2lg3 form an arithmetic sequence, then a + B =?

The tolerance is LG2 + 2lg3-lg6 = LG2 * 9 / 6 = Lg3
b=lg6-lg3=lg2
a=lg2-lg3=lg(2/3)
So a + B = LG2 + LG (2 / 3) = LG (4 / 3)

It is known that a = LG2 and B = Lg3. Try to use a and B to denote lg75

lg75=lg(5²×3)
=2lg5+lg3
=2(1-lg2)+lg3
=2-2a+b

What is log2 ^ 0.25

log2 0.25=log2 0.5^2=log2 2^(-2)=-2*log2 2=-2
You should ask the logarithm of 0.25 with 2 as the base, right?

How much is it from 1 to 100? What is the simplest way to calculate?
I want to know, please hurry up!

5050
The first and last two numbers add up to 50 101, and the remaining 50 in the middle is 5050

A geometry problem, in parallelogram ABCD, angle ABC = 75 degrees, AF vertical BC, intersection BD at point E, de = 2Ab, find angle AED

Do you have any graphics!

When the elder brother's age is the younger brother's present age, the elder brother's age is three times the younger brother's age. When the younger brother's age is the elder brother's present age, the sum of their ages is 48, and the younger brother's present age is 48______ I'm 40 years old

Because the age difference between the elder brother and the younger brother is constant, the elder brother's present age = the younger brother's present age + the difference between the two people's ages = three times of the younger brother's past age + two times of the younger brother's past age = five times of the younger brother's past age When the younger brother is 5 times the older brother's present age (5 times the younger brother's past age), the elder brother's present age = 5 times the younger brother's past age + 2 times the younger brother's past age = 7 times the younger brother's past age. At this time, the sum of the two ages = 5 times the younger brother's past age + 7 times the younger brother's past age = 12 times the younger brother's past age = 48, so the younger brother's past age: 48 ÷ 12 = 4 (years old), and the younger brother's present age is: 3 × 4 = 12 years old, a: my younger brother is 12 years old now, so the answer is: 12

If I Ka + B + C I > 1, the value of real number k is obtained

Without special value, the angle between a, B and C is 2 π / 3
So: B + C = - A, so: | Ka + B + C | = | (k-1) a | = (k-1) ^ 2 | a | ^ 2 = (k-1) ^ 2 > 1
That is: K (K-2) > 0, that is: k > 2 or K

As shown in the figure, ad is the height of △ ABC, be bisects ∠ ABC and intersects ad with E. if ∠ C = 70 ° and ∠ bed = 64 °, calculate the degree of ∠ BAC

∵ ad is the height of △ ABC, ∵ C = 70 °, ∵ DAC = 20 °, ∵ be bisection ∵ ABC intersects ad with E, ∵ Abe = ∵ EBD, ∵ bed = 64 °, ∵ Abe + ∵ BAE = 64 °,