How to find the derivative of y = (e ^ x + e ^ - x) / 2 It's urgent!

How to find the derivative of y = (e ^ x + e ^ - x) / 2 It's urgent!

The derivative of e ^ x is itself, that is e ^ x, the derivative of e ^ - x is - e ^ - x, so the derivative of = (e ^ x + e ^ - x) / 2 is y '= (e ^ x-e ^ - x) / 2

The derivative of y = 2 ^ - x E ^ - x is

y=(2e)^(-x)
y'=(2e)^(-x)*ln(2e)*(-x)'
=-(2e)^(-x)*ln(2e)

5 / 4 square meters = () square decimeters

5 / 4 × 100 = 125 (square decimeter)
5 / 4 square meters = (125) square decimeters

Yucai primary school is going to expand a stadium. If the length is increased by 5.5 meters, the area will be increased by 115.5 square meters. If the width is increased by 5.5 meters
Yuying primary school is going to expand a stadium. If the length is increased by 5.5 meters, the area will increase by 115.5 square meters. If the width is increased by 6.5 meters, the area will increase by 188.5 square meters. What is the original area

The length is x meters and the width is y meters
Then (x + 5.5) * y = x * y + 115.5.5.5y = 115.5... Y = 21
（Y+6.5)*X= X*Y+188.5.6.5X=188.5.X=29
So the original area is x * y = 609
Don't forget to answer and add units

The shortest perimeter of the parallelogram formed by two identical triangles with sides of 10cm, 12cm and 13cm is () cm
The longest circumference is () cm?

The shortest is (44) cm and the longest is (50) cm

The decomposition factor is 2A (A-3) 2-6a2 (3-A) - 8A (A-3)

The original formula is 2A (A-3) 2 + 6A2 (A-3) - 8A (A-3) = 2A (A-3) [(A-3) + 3a-4] = 2A (A-3) (4a-7)

As shown in the figure, it is a triangle shaped pattern composed of several potted flowers. Each side (including each vertex) has n + 1 (n > 1) potted flowers, and the total number of pots in each pattern
According to this rule, the quadratic equation with s and N as unknowns is

s =1/2N(n+1)

What are the morphological and structural characteristics of xerophyte leaves and hydrophyte leaves

The leaf of xerophyte: the mesophyll differentiates into palisade tissue and spongy tissue, palisade tissue is close to the upper epidermis, spongy tissue is close to the lower epidermis
Leaves of aquatic plants: mesophyll did not differentiate into palisade tissue and spongy tissue, mesophyll cells arranged loosely, and aerenchyma developed. Leaves living in water had no stomata, while plants living on water had stomata on upper epidermis and no stomata on lower epidermis

(x3-2x2y + XY2) / (x3-xy2) requires reduction

(X3-2x2y+xy2)÷（x3-xy2）
=x(x2-2xy+y2)/[x(x2-y2)]
=(x-y)2/[(x-y)(x+y)]
=(x-y)/(x+y)

A rectangular playground is 150 meters long and 80 meters wide. On a 1:250 scale plan, how many square centimeters is the area of this rectangular playground?

First, the length is 15000 cm and the width is 8000 cm; after scaling, the length is (15000 / 250) cm = 60 cm and the width is (8000 / 250) cm = 32 cm, and the area on the surface is 60 * 32 cm2 = 1920 cm2