The fifth power of (B-A) and the third power of (a-b)

The fifth power of (B-A) and the third power of (a-b)


=(b–a)5÷-(b–a)3=-(b–a)2



Calculation, the second power of 2 + the third power of 2 + +The 19th power of 2 =?,
The power is written as follows:
For example: the second power of 2, 2 2 (with a space in the middle)


Let s = 2 ^ 2 + 2 ^ 3 +... + 2 ^ 19
Then 2S = 2 ^ 3 + 2 ^ 4 +. + 2 ^ 19 + 2 ^ 20
2S-S=2^20-2^2
S=4*(2^18-1)



Compare the size of 36 to the 63rd power and 63 to the 36th power


Method 1: 36 ^ 63 = 10 ^ (63 * log (36)) = 10 ^ 98.05
63 ^ 36 = 10 ^ (36 * log (63)) = 10 ^ 64.78
Method 2: 36 ^ 63 = 6 ^ (2 * 63) = 6 ^ (42 * 3) = (6 ^ 3) ^ 42 = (216) ^ 42 > 63 ^ 36



Finding the limit: the square of 1 / SiNx - the square of 1 / X


1/(sinx)^2 - 1/x^2 = [x^2 - (sinx)^2]/[xsinx]^2= [x^2 - (sinx)^2]/x^4*x^2/[sinx]^2lim_ {x->0}[1/(sinx)^2 - 1/x^2]= lim_ {x->0}[x^2 - (sinx)^2]/x^4*x^2/[sinx]^2= lim_ {x->0}[x^2 - (sinx)^2]/x^4= lim_ {x->0...



Simple calculation of 8.75/0.8/1.25


8.75÷4/5÷5/4=8.75×5/4×4/5=8.75×(5/4×4/5)=8.75



The solution equation: {5x + 3Y = 36, {2x-7y = - 2


2x-7y=-2
X = 7y-2 / 2 is taken into the first equation
5(7y-2/2)+3y=36
5 (7y-2) + 6y = 72, each with x2
35y-10+6y=72
41y=82
Y = 2 is taken into any equation
x=6



How to calculate 630 / 14 simply


=7×90/(7×2)
=90/2
=45



If the root sign of the straight line is three X + Y-2 times the root sign three = 0, the square of the truncated circle x + the square of the truncated circle y = 4, the inferior arc is opposite to the center arc of the circle
Come on, tonight
A 6 / 6 π B 4 / 4 π C 3 / 3 π D 2 / 2 π
60 degrees C?


The known circle equation of 60 degrees is x ^ 2 + y ^ 2 = 4, so the circle is a circle with the origin as the center and radius of 2. The known linear equation is: root (3) x + Y-2 root (3) = 0, that is, y = 2 root (3) - root (3) X. if you bring it into the circle equation, you can get the solution of (2 root (3) - root (3) x ^ 2 + x ^ 2 = 4, and get x = 1 or x = 2, that is, the straight line intersects the circle at (1, root



1. What can be simple should be simple
[5 / 3-55% - (35% + 2 / 3)] divided by 2 / 5
Formula calculation
1. 40% of a number is 28 less than 60% of the number. Find the number
How much less is 3 / 4 of 1 / 2.7 than 3?
If you want to say the formula, you can't just say the answer


[5/3-55%-(35%+2/3)]/(2/5)
=[(5/3-2/3)-(55%+35%)]/(2/5)
=[1-80%]/(2/5)
=(1/5)/(2/5)
=1/2
28/(60%-40%)
3-(1/7)*(3/4)



Given the proposition p: x-8x-20 > 0, Q: x-2x + 1-A > 0, if P is a sufficient and unnecessary condition of Q, the value range of positive real number a is obtained


The solution is p: x8q: (x-1-a) (x-1-a) > 0 because a > 0, so X1 a because P is a sufficient and unnecessary condition of Q, so: 1-A > - 21 a1-a take the intersection to get 0