3x + x ^ 2-5 = 0 to solve the equation

3x + x ^ 2-5 = 0 to solve the equation

3x + X "- 5 = 0x" + 3x + (3 / 2) "- 9 / 4 - 20 / 4 = 0 (x + 3 / 2)" - 29 / 4 = 0 (x + 3 / 2 - √ 29 / 2) (x + 3 / 2 + √ 29 / 2) = 0 (2x + 3 - √ 29) (2x + 3 + √ 29) = 0 solve the equation X1 = (- 3 + √ 29) / 2, X2 = (- 3 - √ 2

Solution equation: 2 (x + 1) (x + 2) = 3x (x + 2)

2X / (x + 1) = A / (x + 2) + 1 / [(x + 2) (x + 1)] both sides of the equation are multiplied by (x + 2) (x + 1) at the same time to get: 2x (x + 2) = a (x + 1) + 1. The root addition can only be - 1 or - 2x = - 1, which is substituted into the above formula to get: - 2 (- 1 + 2) = 1, which does not conform to x = - 2, which is substituted into the above formula to get: 0 = - A + 1, which is a = 1. Therefore, it can only be a = 1. I appreciate your diligent and inquisitive spirit very much

X / 4 + 1 = 0.3x + 1 / 0.1 + 1.2 to solve the equation

X / 4 + 1 = 0.3x + 1 / 0.1 + 1.2 to solve the equation
x/4+1=3x+10+1.2;
3x-x/4=1-11.2;
11x/4=-10.2;
x=-40.8/11;
x=-408/110;
x=-204/55;
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Arrange the natural numbers into the following matrix: 1, 2, 4, 7, 11 3，5，8，12，… 6，9，13，… 10，14，… 15，…… Now it is stipulated that the row is horizontal and the column is vertical? (2) Which number is in row 5 and column 10? (3) What's the row and column of 2004?

(1) The first number in the fifth column is 11, and the difference between the first and second rows in the fourth column is 5. According to rule 3, the difference between the first and second rows in the fifth column is 6. According to rule 2, the difference between the first and second rows in the tenth column is 11 + (6 + 7 + 8 + 9 + 10 + 11 + 12 + 13 + 14) = 11 + (6 + 14) × 9 △ 2 = 101. A: the fifth row in the tenth row is 101. (2) the first number in the fifth row is 15, while the fourth row is 101 The difference between the two numbers in the first and second columns is 4. According to rule 3, the difference between the two numbers in the first and second columns in the fifth row is 5. According to rule 2, the difference between the two numbers in the fifth row and the tenth column is 15 + (5 + 6 + 7 + 8 + 9 + 10 + 11 + 12 + 13) = 15 + (5 + 13) × 9 △ 2 = 96. Answer: the difference between the two numbers in the fifth row and the tenth column is 96 When n = 63, 63 × 64 △ 2 = 2016, so 2004 is in the 63rd diagonal row, and the first number of this diagonal row is 1954, that is, 1954 is in the 63rd column of the first row, because 2004-1954 = 50, 2004 is in the 1st + 50 = 51 (row), and 63-50 = 13 (column). Answer: 2004 is in the 51st row and 13th column

In ⊙ o, if the center angle ∠ AOB = 90 ° and the distance from point O to chord AB is 4, then the diameter length of ⊙ o is ()
A. 42B. 82C. 24D. 16

As shown in the figure, the crossing point O is OC ⊥ AB, the perpendicular foot is C, ∵ - AOB = 90 °, a = ∵ AOC = 45 °, OC = AC, ∵ co = 4, ∵ AC = 4, ∵ OA = 42, and the diameter length of ∵ o is 82

x-1/0.5=0.5x-4/0.25

x-2=x/2-16
x/2=-14
x=-28

Finding the radius of the inscribed circle of a right triangle with right sides 6 and 8
Is to find the format

A right triangle with right sides 6 and 8
The hypotenuse is 10
Radius of inscribed circle = (6 + 8-10) △ 2 = 2

Solving equation (10% × 50 + x) / (50 + x)
（10％×50＋X）÷（ 50＋X）
（10％×50＋X）÷（ 50＋X）=20％

（10％×50＋X）÷（ 50＋X）=20％
=>（5＋X）÷（ 50＋X）=20％
=> 5＋X = 20％ x（ 50＋X）
=> 5＋X = 10 + 0.2X
=> 0.8X = 5
=>X = 6.25 (positive solution)

Given the root X of the curve y = 2 * ~ find the tangent equation of the curve at point P (1.2) ~ find the tangent equation of the curve passing through point P (0.2) and tangent to the curve

Y = 2 √ x is the part of Y & sup2; = 4x above the x-axis,
The tangent equation y & acute; y = 2 (x + X & acute;),
So the tangent equation at point P (1.2) is
2Y = 2 (x + 1), that is, 2x-2y + 1 = 0
One of the lines passing through the point P (0.2) and tangent to the curve is x = 0,
The other is Y-2 = K (x-0), i.e. y = KX + 2, substituting Y & sup2; = 4x
k²x²+4(k-1)x+4=0,
From Δ = 16 (k-1) & sup2; - 16K & sup2; = 0, k = 1 / 2 is obtained and substituted into tangent equation
Y = 1 / 2x + 2, that is x-2y + 4 = 0
So there are two tangent lines: x-2y + 4 = 0 and x = 0,
Where x = 0 is a semi tangent

1、 1. The following statement is wrong: A. negative integers and negative fractions are collectively referred to as negative rational numbers B. positive integers, 0. Negative integers are collectively referred to as integers C. positive rational numbers

A is wrong