Given X-Y / y = 8 / 3, find the value of X + Y / y

Given X-Y / y = 8 / 3, find the value of X + Y / y

(x-y)/y=x/y -1=8/3
x/y=1+8/3=11/3
(x+y)/y=x/y +1=11/3 +1=14/3

If x + 4 of 3 = y + 3 of 2 = Z + 8 of 4, and X + y + Z = 12, find the value of x.y.z

(x + 4) / 3 = (y + 3) / 2 = (Z + 8) / 4, x = (3Y + 1) / 2, z = 2y-2, (3Y + 1) / 2 + y + 2y-2 = 12, y = 3, x = 5, z = 4

What is (- 52) + (- 7) equal to

(-52)+(-7)
=-52-7
=-59

It is known that three sides a, B and C of a triangle satisfy a + B + C = AB + BC + AC. the shape of the triangle is determined by the multiplication formula

2A + 2B + 2C = 2Ab + 2BC + 2Ac
The formula is as follows
(a-b) square + (B-C) square + (A-C) square = 0
So A-B = 0
b-c=0
a-c=0
So a = b = C
Then this is an equilateral triangle

A mathematical problem in 2011
The known function y = f (x) = - x ^ 3 + ax ^ 2 + B (a, B in real number range)
(1) In order to make f (x) an increasing function on (0,1), the value range of a is obtained;
(2) If x belongs to (0,1), the obliquity of the tangent at any point on the image of y = f (x) is angle a, when 0=

Analysis:
The derivative of F (x) is f '(x) = - 3x ^ 2 + 2 * a * X,
①
Then - 3x ^ 2 + 2 * a * x is constant > 0 on (0,1), and then the parameter a is separated,
That is, a > 3 * x / 2 is derived from - 3x ^ 2 + 2 * a * x > 0,
Because x is on (0,1),
So the range of a is a > 3 / 2
②
From known 0

3 / 4x-50 × 2 / 5 = 19 solution equation

3/4X-50×2/5＝19
3/4X-20＝19
3/4X=20+19
3X/4=39
X=39*4/3
X=52

(6 / 5-9 / 5) divided by (1 / 2 + 7 / 18) =?

(6/5-9/5)/(1/2+7/18)
=-3/5)x9/8
=-27/40

Given the quadratic function y = AX2 + BX + C, when x = 2, there is a maximum value of 2, and the length of the line cut by the image on the x-axis is 2,

Y = AX2 + BX + C, when x = 2, there is a maximum of 2
a

Calculation: 1234 + 2341 + 3412 + 4123
[thought navigation] by observing the whole pattern, we can find that the four four digits in the question are all composed of numbers 1, 2, 3 and 4, and the four digits appear once in each digit, so there is a problem
The original formula is 1 × 1111 + 2 × 1111 + 3 × 1111 + 4 × 1111
＝（1＋2＋3＋4）×1111
＝10×1111
＝11110

The first formula has 1000, the second one has 1, the third one has 10, and the fourth one has 100, so it's 1 × 1111

Given that the parabola y = (1-m) x Λ - 2mx - (M + 2) has a downward opening and has no intersection with the X axis, then the value range of M is obtained

According to the meaning of the title
1-m