Given that | x | = 12 and 3 / 4, | y | = 8 and 1 / 2, and | x + y ≠ x + y, find the value of X + y

Given that | x | = 12 and 3 / 4, | y | = 8 and 1 / 2, and | x + y ≠ x + y, find the value of X + y

Because | x + y ≠ x + y,
Description x + Y0
Then x + y = - 12 and 3 / 4 + 8 and 1 / 2
=-51/4+17/2
=-17 / 4 is minus four and a quarter
2. If y

Solving the system of linear equations X: y = 3:4 (1) x: z = 3:5 (2) x + y + Z = 36 (3)

This uses the substitution elimination method
x:y=3:4
y=4/3x
x:z=3:5
z=5/3x
Substitute (3) to get
x+4/3x+5/3x=36
4x=36
x=9
y=12
z=15

A system of linear equations with three variables, x + Y-Z = 3, X-Y + Z = - 3 - x + y + Z = 6

x+y-z=3 (1)
x-y+z=-3 (2)
-x+y+z=6 (3)
(1)+(2)+(3)
x+y+z=6 (4)
(4)-(1)
2z=3
(4)-(2)
2y=9
therefore
y=9/2
z=3/2
x=z+3-y=6

Simplification (- 3 / 2x & # 178; y) &# 178; (2x & # 178; - 4xy + 7Y & # 178;) (- 4x-3y & # 178;) (3Y & # 178; - 4x)
This is a simplification of the two questions

1)
2)（-4x-3y²）（3y²-4x）=
-(4x+3y²)(3y²-4x)=(a+b)(a-b)=a²-b²=-16x²-9y4

How to divide 85 by 2.5 by 4?

85÷2.5÷4
＝85÷（2.5x4）
=85÷10
=8.5

The line L passing through the point m (1,2) divides the circle (X-2) 2 + y2 = 9 into two arcs. When the inferior arc is the shortest, the equation of line L is ()
A. x=1B. y=1C. x-y+1=0D. x-2y+3=0

Let the center of the circle be o, then o (2,0), х Kom = 2 − 01 − 2 = - 2. The slope of х line L is k = 12, and the equation of х L is Y-2 = 12 (x-1), that is, x-2y + 3 = 0. So D is chosen

What is 3x in 7 divided by 2 in 5 (in terms of solving the equation)
I'd better hurry up. I'll reward more for my wealth
The process of solving the equation!!!

15x/14

It is known that P: x2-8x-20 ＞ 0, Q: x2-2x + 1-a2 ＞ 0. If P is a sufficient and unnecessary condition of Q, the value range of positive real number a is obtained

p: X ＜ - 2 or ＞ 10, Q: X ＜ 1-A or X ＞ 1 + a ∵ where p is a sufficient and unnecessary condition for Q, ∵ 1 − a ≥ − 21 + a ≤ 10, that is, 0 ＜ a ≤ 3

(1 / 5 + 2 / 3) * 15?

(1/5+2/3)*15
=1/5*15+2/3*15
=3+10
=13

As shown in the figure, make two mutually perpendicular straight lines through the origin O and intersect with the parabola y ^ 2 = 4x at O, a and O, B respectively. If the line AB is exactly bisected by the straight line y = 3, find ab

Let two straight lines y = KX, y = - X / K (k > 0)
They are connected with parabola respectively
→ X1 = 4 / K & # 178;, X2 = 4K & # 178; (x1, X2 are abscissa of a and B respectively)
→y1=4/k,y2=-4k
→y1+y2=2*3
→4/k-4k=6
→(2k-1)(2k+2)=0
→ k = 1 / 2 or K = - 1
Why don't you count for yourself?