On the linear equation of one variable with absolute value Solve the following equation: 1.|x-|3x+1||=4 2.|x+3|-|x-1|=x+1 3.|x-1|+|x-5|=4 1. Discuss the number of solutions of the equation | 2x-2 | + | 2x-5 | = a about X 2. Given that the equation | x | = ax + 1 has a negative root but no positive root, find the value range of A

On the linear equation of one variable with absolute value Solve the following equation: 1.|x-|3x+1||=4 2.|x+3|-|x-1|=x+1 3.|x-1|+|x-5|=4 1. Discuss the number of solutions of the equation | 2x-2 | + | 2x-5 | = a about X 2. Given that the equation | x | = ax + 1 has a negative root but no positive root, find the value range of A

From the original equation, we get X - | 3x + 1 | = 4 or X - | 3x + 1 | = - 4x-4 = | 3x + 1 |, or x + 4 = | 3x + 1 | - x-4 > = 0, that is, x > = 4 or x + 4 > = 0, that is, x > = - 4x-4 = 3x + 1 or 4-x = 3x + 1 or x + 4 = 3x + 1 or x + 4 = - 3x-1x = - 2.5 or x = 0.75 or x = 1.5 or x = - 1.25

Given that the function FX satisfies f (x + y) = FX + FY for any real number XY, we prove that f (X-Y) = FX FY

If the derivative is f '(x) = 1 / x, what is the original function

f（x）=lnx+C

The function f (x) = A-1 / 2 ^ x + 1 (a ∈ R) 1 is known. It is proved that f (x) is an increasing function on (- ∞, ∞). 2. The value of a is determined so that f (x) is an odd function

(1)
Method 1: F (x) = A-1 / (2 ^ x + 1), f '(x) = 2 ^ xln2 / (2 ^ x + 1) ^ 2 > 0, so no matter what a is, f (x) is always an increasing function;
Method 2: take x1, X2 and X1 in R

If a and B are symmetric matrices of order n, then 2a-3b and ab-ba are also symmetric matrices

If a and B are symmetric matrices of order n, then transpose of a = a, transpose of B = B. transpose of (2a -- 3b) = transpose of 2 * a - transpose of 3 * b = transpose of 2A -- 3B 〈 2a-3b is also symmetric matrix. Transpose of (AB -- BA) = transpose of (AB) - (BA) = transpose of B * transpose of a - transpose of a * transpose of B = transpose of Ba -- AB = (AB -- BA) 〉 ab-ba

There are singular and plural in the first person, singular and plural in the second person, and plural in the third person before have

First person singular: I have
First person plural: we have
Second person singular: you have
Second person plural: you have
Third person singular: he / she / it has
The third person plural: they have

Simplified evaluation: 2 (3ax & # 178; - 2ax-3) - 3 (AX & # 178; - 4ax-1), where a = - 2, x = 3

2（3ax²-2ax-3）-3（ax²-4ax-1）
=6ax²-4ax-6-3ax²+12ax+3
=3ax²+8ax-3
=3*(-2)*9+8*(-2)*3-3
=-54-48-3
=-105

Can a great deal of modify countable nouns?

A great deal of can only be followed by uncountable nouns

Given that a, B and C are three sides of △ ABC, and A2 + B2 + C2 = AB + AC + BC, then △ ABC is ()
A. Isosceles triangle B. right triangle C. equilateral triangle D. isosceles right triangle

The original formula can be reduced to 2A2 + 2B2 + 2c2 = 2Ab + 2Ac + 2BC, that is, A2 + B2 + C2 + A2 + B2 + c2-2ab-2ac-2bc = 0; according to the complete square formula, we can get: (a-b) 2 + (C-A) 2 + (B-C) 2 = 0; from the properties of non negative numbers, we can know that A-B = 0, C-A = 0, B-C = 0; that is, a = b = C. so △ ABC is an equilateral triangle, so we choose C

According to the sentence requirements, the English words Jielong: (1) O__ (2)n__ (3)r__ (4) d__ (5) e__ (6) y__ (7) f__ (8) s__
1.I_____ get up at six o'clock.
2.My phone_____ is 5777579.
3.I_____ funny stories to my sister.
4.What's the______ today.
5.It'not______ to learn English well.
6.Come down there and see for______ .
7.Sleepless in Seattle is a_______ movie.
8.I don't think_____ .

1、often
2、number
3、read
4、date
5、easy
6、yourself
7、funny
8、so