If the absolute value of the coefficients in the numerator and denominator is the smallest integer, then the numerator and denominator of the fraction (0.02x + 0.06y) / (0.8x-0.2y) are multiplied by ()

If the absolute value of the coefficients in the numerator and denominator is the smallest integer, then the numerator and denominator of the fraction (0.02x + 0.06y) / (0.8x-0.2y) are multiplied by ()


Multiply the numerator and denominator by 100 to get (2x + 6y) / (80x-20y), but at this time, the absolute value of the coefficients in the numerator and denominator is not the smallest integer, so you need to divide it by 2 to get (x + 3Y) / (40x-10y). But at this time, the absolute value of the coefficients in the numerator and denominator is the smallest integer, so you can't reduce it. Therefore, multiply 100 first, divide it by 2 to get (x + 3Y) / (40x-10y)



Without changing the value of the fraction, the coefficients in the numerator and denominator of the fraction are integers 0.2x-0.5y/0.7x + 0.3y


Multiply the numerator and denominator by 10 at the same time
(2x-5y)/(7x+3y)



In a right angle trapezoid ABCD, ad ‖ BC (BC > AD), B = 90 °, ab = BC = 12, e is a point on AB, and DCE = 45 °, be = 4, the length of De is calculated


Square the trapezoid abcf,
There is be + DF = De
Let de = x, DF = x-4
Then AE = 12-x, ad = 12 - (x-4)
So we can use Pythagorean theorem in triangle ade



Solving equation 6x + 4x = 19 in grade five


6x+4x=19
10x=19
x=1.9



4 of () = 18 divided by () = 1 of 2 = () 7 = 9 ()
emergency


(2 / 4) = 18 divided by (36) = 1 / 2 = (7 / 14) = 9 to (18)



How to determine the value range of a, B and C in quadratic function y = AX2 + BX + C


In order to determine the value range of A.B.C in quadratic function y = AX2 + BX + C, two methods are used to determine the symmetry axis and the vertex around the Y axis



1234*432143214321-4321*123412341234


=1234*4321(1*100010001000-1*100010001000)
=0



If the parabola y = (1-m) x & sup2; - 2mx - (M + 2) has a downward opening and no intersection with the X axis, then the value range of M is?


1-m2



Factorization (18:20:3:56)
(3y-1)^2=(y-3)^2
Given a ^ 2 + 2Ab + 2B ^ 2-6b + 9 = 0, find the value of a-b


Given a ^ 2 + 2Ab + 2B ^ 2-6b + 9 = 0, find A-B:
a^2+2ab+2b^2-6b+9=0
(a+b)^2+(b-3)^2=0
b=3,a=-3
a-b=-3-3=-6
I'll always be right



Given that point a (3x-6, 4Y + 15) and point B (5Y, x) are symmetric about X axis, then the value of X + y is ()
A. 0B. 9C. -6D. -12


∵ point a (3x-6, 4Y + 15), point B (5Y, x) are symmetric about the X axis, ∵ 3x-6 = 5Y; 4Y + 15 + x = 0; the solution is: x = - 3, y = - 3, ∵ x + y = - 6, so C