What is the unit of power? What is the power per unit time? Does w refer to the electrical work consumed in one hour?

What is the unit of power? What is the power per unit time? Does w refer to the electrical work consumed in one hour?

Watt, you can convert it, the unit of one kilowatt hour is kilowatt hour, that is to say, a kilowatt thing consumes one kilowatt hour

Decomposition factor 9 (a + b) ² + 6 (A & #178; - B & #178;) + (a-b) ²

How much energy can a 1000 MAH battery store
It can store several kilowatts of electricity

You can calculate: if your battery is 1000 MAH, that is to say, your battery output current is 1000, one degree of electricity is equal to 1 kwh, battery power (WH) = battery voltage (V) x battery capacity (ah) 4.2 * 1 = 4.2 W

Simple calculation: 8 out of 13 - (5 out of 7-5 out of 13)

8/13-(5/7-5/13)=8/13-5/7+5/13=(8/13+5/13)-5/7=1-5/7=2/7

A small hydropower station generator output power is 100kW, output voltage is 500V, line resistance is 10 ohm, the allowable power consumption is output power
The output power of a small hydropower station is 100kW and the output voltage is 500V. The resistance of the transmission line is 10 ohm, the allowable power consumption is 4% of the output power, and the electricity consumption unit needs 220 V voltage. Ask: what are the turns ratio of primary and secondary coils of step-up transformer and step-down transformer

Some symbols are not easy to type. You can change them yourself
Power consumption allowed
P=100kw*4%=4kw
Maximum current on transmission line
I = under root sign (4kw / 10 Ω) = 20A
No matter the total power of step-up or step-down is constant, the voltage after step-up can be obtained
U1 = ptotal / I = 5000v
The ratio of boost turns is 500 / 5000 = 1:10
The ratio of step-down turns is 5000 / 220 = 250:11

7 × 3 / 4 + 75% × 2.3-2 △ 4 / 3

7 × 3 / 4 + 75% × 2.3-2 △ 4 / 3
= 9.7 × 3 / 4 + 3 × 2.3-2 × 3 / 4
= 3 / 4 × (9.7 + 2.3-2)
= 3 / 4 × 10
＝7.5

The range of ammeter is 100 μ a, and the internal resistance is 2000 ohm. If we change it to 200 Ma ammeter, how much should the mill be connected in parallel

After refitting, the current through the ammeter can only be 100 μ a when measuring 200mA current, and the shunt resistance is 200ma-100ua = 199900ua
At this time, the voltage at both ends of the parallel resistance and the ammeter is the same, so the resistance value r of the parallel resistance meets the following requirements: R * 199900 = 100 * 2000, r = 2000 / 1999 ohm

A mathematical calculation problem (real number)
|√3-2|+³√-8+（2-√3）×√3

Original formula = 2 - √ 3 + (- 2) + 2 √ 3-3 = √ 3-3

Physics problems about electric energy
How to understand better memory

These three are all right and can be transformed into each other. Just remember the first one. The latter two can be transformed and deduced respectively according to Ohm's law u = IR (i.e. I = u / R). It's easy to understand

Examples of applying chemical knowledge in real life
For example, the more the better

Copper will be oxidized into black copper oxide in humid air. Copper oxide on the surface of copper will continue to react with carbon dioxide in the air to form a layer of green basic copper carbonate cuco3 &; Cu (OH) 2