We know that x is equal to 2 times the following sign 3 plus 1, y is equal to 2 times the following sign 3 minus 1, and find the square of x minus 4xy plus y square?

X = 2 radical 3 + 1
Y = 2 radical 3-1
x²-4xy+y²=x²-2xy+y²-2xy=(x-y)²-2xy
=[(2 radical 3 + 1 - (2 radical 3-1)] ² - 2 * (2 radical 3 + 1) * (2 radical 3-1)
=2 & # 178; - 2 * [(2 radical 3) &# 178; - 1]
=4-2*(12-1)
=-18

120x minus x equals 24 to find X

120x-x=24
(120-1)x=24
119x=24
The solution is x = 24 / 119 ≈ 4.96

When x is equal to what number, the value of the algebraic expression X-1 \ \ 3 is - 3 greater than that of x 1 \ \ 2

According to the meaning of the title
（x-1）/3-（x-1）/2=-3
2x-2-3x+3=-18
x=18+1
x=19
For reference

The third power of (- 1) - the second power of (- 1) divided by [(- 1 / 2, the second power of (- 1) - 3 / 4] has process and result

(-1)^3 - (-1)^2 / [ (-1/2)^2 -3/4]
=-1 - 1 / [ 1/4 - 3/4 ]
= -1-1/ [-2/4]
= -1 -1/( -1/2)
=-1 +2
=1
Note: ^ 2 is the second power of

The fruit store sold 120 kg of fruit, and then transported 200 kg of fruit, which was one fifth more than the original. How many kg of fruit did the fruit store have?
How many kilos of fruit are there now?

（200-120）÷1／5=400
400+200-120=480
The fruit shop used to have 400 kg of fruit
Now there are 480 kilograms of fruit

The master and the apprentice process a batch of parts. The number of parts processed by the master is 25 more than 1 / 2 of the total number. The number of parts processed by the apprentice is 1 / 3 of the total number of parts processed by the master?
It's better to explain the formula,

Let the total number be x, and the number processed by the master: 1 / 2 times x plus 25
Number of apprentices: (1 / 2x + 25) * 1 / 3
Master processing quantity + apprentice processing quantity = Total (x)
Find x = 100

What are the three elements of sine, the maximum value of sine voltage, the effective value, the instantaneous value, the effective value phasor, and the sign of the maximum phasor

Amplitude, frequency, phase. I don't know what you're talking about!
The maximum value is the peak value, the effective value is the root 2 of the peak value, and the instantaneous value is the real value at a certain time

A school plans to organize 385 teachers and students to rent a car. Now we know that the rental company has 42 seat and 60 seat buses, and the rent of 42 seat buses is 320 yuan per car,
The rent for 60 buses is 460 yuan per car
How much does it cost for the school to rent these two buses separately?
2. If the school rents 8 of these two buses at the same time, and the rent is less than that of renting one bus alone, please choose the most economical scheme

1. All 42 seat buses need:
385 △ 42 ≈ 10 (vehicle) 10 × 320 = 3200 (yuan)
For all 60 seat buses:
382 △ 60 ≈ 7 (vehicles) 7 × 460 = 3220 (yuan)
2. The best solution is to rent 5 vehicles with 42 seats and 3 vehicles with 60 seats
5 × 320 + 3 × 460 = 2980 yuan

Let the square matrix a satisfy a * a-a-2e = 0, prove that a and a + 2E are invertible, and find 1 / A and 1 / (a + 2e)

Let the square matrix a satisfy a * a-a-2e = 0, prove that a and a + 2E are invertible, and find 1 / A and 1 / (a + 2e). Question 1: because a ^ k = 0, so (e-A ^ k) = E and (e-A ^ k) = (e ^ K-a ^ k) = (e-A) (E + A + A's 2nd power + A's 3rd power +... + A's k-1) = e {a ^ K-B ^ k} = (a-b) (A's n-1st power + A's n-2nd power * B + A's

Plural problem (urgent process)
1. Given the complex number Z = [(√ 3 + I) / 2] ^ 7, find its trigonometric form
2. Calculate (COS Π / 4 + isin Π / 4) ^ 3 / (COS Π / 12 isin Π / 12) ^ 4

Complex number problem (urgent ·· process ～) 20 - 14 days and 23 hours to the end of the problem 1. Known complex z = [(√ 3 + I) / 2] ^ 7 find its triangular form 2. Calculate (COS Π / 4 + isin Π / 4) ^ 3 / (COS Π / 12-isin Π / 12) ^ 4lzj60744 - first level answer of probation period: [1] z = [(√ 3 + I) / 2] ^ 7 = (C

We know that x is equal to 2 times the following sign 3 plus 1, y is equal to 2 times the following sign 3 minus 1, and find the square of x minus 4xy plus y square?