If the square of (x + Y-5) + / 3y-2x + B / = 0, find the value of X and y

If the square of (x + Y-5) + / 3y-2x + B / = 0, find the value of X and y

∫ (x + Y-5) ≥ 0; 3y-2x + B ≥ 0 ∫ if the sum of them is 0, then they must be 0 respectively, that is, (x + Y-5) = 0 and 3y-2x + B = 0 ∫ x + Y-5 = 0 and 3y-2x + B = 0 ∫ x = 3 + B / 5; y = 2-B / 5

-2x squared-1 / 6 [3Y squared-2 (x squared-y squared) + 6], where x = - 2, y = - 0.5

Take X and Y in - 2 * 4-1 / 6 [3 * 4 - (4-1 / 4) + 6] = - 213 / 24

It is known that: (2x + 3y-4) 2 + | x + 3y-7 | = 0, then XY=______ ．

From the meaning of the question, we can get: (2x + 3y-4) 2 = 0, | x + 3y-7 | = 0, and the equation group is 2x + 3Y − 4 = 0x + 3Y − 7 = 0. Subtracting the two equations, we can get x = - 3. Substituting the value of x into any equation, we can get y = 103, | xy = - 10

The first step is to simplify the evaluation: y to the second power of 4x - [6xy-3 (4xy-2) + y to the second power of 4x] + 1, where x = 2, y = - 1 / 2
First, simplify the evaluation
4X to the second power Y - [6xy-3 (4xy-2) + 4x to the second power y] + 1, where x = 2, y = - 1 / 2

Original formula = 4x2 ˇ Y - [6xy - (12xy-6) + 4x ˇ 2Y] + 1
=4xˇ2y-［6xy-12xy+6+4xˇ2y］+1
=4xˇ2y-6xy+12xy-6-4xˇ2y+1
=（4-4）xˇ2y+（-6+12）xy+（-6+1）
=6xy-5
When x = 2, y = - - 189
6xy-5
=6*2*（-½）-5
=-6-5
=-11

Simple calculation of 201.1 times 1999-2012 times 199.8

201.1×1999-2012 ×199.8=2011×199.9-2012 ×199.8=(2012-1)×199.9-2012 ×199.8=2012×199.9-199.9-2012 ×199.8=2012×(199.9-199.8)-199.9=2012×0.1-199.9=201.2-199.9=1.3

If the parabola xsquare = 2PY, passing through the point m (0, - P / 2), tangent to the parabola, a and B are tangent points, then the length of AB is ()
Let a (x1,1 / 2p, X1 Square), find out the slope of a, and substitute it into the parabola. How can we give the tangent equation: y = kx-p / 2, substitute it, how can we get this?
Why does the answer say: after simultaneous equations, there is a real root? Not two?
Can we set the tangent point, then do the equation passing through the tangent point and so on, and directly set the tangent equation without using the derivative

Because the tangent passes through the point m (0, - P / 2), the tangent equation is y = kx-p / 2
If the simultaneous equation has two real roots, denoted as x1, X2, then the simultaneous equation is x-2pkx + P = 0. Then, AB length d = under the root sign (1 + k) * x1-x2, where, x1-x2 = under the root sign [(x1 + x2) square-4x1x2], we can get
Of course, you can set the tangent point, and then do the equation through the tangent point, but it's more troublesome

456*55+457*45=
You can't use calculators. You can't use dead reckoning

456*55+457*45=
＝456×55＋（456＋1）×45
＝456×55＋456×45＋1×45
＝456×（55＋45）＋45
＝456×100＋45
＝45600＋45
＝45645

A number is 0.6 less than 75% of 12.8. What's the number?

12.8 × 75% - 0.6 = 9.6-0.6 = 9

Mathematical fraction problem: do not change the value of the fraction, the X + two-thirds y divided by one-half X - 2Y in the molecular denominator of the coefficient into an integer
X ≠ multiplication sign

Multiply the numerator and denominator by 6 at the same time to get
6x+4y/3x-12y

Simple calculation of 5 molecules 7 * 2 / 3 + 14 / 15 divided by 2 / 9

14 / 15 + 14 / 15 × 9 / 2
=14 out of 15 × (1 + 9 out of 2)
=14 / 15 × 11 / 2
=77 out of 15
=5 and 2 / 15