Quarter + Half + quarter = quarter × () = half × () = () Idea Click: half can be expressed as quarter + quarter

Quarter + Half + quarter = quarter × () = half × () = () Idea Click: half can be expressed as quarter + quarter

Quarter + Half + quarter = quarter × (4) = half × (2) = (1)

Math problem x + (0.4-0.35) = 1 / 4 times 1 / 2

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x+(0.4-0.35)=1/4×1/2
X+0.05=0.125
X=0.125-0.05
X＝0.075
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Ducks are one sixth more than chickens. There are 30 ducks and how many chickens

30-30*6/1=25

The known function f (x) = 3sin (K / 5) x + π / 3
There is a symmetry axis X = π / 6, and the maximum and minimum values appear at least once between any two integers. The minimum value of K can be obtained

The answer upstairs is right,
There's something wrong with the process
The maximum and minimum values appear at least once between two integers
Minimum positive period T = 2 π / (K / 5) = 10 π / K ≤ 1
The solution is k ≥ 10 π≈ 31.4
One axis of symmetry of∵function is π / 6
The function takes the maximum value at π / 6
That is K / 5 · π / 6 + π / 3 = π / 2 + n π
The solution is k = 5 + 30n, where n ∈ Z
Combined K ≥ 31.4
The minimum value of K should be 35

(1) 9x squared - 25y squared (2) m squared - 121
(3) Square of X - square of 4Y (4) - square of 1 / 9m + square of 4 / 49n
(5) The fifth power of a - the square of the fourth power (6) (2x-1) of 16ab - (x + 1)

1) 9x squared - 25y squared
=(3x+5y)(3x-5y)
(2) Square of m-121
=(m+11)(m-11)
(3) The square of X - the square of 4Y
=(x+2y)(x-2y)
(4) - 1 / 9m square + 4 / 49n square
=(2/7n+1/3m)(2/7n-1/3m)
(5) The fifth power of a - the fourth power of 16ab
=A (the fourth power of a - the fourth power of 16b)
=a(a²+4b²)(a²-4b²)
=a(a²+4b²)(a+2b)(a-2b)
(6) Square of (2x-1) - (x + 1)
=(2x-1+x-1)(2x-1-x+1)
=(3x-2)x

General term formula of sequence 1,0, - 1,0

Sin (n π / 2) or cos (n π / 2 - π / 2),
N starts with 1

If the volume formula of ball is 4 / 3 π r to the third power, the radius of ball a is r, and the radius of ball B is R + 1, how much more is the volume of ball B than that of ball a

The beauty of Mathematics
The volume of ball B is larger than that of ball a
4/3 π (R+1)³ - 4/3πR³
= 4π/3 [ (R+1)³ - R³ ]
= 4π/3 (3R²+3R+1)

Practical problems in happy mathematics class of Grade 7 Volume 1 and answers to multiple choice questions (2) and (3) of one variable linear equation

A、D、C、B、A、D、D、C

The following two groups of numbers are arranged, and the nth number is expressed by algebraic formula
（1）1,5,9,13,17,21……
（2）-1,3／4,-5／9,16／7,-25／9……

(1)4n-3
(2) The last few numerator denominators are reversed
（-1）^n（2n-1）/n^2

The sum of integers with absolute values greater than 1 and less than 5 is______ ．

The integers with absolute value greater than 1 but less than 5 have - 2, - 3, - 4, 0, 2, 3, 4, the sum of which is 0