Calculation: 4.65 × 32 + 2.5 × 46.5 + 0.465 × 430

Calculation: 4.65 × 32 + 2.5 × 46.5 + 0.465 × 430


4.65×32+2.5×46.5+0.465×430=4.65×32+25×4.65+4.65×43=4.65×(32+25+43)=4.65×100=465.



1287*1/2*3/40+3/4*870*1/4+3/4
1287 and 1 / 2 * 3 / 40 + 3 / 4 * 870 and 1 / 4 + 3 / 4


(1287+1/2)*3/40+3/4*(870+1/4)+3/4
=(1287+1/2)*3/40+3/4*(870+1/4+1)
=(1287+1/2)*3/40+3/40*(871+1/4)*10
=(1287+1/2)*3/40+3/40*(8710+10/4)
=3/40*(1287+1/2+8710+10/4)
=3/40*(1287+2/4+8710+10/4)
=3/40*(1287+12/4+8710)
=3/40*10000=3*250=750



1 * 3 * 4 * 6 * how to calculate 24?


(1^3)×4×6



The circumference of a rectangle is 26cm. If the length is reduced by 4cm and the width is increased by 2cm, the rectangle will become a square


Let the length of the side be x, (x + 4) + (X-2) = 13, x = 5.5



Simple operation of 3.4-2.2 + 7.6-5.8





Given that f (x) = a-12x-1 is an odd function defined on (- ∞, - 1] ∪ [1, + ∞), then the range of F (x) is___ .


∪ f (x) = a-12x-1 is an odd function defined on (- ∞, - 1] ∪ [1, + ∞) ∪ f (- x) = - f (x) ∪ a-12-x-1 = - A + 12x-1 ∪ 2A = 12-x-1 + 12x-1 ∪ 2A = 2x1-2x + 12x-1 ∪ [1, + ∞) ∪ [1, +) ∪ [2x ∈ (0, 12] ∪ [2



A square with a side length of 2 cm has a perimeter twice the area. It is a judgment question. How to judge?


Wrong, different units, no direct comparison



() + () = () + () = () + () = () + () = () + () use 1.2.3.4.5.6.7.8.9.10, each number can only be used once
All equations hold!


1+10=2+9=3+8=4+7=5+6



The sum of the first n terms of the sequence {an} is Sn, A1 = 1, and 2An = 1 + √ 1 + 8s (n-1), (n > = 2) to find the general term an


From 2an-1 = √ 1 + 8s (n-1) square, an ^ 2-An = 2S (n-1)
So a (n-1) ^ 2-A (n-1) = 2S (n-2) ^ 2
By subtracting the two formulas, we get [an + a (n-1)] [an-a (n-1) - 1] = 0
Because an > 0, so an = a (n-1) + 1, and A1 = 1, so {an} is an arithmetic sequence
an=1+(n-1)*1=n



The school needs 500 square bricks with a side length of 2 mm, and how many square bricks with a side length of 4 DM?


Suppose you need x bricks. According to the meaning of the question, 4 × 4x = 2 × 2 × 500 & nbsp; & nbsp; & nbsp; 16x = 2000 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; X = 125 A: you need 125 such square bricks