If the area ratio of two similar triangles is 4:9, the perimeter of the two triangles is

If the area ratio of two similar triangles is 4:9, the perimeter of the two triangles is


“jlysww”:
Is it to find the perimeter ratio of two triangles?
Perimeter ratio = √ 4: √ 9 = 2:3
A: the perimeter ratio is 2 to 3
Good luck and goodbye



The least common multiple of two numbers is 240 and the greatest common divisor is 20. One of them is 60 and the other is ()


The least common multiple of two numbers is 240, the greatest common divisor is 20, one of which is 60, the other is (80)



It is known that the slope of line L1 is 2. There are three points a (3,5) B (a, 7) C (- 1, b) on line L2. If L1 is perpendicular to L2, what is a equal to


Line L2 y = - 1 / 2x + M
5=-3/2+m
m=13/2
y=-1/2x+13/2
7=-1/2a+13/2
a=-1
b=1/2+13/2
b=7



feed animal ____ food
What preposition is used in the middle





It is known that the three vertices of an equilateral triangle OAB are on the parabola y ^ 2 = 2x, where o is the origin of the coordinate. Let C be the circumscribed circle of the triangle OAB, and then the equation of the circle is obtained


The slope of OA is tan30 ° = 1 / √ 3, and the equation is y = x / √ 3. Substituting it into the parabolic equation y ^ 2 = 2x, we get x = 0 or x = 6, substituting y = 2 √ 3, a (6,2 √ 3), the center of the circle is set as D (D, 0), d = 6 - (2 √ 3) tan30 ° = 4, and the radius is set as R, R & sup2; = | Da | & sup2; = (6-4) & sup2; + (2 √ 3-0) & sup2; = 16



How much is 390 divided by 4? No remainder!
It can't have decimal 0 () ()) 0


97.5
The score is 97 (1 / 2), which is 97 and 1 / 2



In polar coordinates, the polar coordinates of the center of the circle ρ = 4 ρ sin θ are?


Should it be ρ = 4asin θ
Multiply both sides by ρ to get ρ ^ 2 = = 4A ρ sin θ,
Substituting x = ρ cos θ, y = ρ sin θ,
The results show that x ^ 2 + y ^ 2 = 4ay, and x ^ 2 + (y-2a) ^ 2 = (2a) ^ 2,
So its center coordinates are x = 0, y = 2A, so its center polar coordinates are (2a, π / 2)



1.y(y+1)(x²+1)+x(2y²+2y+1)
2.6x²-5xy-6y²-2xz-23yz-20z²
Using rational roots, we can find out:
3. X fourth power + 5x & sup2; + 9
4.x³+6x²+11x+6
Come on


Y (y + 1) (X & sup2; + 1) + X (2Y & sup2; + 2Y + 1) + 1 = y (y + 1) (x ^ 2 + 1) + 2x (y + 1) y + X + 1 = y (y + 1) (x + 1) ^ 2 + X + 1 = (x + 1) (XY ^ 2 + XY + y ^ 2 + y + 1) 2



The center of the ellipse is at the origin, and the focus is on the x-axis. The lines between a focus and the two ends of the minor axis are perpendicular to each other, and the distance from the focus to the nearest vertex on the major axis is smaller
Solving elliptic equation with distance from root 10 to root 3


According to the meaning of the title
b=c
And a-c = √ 10 - √ 3
Then a & # 178; = B & # 178; + C & # 178;
a²=2c²
a=√2c
Substituting
c(√2-1)=√10-√3
c=(√10-√3)/(√2-1)=(√10-√3)(√2+1)
I always think the numbers are a little strange
Maybe I did something wrong



3x^2-4x=9,-6x^2+8x-5=?
It's over today


-2*9-5=-23