2.65 + 2.52 △ 1.2-3.84

2.65 + 2.52 △ 1.2-3.84

The chord length of the straight line kx-y + 6 = 0 cut by the circle x2 + y2 = 25 is 8, and the value of K is obtained

The chord length of the straight line kx-y + 6 = 0 cut by circle x2 + y2 = 25 is 8, the distance between chord centers is 52 − 42 = 3, and the solution is k = ± 3

How much is infinity minus infinity?
Say infinity = infinity, the subtracted and the subtracted are equal, then it is zero
But infinity, minus more or infinity, the answer is infinity

It's too general for you to say that
This is not an ordinary function, but a generalized function
You should know: when X -- > 0 (the reason why we discuss the case of x = 0 is that infinity can take its reciprocal), SiN x is equivalent to X. they are equivalent to infinitesimal. In addition, there are some problems
We can't simply say who subtracts who is how much. I suggest you refer to Chapter 1 of higher mathematics, the 6th Edition Textbook of Tongji University

4x-1 / (x + 2) (x-1) = A / x + 2 + X / X-1, then a equals (the relationship between a and X,)
I want a specific process,
I only know 4x-1 = m (x-1) + X (x + 2) what to do next

(4x-1)/(x+2)(x-1)=A/(x+2)+x/(x-1)(4x-1)=[A/(x+2)+x/(x-1)]*(x+2)(x-1)(4x-1)=A(x-1)+x(x+2)A(x-1)=(4x-1)-x(x+2)A(x-1)=4x-1-x^2-2xA(x-1)=-x^2+2x-1A(x-1)=-(x-1)*(x-1)A=-(x-1) A=-x+1

Recursive equation calculation: 71 1 / 6 + 61 1 / 5 × 5 / 6 + 51 1 / 4 × 4 / 5 + 41 1 / 3 × 3 / 4 + 31 1 / 2 × 2 / 3

71 and 1 / 6 × 6 / 7 + 61 and 1 / 5 × 5 / 6 + 51 and 1 / 4 × 4 / 5 + 41 and 1 / 3 × 3 / 4 + 31 and 1 / 2 × 2 / 3
=（70+7/6）×6/7+（60+6/5）×5/6+（50+5/4）×4/5+（40+4/3）×3/4+（30+3/2）×2/3
=60+1+50+1+40+1+30+1+20+1
=205

As shown in the figure, the quadratic function y of Y with respect to X is y = - 33m (x + m) (x-3m). The vertex of the image is m. the x-axis of the image intersects at two points a and B, and the positive half axis of the y-axis intersects at point D. take ab as the diameter of the circle, and the center of the circle is c. the coordinates of the fixed point e are (- 3,0), connecting ed. (M > 0)
(1) Write out the coordinates of a, B and D;
(2) When m is on the line ed, the position relationship between the line and the circle is determined;
(3) When m changes, M is used to represent the area s of △ AED, and the diagram of the function image of s with respect to m is drawn in the given rectangular coordinate system

If a is on the left side of the x-axis, then a (- m, 0), B (3m, 0); if a is on the right side of the x-axis, then a (3m, 0), B (- m, 0) d (0,3m & # 178;)

It is known that a = 4322 × 1233, B = 4321 × 1234
A. a＜bB. a=bC. a＞b

A = 4322 × 1233 = (4321 + 1) × 1233 = 4321 × 1233 + 1233b = 4321 × 1234 = 4321 × (1233 + 1) = 4321 × 1233 + 43214321 × 1233 + 1233 < 4321 × 1233 + 4321

If the function y = AX2 + 3x + 1 has only one intersection with the X axis, then the value of a is______ ．

When the function is a first-order function, there is an intersection point between the function and the x-axis, where a = 0; when the function is a second-order function, there is an intersection point between the function and the x-axis. According to the properties of the second-order function, it can be obtained that: △ = 9-4a = 0, so a = 2.25, so the value of a is 0 or 2.25

The position of rational number A & # 160; &# 160; B & # 160; C on the number axis is shown in the figure:
       a      0     b              c
To judge positive and negative, use "or" to "fill in the blanks of 353535;3535; 160; 1, B-C & 35;35;35;35;####35;3535;3535353535\\3535; 1, b-c-c & \\\35;; \\\\35\\\\\\\\\\\\\\\\\\\\35; 160; 0 & # 160; &# 160; &# 160; 3. A + B & # 160; &# 160; &# 160; &# 160; 0 & # 160; &# 160; &# 160;
Simplification: |a-b | + |a-b | + |a + B | &# 160; &# 160;

1、<
2、<
3、<
Simplification = (- A + b) + (- a-b) + (- A + b) = - 3A + B

Given that the ratio of distance between point m and two fixed points o (0,0), a (3,0) is 2 / 1, the trajectory equation of point m is obtained

Let m (x, y), from the meaning of the title, we know that om = 2 am
According to the distance formula between two points: √ (x ^ 2 + y ^ 2) = 2 √ [(x-3) ^ 2 + y ^ 2]
The square of both sides is: (x ^ 2 + y ^ 2) = 4 [(x-3) ^ 2 + y ^ 2]
The result is: x ^ 2-8x + y ^ 2 + 12 = 0
The formula is: (x-4) ^ 2 + y ^ 2 = 4
The trajectory is a circle with point (4,0) as its center and 2 as its radius