2-1/6(x+5)=x-1/3(x-1) To the denominator solution equation, to the process, thank you!

2-1/6(x+5)=x-1/3(x-1) To the denominator solution equation, to the process, thank you!

Multiply both sides by six
12-(x+5)=6x-2(x-1)
12-x-5=6x-2x+2
-5x=-5
x=1

6 / 5 [x + 3] = 2 / 3 [X-1]

（6 / 5）（x + 3）= （2 / 3）（x - 1）
（6 / 5）x + 18 / 5 = （2 / 3）x - 2 / 3
（6 / 5）x - （2 / 3）x = - 18 / 5 - 2 / 3
（8 / 15）x = - 64 / 3
x = - 40

If a × two fifths = B △ two fifths, then the size of a and B is

a>b

General division: (1) 3 of X and 6 of 1-x and the sum of squares of x-x + 5 (2) (X-Y) (X-2) 3Y (X-Y) (2-x) 3xy

Solution (1): the simplest common denominator is the square of X (x-1) x 3 = 3 / x = 3 (x-1) / [x (x-1)] 1-x 6 = 6 / (1-x) = - 6 / (x-1) = - 6x / [x (x-1)] x-x + 5 = (x + 5) / (X & # 178; - x) = (x + 5) / [x (x-1)] (2): the simplest common denominator is the square of (X-Y) (X-2) (X-Y) (X-2) 3Y = 3Y & # 178; / [(x

1+2-3+4-5+6-7+^+98-99+100

1+2-3+4-5+6-7+.+98-99+100
=1+(2-3)+(4-5)+(6-7)+.+(98-99)+100
=1-1-1-1-.-1+100
=1 + 100-1-1-1 -. - 1, a total of 100 items, in addition to the first and the last, there are 98 items, with two as a group, a total of 98 / 2 = 49 groups
=101-49
=52

It is known that the product of three rational numbers A.B.C is negative and their sum is positive. When x = | a | / A + | B | / B + | C | / C, we try to find the square of 2012 of 2010x
-The value of 2012x + 2013

a. If the product of B.C is negative, then there are odd negative numbers in a.b.c. there are two possibilities: one negative number, two positive numbers or three negative numbers
If their sum is positive, it can't be all negative, so it's two positive numbers and one negative number. Suppose a, B are positive and C is negative
Then the absolute values of a, B and C are a, B and - C respectively, so x = | a | / A + | B | / B + | C | / C = 1 + 1 + (- 1) = 1

There is only one value that satisfies the equation AX square - ax + 3x + 1 = 0 about X, then a = answer and specific method!

The 1900 is for you
Ax ^ 2-ax + 3x + 1 = 0 if there is only one root, then the discriminant = 0, so there is:
(-a+3)^2-4a*1=0
a^2-6a+9-4a=0
a^2-10a+9=0
(a-9)(a-1)=0
So a = 9 or a = 1

Two tenths = a fraction, fifteen twentieth = a quarter, nine fourths = a few eighths
6 / 7 = 14 / 7, 4 / 7 = 12 / 72, 8 / 7 = 1 / 7
9 / 12 = 31 / 3 = 9 / 24 / 18 = 3 / 12
Judgment: to correct, write down the corrected sentences
1 is less than all false scores ()
Divide six kilos of sugar into seven parts. Each part is one seventh of a kilogram
The three good students in class 53 account for one ninth of the total number of students in the class. They regard the total number of students in the class as a whole
Sixteen out of seven is larger than two-thirds
The score equal to six out of seven is only twelve out of fourteen
choice
The numerator of a fraction is multiplied by five, and the denominator remains unchanged
1, down to a fifth of the original
2. Expand to one fifth of the original
3, unchanged
Fractional formula calculation
Who can do it fast?
Xiao Ming: I did eight calculation problems in five minutes
Lan Lan: I did six math problems in four minutes

2 / 10 = (5) 1 / 20 15 = 4 / 4 (3) 24 / 9 = 8 / 8 (3) 7 / 6 = 14 / 12 7 / 4 = (21) 12 / 72 8 = 9 / 9

LIM (x + sin2x) / (2x SiNx) x tends to 0

lim(x→0)(x+sin2x)/(2x-sinx) (0/0)
=lim(x→0)(1+2cos2x)/(2-cosx)
=(1+2)/(2-1)
=3

If the expansion of polynomial (MX + 4) multiplied by (2-3x) does not contain x term, then what is m equal to?

(MX + 4) times (2-3x)
=-3mx²+8+(2m-12)x
∵ expanded without x items
∴2m-12=0
∴2m=12
∴m=6