|x-5|/2-1=3

|x-5|/2-1=3


That is | X-5 | / 2 = 4
|x-5|=8
x-5=-8,x-5=8
So x = - 3, x = 13



1/2{1/3[1/4(x+1/5-1)-6]+x}=1
In parentheses, it's five times x + 1 and - 1


1/2{1/3[1/4(x+1/5-1)-6]+x}=1
1/3{1/4[(x+1)/5-1]-6}+x=2
1/4[(x+1)/5-1]-6+3x=6
1/4[(x+1)/5-1]=12-3x
(x+1)/5-1=48-12x
(x+1)/5=49-12x
x+1=245-60x
61x=244



1/x+2-1/x+3=1/x+5-1/x+6


Answer: 1 / (x + 2) - 1 / (x + 3) = 1 / (x + 5) - 1 / (x + 6) general score: [(x + 3) - (x + 2)] / [(x + 2) (x + 3)] = [(x + 6) - (x + 5)] / [(x + 5) (x + 6)] 1 / (x ^ 2 + 5x + 6) = 1 / (x ^ 2 + 11x + 30) so: x ^ 2 + 5x + 6 = x ^ 2 + 11x + 3011x-5x = 6-306x = - 24x = - 4, x = - 4 is the root of the original fraction equation



How many hours is an hour


One hour, one hour



The square of a number is 121. What is the number?


±11



The known function f (x) = 2A + 1 / A-1 / A ^ 2x, constant a > 0
(1) Let Mn > 0, it is proved that the function f (x) increases monotonically on [M, n];
(2) Let 0 < m < N and the domain and range of F (x) be [M, n]


(1) ∵ f (x) = (2a + 1) / A-1 / A & sup2; X = (- 1 / A & sup2;) / x + (2a + 1) / A and a ∵ 0 ∵ 1 / A & sup2; > 0 ∵ 1 / A & sup2; < 0 (this problem is similar to the inverse proportion function y = K / x, K ≠ 0 is equivalent to k = - 1 / A & sup2;) ∵ the inverse proportion function y = (- 1 / A & sup2;) / X in [M



On the drawing with a scale of 1:2000, we measured a school's rectangular playground, which is 5cm long and 2cm wide. What's the actual area of the playground?
(using the equation,


Length 5 × 2000 = 10000cm, width 2 × 2000 = 4000cm
Actual area: 10000 × 4000 = 40000000 square centimeters = 4000 square meters



What is (- 1024) + [(- 1024) + 2] + (- 1024) × 0.5?


-3588



Piecewise point derivative of piecewise function
First of all, it has been determined to be continuous. The teacher said that we should use the definition to find the derivative. Does it mean that we can use the definition to find the left derivative and the right derivative respectively? Is it equal to the derivative of the point? And does the definition method mean that we can strictly use the Y difference / X difference, or can we use the formula separately?


Generally, the derivative of a piecewise function can be obtained directly in each segment,
For segmentation points, we only need to judge whether the left and right derivatives are equal according to the definition,
Only left and right are equal (and continuous) can be derived



Simple calculation of 9999 times 2222 plus 3333 times 3334
No*


9999×2222+3333×3334
=3333×6666+3333×3334
=3333×(6666+3334)
=3333×10000
=33330000