Fifth grade math exercises Fill in the blanks: 1. The volume of a bottle of mineral water is about 500 () the volume of a car's fuel tank is about 120 () The volume of a small medicine bottle is about 10 () and the floor area of a classroom is about 70 () 2. To make a cuboid frame 15 cm long, 10 cm wide and 8 cm high, you need at least iron wire (). To paste a layer of paper outside the frame, you need at least () paper. The volume of this carton is () 3. The cuboid has a volume of 120m, a length of 5m, a width of 4m and a height of () 4. The edge length, surface area and volume of the cube increase by 2 times and () times respectively 5. Use a small cube with edge length of 1 decimeter to make a cuboid with edge length of 5 decimeter, width of 4 decimeter and height of 2 decimeter 6. The surface area of a cube is 24 square decimeters, and its volume is () cubic decimeters 7. There is a certain liquid medicine 3 liters, to be sub packed into 2 ml each bottle, a total of () bottles can be sub packed 8. The sum of the edges of a cube is 96 decimeters, and the surface area of the cube is () 9. A cuboid tank, 6 decimeters long and 2 decimeters wide, is twice as high as wide. After loading 30 liters of oil, the height of the oil is () 10. Cut a cube with an edge length of 8 decimeters into two cuboids of the same size. The volume of each cuboid is (), and the surface area is () Judgment questions: 1. Two cuboids of equal volume have the same surface area 2. 500 ml is equal to 500 cubic decimeter 3. The length and volume of the cube are 3 and 9 times larger 4. Put two cubes together to form a cuboid with the same volume and surface area 5. It takes at least eight small cubes to make a big cube 6. If the bottom area of two cubes is equal, the volume is equal

Fifth grade math exercises Fill in the blanks: 1. The volume of a bottle of mineral water is about 500 () the volume of a car's fuel tank is about 120 () The volume of a small medicine bottle is about 10 () and the floor area of a classroom is about 70 () 2. To make a cuboid frame 15 cm long, 10 cm wide and 8 cm high, you need at least iron wire (). To paste a layer of paper outside the frame, you need at least () paper. The volume of this carton is () 3. The cuboid has a volume of 120m, a length of 5m, a width of 4m and a height of () 4. The edge length, surface area and volume of the cube increase by 2 times and () times respectively 5. Use a small cube with edge length of 1 decimeter to make a cuboid with edge length of 5 decimeter, width of 4 decimeter and height of 2 decimeter 6. The surface area of a cube is 24 square decimeters, and its volume is () cubic decimeters 7. There is a certain liquid medicine 3 liters, to be sub packed into 2 ml each bottle, a total of () bottles can be sub packed 8. The sum of the edges of a cube is 96 decimeters, and the surface area of the cube is () 9. A cuboid tank, 6 decimeters long and 2 decimeters wide, is twice as high as wide. After loading 30 liters of oil, the height of the oil is () 10. Cut a cube with an edge length of 8 decimeters into two cuboids of the same size. The volume of each cuboid is (), and the surface area is () Judgment questions: 1. Two cuboids of equal volume have the same surface area 2. 500 ml is equal to 500 cubic decimeter 3. The length and volume of the cube are 3 and 9 times larger 4. Put two cubes together to form a cuboid with the same volume and surface area 5. It takes at least eight small cubes to make a big cube 6. If the bottom area of two cubes is equal, the volume is equal

The volume of a bottle of mineral water is about 500 cm. The volume of a car fuel tank is about 120 L. the volume of a small medicine bottle is about 10 ml. the floor area of a classroom is about 70 M. to make a cuboid frame of 15 cm long, 10 cm wide and 8 cm high, at least iron wire is needed

(ask to use the formula learned in grade five)
1. Put 15kg gasoline into three equal weight barrels. It is known that the first barrel weighs 3.25kg and the second barrel weighs 3.25kg
75 kg. The third barrel contains half of the gasoline. How many kg are the first and second barrels?
2. When a butterfly flies 3 kilometers in 0.4 hours, the speed of a bee is 2.5 times that of a butterfly. How many kilometers per hour is the speed of a bee?

1 by the meaning of the title, the first two barrels contain the other half: 15 △ 2 = 7.5kg
Total weight of the first two barrels: 3.25 + 5.75 = 9kg
Description: weight of two barrels: 9-7.5 = 1.5kg, weight of one barrel: 1.5 △ 2 = 0.75kg
First barrel oil: 3.25-0.75 = 2.5kg
Second barrel oil: 5.75-0.75 = 5kg
2. Speed of bee: 3 △ 0.4 × 2.5 = 18.75 km
The speed of bees is 18.75 kilometers per hour

Fifth grade mathematics volume 2 extracurricular exercises, (formula to be solved)
1. If the side of a rectangular iron box with a square bottom is unfolded, a square with a side length of 40 cm can be obtained. If the iron box contains half a box of water, when the iron box is flat and the water surface is calm, the area of the surface in contact with the water can be calculated
2. From one end of the playground to the other end, the total length is 120 meters. From one end to the other, a small red flag is inserted every 3 meters (one at each end). Now we need to insert a small red flag every 5 meters. Question: how many small red flags can we not pull out?

(1) 10 * 10 + 40 * 20 = 900 square centimeter
(2) 120 / 15 + 1 = 9 faces

4 / 11 × 7 / 13 + 6 / 11 × 4 / 13 (simple calculation)

4/11×7/13+6/11×4/13
=4/13x7/11+4/13x6/11
=4/13x(7/11+6/11)
=4/13x13/11
=4/11
If you don't understand this question, you can ask,

Who has 200 fifth grade problem solving?
It's better to make it a little more difficult. Don't use fractions, integers or decimals,

3/7 × 49/9 - 4/3
8/9 × 15/36 + 1/27
12× 5/6 – 2/9 ×3
8× 5/4 + 1/4
6÷ 3/8 – 3/8 ÷6
4/7 × 5/9 + 3/7 × 5/9
5/2 -（ 3/2 + 4/5 ）
7/8 + （ 1/8 + 1/9 ）
9 × 5/6 + 5/6
3/4 × 8/9 - 1/3
7 × 5/49 + 3/14
6 ×（ 1/2 + 2/3 ）
8 × 4/5 + 8 × 11/5
31 × 5/6 – 5/6
9/7 - （ 2/7 – 10/21 ）
5/9 × 18 – 14 × 2/7
4/5 × 25/16 + 2/3 × 3/4
14 × 8/7 – 5/6 × 12/15
17/32 – 3/4 × 9/24
3 × 2/9 + 1/3
5/7 × 3/25 + 3/7
3/14 ×× 2/3 + 1/6
1/5 × 2/3 + 5/6
9/22 + 1/11 ÷ 1/2
5/3 × 11/5 + 4/3
45 × 2/3 + 1/3 × 15
7/19 + 12/19 × 5/6
1/4 + 3/4 ÷ 2/3
8/7 × 21/16 + 1/2
101 × 1/5 – 1/5 × 21
50＋160÷40 （58+370）÷（64-45）
120-144÷18+35
347+45×2-4160÷52
（58+37）÷（64-9×5）
95÷（64-45）
178-145÷5×6+42 420+580-64×21÷28
812-700÷（9+31×11） （136+64）×（65-345÷23） 85+14×（14+208÷26） （284+16）×（512-8208÷18）
120-36×4÷18+35 （58+37）÷（64-9×5） (6.8-6.8×0.55)÷8.5 0.12× 4.8÷0.12×4.8
（3.2×1.5+2.5）÷1.6 3.2×（1.5+2.5）÷1.6 6-1.6÷4 5.38+7.85-5.37 7.2÷0.8-1.2×5
6-1.19×3-0.43 6.5×（4.8-1.2×4） 0.68×1.9+0.32×1.9 10.15-10.75×0.4-5.7
5.8×（3.87-0.13）+4.2×3.74
32.52-（6+9.728÷3.2）×2.5
3/7 × 49/9 - 4/3
8/9 × 15/36 + 1/27
12× 5/6 – 2/9 ×3
8× 5/4 + 1/4
6÷ 3/8 – 3/8 ÷6
4/7 × 5/9 + 3/7 × 5/9
5/2 -（ 3/2 + 4/5 ）
7/8 + （ 1/8 + 1/9 ）
9 × 5/6 + 5/6
3/4 × 8/9 - 1/3
7 × 5/49 + 3/14
6 ×（ 1/2 + 2/3 ）
8 × 4/5 + 8 × 11/5
31 × 5/6 – 5/6
9/7 - （ 2/7 – 10/21 ）
5/9 × 18 – 14 × 2/7
4/5 × 25/16 + 2/3 × 3/4
14 × 8/7 – 5/6 × 12/15
17/32 – 3/4 × 9/24
3 × 2/9 + 1/3
5/7 × 3/25 + 3/7
3/14 ×× 2/3 + 1/6
1/5 × 2/3 + 5/6
9/22 + 1/11 ÷ 1/2
5/3 × 11/5 + 4/3
45 × 2/3 + 1/3 × 15
7/19 + 12/19 × 5/6
1/4 + 3/4 ÷ 2/3
8/7 × 21/16 + 1/2
30.8÷[14－(9.85＋1.07)]
[60－(9.5＋28.9)]÷0.18
2.881÷0.43－0.24×3.5
20×[(2.44－1.8)÷0.4＋0.15]
28-(3.4+1.25×2.4)
2.55×7.1+2.45×7.1
777×9+1111×3
0.8×〔15.5-(3.21+5.79)〕
（31.8+3.2×4）÷5
31.5×4÷(6+3)
0.64×25×7.8+2.2
2÷2.5+2.5÷2
194－64.8÷1.8×0.9
36.72÷4.25×9.9
5180－705×6
24÷2.4－2.5×0.8
(4121+2389)÷7
671×15-974
469×12+1492
405×(3213-3189)
3.416÷（0.016×35）
0.8×[(10－6.76)÷1.2]
19.4×6.1×2.3 5.67×0.2-0.62
18.1×0.92+3.93 0.0430.24+0.875
0.4×0.7×0.25 0.75×102 100-56.23
0.78+5.436+1 4.07×0.86+9.12.5
2. 8/9 × 15/36 + 1/27
3. 12× 5/6 – 2/9 ×3
4. 8× 5/4 + 1/4
5. 6÷ 3/8 – 3/8 ÷6
6. 4/7 × 5/9 + 3/7 × 5/9
7. 5/2 -（ 3/2 + 4/5 ）
8. 7/8 + （ 1/8 + 1/9 ）
9. 9 × 5/6 + 5/6
10. 3/4 × 8/9 - 1/3
11. 7 × 5/49 + 3/14
12. 6 ×（ 1/2 + 2/3 ）
13. 8 × 4/5 + 8 × 11/5
14. 31 × 5/6 – 5/6
15. 9/7 - （ 2/7 – 10/21 ）
16. 5/9 × 18 – 14 × 2/7
17. 4/5 × 25/16 + 2/3 × 3/4
18. 14 × 8/7 – 5/6 × 12/15
19. 17/32 – 3/4 × 9/24
20. 3 × 2/9 + 1/3
21. 5/7 × 3/25 + 3/7
22. 3/14 ×× 2/3 + 1/6
23. 1/5 × 2/3 + 5/6
24. 9/22 + 1/11 ÷ 1/2
25. 5/3 × 11/5 + 4/3
26. 45 × 2/3 + 1/3 × 15
27. 7/19 + 12/19 × 5/6
28. 1/4 + 3/4 ÷ 2/3
29. 8/7 × 21/16 + 1/2
30. 101 × 1/5 – 1/5 × 21
31.50＋160÷40 （58+370）÷（64-45）
32.120-144÷18+35
33.347+45×2-4160÷52
34（58+37）÷（64-9×5）
35.95÷（64-45）
36.178-145÷5×6+42 420+580-64×21÷28
37.812-700÷（9+31×11） （136+64）×（65-345÷23）
38.85+14×（14+208÷26）
39.（284+16）×（512-8208÷18）
40.120-36×4÷18+35
41.（58+37）÷（64-9×5）
42.(6.8-6.8×0.55)÷8.5
43.0.12× 4.8÷0.12×4.8
44.（3.2×1.5+2.5）÷1.6 （2）3.2×（1.5+2.5）÷1.6
(15.6+9.744/2.4)*0.5
2.881/0.43-3.5*0.24
13.5*0.68/8.5
43.6-7.6*4.1
(86.9+667.6)/50.3
(73.5+80.5)/(10+12)
(7.8*15+5.1*10+6*5)/(15+10+5)
12.53-1.35*2-9.3
0.8*(4-3.75)/0.1
6-1.3*(10-7.3)
1. 3/7 × 49/9 - 4/3
2. 8/9 × 15/36 + 1/27
3. 12× 5/6 – 2/9 ×3
4. 8× 5/4 + 1/4
5. 6÷ 3/8 – 3/8 ÷6
6. 4/7 × 5/9 + 3/7 × 5/9
7. 5/2 -（ 3/2 + 4/5 ）
8. 7/8 + （ 1/8 + 1/9 ）
9. 9 × 5/6 + 5/6
10. 3/4 × 8/9 - 1/3
11. 7 × 5/49 + 3/14
12. 6 ×（ 1/2 + 2/3 ）
13. 8 × 4/5 + 8 × 11/5
14. 31 × 5/6 – 5/6
15. 9/7 - （ 2/7 – 10/21 ）
16. 5/9 × 18 – 14 × 2/7
17. 4/5 × 25/16 + 2/3 × 3/4
18. 14 × 8/7 – 5/6 × 12/15
19. 17/32 – 3/4 × 9/24
20. 3 × 2/9 + 1/3
21. 5/7 × 3/25 + 3/7
22. 3/14 ×× 2/3 + 1/6
23. 1/5 × 2/3 + 5/6
24. 9/22 + 1/11 ÷ 1/2
25. 5/3 × 11/5 + 4/3
26. 45 × 2/3 + 1/3 × 15
27. 7/19 + 12/19 × 5/6
28. 1/4 + 3/4 ÷ 2/3
29. 8/7 × 21/16 + 1/2
30. 101 × 1/5 – 1/5 × 21
31.50＋160÷40 （58+370）÷（64-45）
32.120-144÷18+35
33.347+45×2-4160÷52
34（58+37）÷（64-9×5）
35.95÷（64-45）
36.178-145÷5×6+42 420+580-64×21÷28
37.812-700÷（9+31×11） （136+64）×（65-345÷23）
38.85+14×（14+208÷26）
39.（284+16）×（512-8208÷18）
40.120-36×4÷18+35
41.（58+37）÷（64-9×5）
42.(6.8-6.8×0.55)÷8.5
43.0.12× 4.8÷0.12×4.8
44.（3.2×1.5+2.5）÷1.6 （2）3.2×（1.5+2.5）÷1.6
45.6-1.6÷4= 5.38+7.85-5.37=
46.7.2÷0.8-1.2×5= 6-1.19×3-0.43=
47.6.5×（4.8-1.2×4）= 0.68×1.9+0.32×1.9
48.10.15-10.75×0.4-5.7
49.5.8×（3.87-0.13）+4.2×3.74
50.32.52-（6+9.728÷3.2）×2.5
51.3/7 × 49/9 - 4/3
52. 8/9 × 15/36 + 1/27
53. 12× 5/6 – 2/9 ×3
54. 8× 5/4 + 1/4
55. 6÷ 3/8 – 3/8 ÷6
56. 4/7 × 5/9 + 3/7 × 5/9
57. 5/2 -（ 3/2 + 4/5 ）
58. 7/8 + （ 1/8 + 1/9 ）
59. 9 × 5/6 + 5/6
60. 3/4 × 8/9 - 1/3
61. 7 × 5/49 + 3/14
62. 6 ×（ 1/2 + 2/3 ）
63. 8 × 4/5 + 8 × 11/5
64. 31 × 5/6 – 5/6
65. 9/7 - （ 2/7 – 10/21 ）
66. 5/9 × 18 – 14 × 2/7
67. 4/5 × 25/16 + 2/3 × 3/4
68. 14 × 8/7 – 5/6 × 12/15
69. 17/32 – 3/4 × 9/24
70. 3 × 2/9 + 1/3
71. 5/7 × 3/25 + 3/7
72. 3/14 ×× 2/3 + 1/6
73. 1/5 × 2/3 + 5/6
74. 9/22 + 1/11 ÷ 1/2
75. 5/3 × 11/5 + 4/3
76. 45 × 2/3 + 1/3 × 15
77. 7/19 + 12/19 × 5/6
78. 1/4 + 3/4 ÷ 2/3
79. 8/7 × 21/16 + 1/2
6/7＋2/15＋1/7＋ 13/15 19/21＋5/7－3/14
5/9－2/3＋5/9
8/9－（1/4－1/9）－ 3/4
The reward you offered is too little! It's cheaper this time!

Known: as shown in the figure, in rectangular ABCD, e is a point on DC, BF ⊥ AE is at point F, and BF = BC, prove: AE = ab

It is proved that the ∵ quadrilateral ABCD is a rectangle, ∵ BC = ad, DC ∥ AB, ∥ d = 90 °, ∵ DEA = ≌ fab, ∵ BF = BC, ∥ ad = BF. In △ ade and △ BFA, ≌ DEA = ≌ Fab ∥ d = ∥ bfaad = BF, ≌ AE = ba

If the equation MX ^ 2 - (1-m) x + M = 0 with X as the unknown has no real root, then the value range of M is?

If M = 0, then - x = 0
If M ≠ 0, it is a quadratic equation of one variable, and if there is no solution, the discriminant is less than 0
So [- (1-m)] ^ 2-4m ^ 20
m1/3
To sum up
m1/3

Application of surface area and volume of cylinder
1. If a cube with an edge length of 20 cm is cut into the largest cylinder, how many square centimeters is its surface area?
2. Use a rectangular wood with a square cross section to cut a cylinder with the largest bottom. The diameter of the bottom is 2 decimeters and the height is 4 decimeters. Question 1: what is the area to be cut? What is the surface area of the cylinder?
3. The volume of the cylinder is 50.24 cubic centimeter, the diameter of the bottom is 4cm, and how high is it?
If the answer is good, I will add 5 points```

1. If a cube with an edge length of 20 cm is cut into the largest cylinder, how many square centimeters is its surface area?
What is the base radius of the cylinder
20 △ 2 = 10 cm
What's the bottom area
10 × 10 × 3.14 = 314 square centimeters
What is the lateral area
20 × 3.14 × 20 = 1256 square centimeter
What is the surface area
314 × 2 + 1256 = 1884 square centimeter
2. Use a rectangular wood with a square cross section to cut a cylinder with the largest bottom. The diameter of the bottom is 2 decimeters and the height is 4 decimeters. Question 1: what is the area to be cut?
What is the volume of a cube
2 × 2 × 4 = 16 cubic decimeter
What is the volume of a cylinder
(2 △ 2) × (2 △ 2) × 3.14 × 4 = 12.56 cubic decimeter
What's the cut volume
16-12.56 = 3.44 cubic decimeter
Question 2: what is the surface area of this cylinder?
What's the bottom area
(2 △ 2) × (2 △ 2) × 3.14 = 3.14 square decimeter
What is the lateral area
2 × 3.14 × 4 = 25.12 square decimeter
What is the surface area
3.14 × 2 + 25.12 = 31.4 square decimeters
3. Cylindrical