The circular equation of circle x2 + Y2 + 4x-4y + 4 = 0 with respect to the symmetry of line L: X-Y + 2 = 0 is

The circular equation of circle x2 + Y2 + 4x-4y + 4 = 0 with respect to the symmetry of line L: X-Y + 2 = 0 is

By simplifying, we get the circle and the straight line y = x + 2 of (x + 2) 2 + (Y-2) 2 = 4
That is to find the point where the center of the circle (- 2,2) is symmetric to the line y = x + 2
And R = 4
Then the circular equation is x2 + y2 = 4

If the value of fraction 2x + 5 / x + 1 is an integer, then the value of integer x is

Is that so
（2X+5）/（X+1）
If it's a fraction like this
（2X+5）/（X+1）=2+3/（X+1）
Because fractions are integers
SO 2 + 3 / (x + 1) is an integer
That is, 3 / (x + 1) is an integer
So x + 1 is the factor of 3, which is - 3, - 1,1, + 3
Accordingly, X is - 4, - 2,0,2

Let X and y be real numbers, then the number of elements of the set composed of the values of X divided by | x | + y divided by | y | + XY divided by | XY |, is,?
The answer process,

Two {3, - 1}
All timing 3
- 1 when all negative
1 positive and 1 negative - 1

The difference between 1 and the reciprocal of a number is 56. The number is______ ．

A: the number is 6. So the answer is: 6

Solve the equations {X & # 178; - 2xy-8y & # 178; = 0 {(x + y) &# 178; - 3 (x + y) - 10 = 0

X & # 178; - 2xy-8y & # 178; = 0 can be transformed into (x-4y) (x + 2Y) = 0, the solution is x-4y = 0 or x + 2Y = 0 (x + y) & # 178; - 3 (x + y) - 10 = 0, the solution is ((x + y) - 5) ((x + y) + 2) = 0, the solution is x + y = 5 or x + y = - 2, so it can be combined into four equations, the solution is x = 4, y = 4 or x = - 1.6, y = - 0.4 or x =

In finding the zero interval of a function by dichotomy, what condition must a function satisfy? Is it necessary to define the monotonicity in the domain?

There are zeros and monotone functions

The parabola y = x ^ 2 + X-6 has an intersection with the X axis

The parabola y = x ^ 2 + X-6 has [2] intersections with the X axis
If you don't understand, I wish you a happy study!

If y = 2x2-3x + 4 is known, then y ＜ 0

The equation is as follows
Y=2X^2-3X+4
=2(X^2-3/2X+9/16)-9/8+4
=2(X-3/4)^2+23/8
The vertex coordinates are (3 / 4,23 / 8)
The axis of symmetry is x = 3 / 4
The minimum value of Y is 23 / 8. Because the Δ of the equation is less than 0, y cannot be less than 0
If the minimum of Y is 23 / 8, it can be determined that y is not less than 0

1）3(x-1)+5(3x-2)=8(x+7)+6
It's solving the equation
2）x-7.2+1.5=3
3）9.2-（3.6+x)=2.5
4) (x-4)/3=5.4
Come on. It's for the afternoon

A:
1）
3(x-1)+5(3x-2)=8(x+7)+6
3x-3+15x-10=8x+56+6
18x-13=8x+62
18x-8x=13+62
10x=75
x=7.5
2）x-7.2+1.5=3
x-5.7=3
x=3+5.7
x=8.7
3）9.2-（3.6+x)=2.5
9.2-3.6-x=2.5
5.6-x=2.5
x=5.6-2.5
x=3.1
4) (x-4)/3=5.4
x-4=5.4*3
x-4=16.2
x=4+16.2
x=20.2

Partition. X-2x ^ 2Y / x ^ 2y-2xy ^ 2

x-2x^2y/x^2y-2xy^2
=x(1-2xy)/[xy(x-2y)]
=(1-2xy)/[y(x-2y)]