Want to know: F (x) = x3-3x K, G (x) = (2kx-k) / (X22) 1 / 2 × 2 / 3 × 3 / 4 × 4 / 5 × We want to know: F (x) = x3-3x K, G (x) = (2kx-k) F (x) = loga (x ^ 2-ax) in (- 1 / 2,0) - 1 / 2

Want to know: F (x) = x3-3x K, G (x) = (2kx-k) / (X22) 1 / 2 × 2 / 3 × 3 / 4 × 4 / 5 × We want to know: F (x) = x3-3x K, G (x) = (2kx-k) F (x) = loga (x ^ 2-ax) in (- 1 / 2,0) - 1 / 2


An = 2A (n-1) (N 2) / [n (n 1)] (n ≥ 2, n ∈ n *) so 4 [X-2] 2 - 1 = 8, so (x) = x2-2x + 2 each term in the formula is a vector, the same below



If the length and width of a rectangle are increased by 4 meters, the area will be increased by 88 square meters?


144m
Let the length be x meters and the width be y meters
(X+4)(Y+4)=XY+88
X+Y=72
2 (x + y) = 144m



A cube + AB Cube - 2A cube B


a^3+ab^2-2a^2b
=a(a^2+b^2-2ab)
=a(a-b)^2



Indefinite integral f (x) DX = x ^ 2 + C, then indefinite integral XF (1-x ^ 2) DX to detailed process, urgent ah!


Sxf(1-x^2)dx 
=-1/2*Sf(1-x^2)d(1-x^2)
=-1/2*(1-x^2)^2+c



5、 Write words according to the meaning. (1) describe being very proud. (2) describe being depressed and very disappointed


Dejected and elated



The volume of the cone is 2.4 cubic decimeters, the bottom area is 2.4 square decimeters, and the height is______ Decimeter


4 × 3 / 2.4, = 7.2 / 2.4, = 3 (decimeter); answer: the height of the cone should be 3 decimeter



Fill in the operation symbol between the five digits 9, and the result is equal to 1


(9-9)/9+9/9



Arctan X / 1 + Y2, x = 1, y = 1 total differential


z=arctan[x/(1+y²)]
∂z/∂x={1/[1+x²/(1+y²)]}*[1/(1+y²)]
∂z/∂y={1/[1+x²/(1+y²)]}*[-x/(1+y²)²]*2y
So DZ = {1 / [1 + X & sup2; / (1 + Y & sup2;)]} * [1 / (1 + Y & sup2;)] DX + {1 / [1 + X & sup2; / (1 + Y & sup2;)]} * [- x / (1 + Y & sup2;) & sup2;] * 2ydy
x=1,y=1
dz=(2/5)dx-(2/5)dy



Given the function f (x) = x ^ 2-mx + N and f (1) = - 1, f (n) = m, find the value or expression of F (- 1), f [f (- 1)] and f [f (x)]


Because f (x) = x ^ 2-mx + N, f (1) = - 1, f (n) = M
So 1-m + n = - 1 N ^ 2-MN + n = n (n-m + 1) = m
The solution is m = 1, n = - 1
So f (x) = x ^ 2-x-1
So f (- 1) = (- 1) ^ 2 - (- 1) - 1 = 1
f[f(-1)]=f(1)=-1
f[f(x)]=f(x^2-x-1)=[x^2-x-1]^2-[x^2-x-1]-1=x^4-2x^3-2x^2+3x+1



4,7,9,20,36 how to calculate the result by addition, subtraction, multiplication and division


(9-7)*20+36-4=72