Given f (x) = x + 1 / x-3, find f (radical 2)

Given f (x) = x + 1 / x-3, find f (radical 2)

According to the theme
X + x-3 = radical 2
2x-3 = root 2
2X = root 2 + 3
Divide by two at the same time
X = radical 2 / 2 + 3 / 2

F (x) = 2 / 1 arccos 2 / x, find f (0), f (1), f (- radical 2), f (radical 3), f (- 2), f (radical 2), f (radical 2), f (radical 3), f (- 2), f (radical 2), f (radical 2), f (radical 2), f (radical 2), f (radical 2), f (radical 2), f (radical 2), f (radical 2,

∵f(x)=½arc cos½x,∴f(0)=½arc cos0=½·½π=¼π,f(1)=½arc cos½=½·(π/3)=π/6,f(-√2)=½arc cos(-½√2)=½·¾π=3π/8,f(√3)=½arc cos &...

If f (x-1 / x) = x2 + 1 / x2 + 1, then the value of F (radical 2-1) is

Let a = X-1 / X
a²=x²-2+1/x²
x²+1/x²=a+2
So f (a) = A & sup2; + 2 + 1
Then f (√ 2-1) = (√ 2-1) & sup2; + 3 = 6-2 √ 2

Given f (x-1 / x) = x2 + 1 / x2 + 1, find the value of F radical 2-1
Please participate widely
How come no one's 11111

Because f (x-1 / x) = x2 + 1 / x2 + 1 = (x-1 / x) squared-1
So f (x) = the square of X-1
F (radical 2-1) = 2-2, radical 2

If the parabola xsquare = 2PY, passing through the point m (0, - P / 2), tangent to the parabola, a and B are tangent points, then the length of AB is ()
Let a (x1,1 / 2p, X1 Square), find out the slope of a, and substitute it into the parabola. How can we give the tangent equation: y = kx-p / 2, substitute it, how can we get this?
Why does the answer say: after simultaneous equations, there is a real root? Isn't it two?

Y = kx-p / 2 is based on the equation obtained by setting the slope as K, then passing through two points a and m and bringing in M

3abc/bc+ca+ab-(a-1/a+b-1/b+c-1/c)÷(1/a+1/b+1/c)=______ .

Do BC + Ca + AB have brackets

PV = NRT, who can explain to me what it means?

P is the pressure, V is the volume, n is the amount of matter, t is the temperature, R is the constant, regardless

Calculate 9 / 5 [5 / 9 (1 / 2x-1 / 3) - 7] - 3 / 2x = 2 (3x-1.8) / 0.6 - (2x-0.8) / 0.4 = (1.2-x) / 0.3

Well, first of all, I'd like to ask if that place is 3 / (2x) or 1.5x. Mathematics should be more rigorous

The perimeter of a rectangle is 88cm. If the width is increased by 25%, the length is decreased by 1 / 2, and the perimeter is unchanged, then what is the area of the original rectangle?

From "width increases by 25%, length decreases by 1 / 2, perimeter remains unchanged", it can be seen that 25% of width = 1 / 2 of length, then width is twice of length; from perimeter 88, it can be seen that width is 88 / 3, length is 44 / 3, then original area is 3872 / 9

(3) A square frame is welded with 36 cm iron wire. How long is the square edge? If the surface of the frame is covered with paper, at least
(3) How long is the edge of a cube frame welded with 36 cm iron wire? If the surface of the frame is covered with paper, at least how many square centimeters of paper is needed?
(4) A square frame with an edge length of 8 cm is just welded with a piece of iron wire. If a cuboid frame with a length of 10 cm and a width of 7 cm is welded with this piece of iron wire, how high should it be?
(5) If each section is 15 decimeters long and its cross section is a rectangle, 1 decimeter long and 0.6 decimeter wide, at least how many square decimeters of iron sheet should be used to make a section of water pipe
(6) A swimming pool is 25 meters long, 10 meters wide and 2.4 meters deep. Tiles are laid around the swimming pool and at the bottom of the pool. If the side length of the tiles is 2 decimeter square, how many tiles are needed at least?
(7) How many square meters does a cuboid with a length of 4 decimeters, a width of 3 decimeters and a height of 2 decimeters occupy? What is its surface area

(3) Weld 36 cm wire into a cube frame
This cube is 36 / 12 = 3cm long
If the surface of the frame is covered with paper, it needs at least 6 × 3 × 3 = 54 square centimeters
(4) A square frame with an edge length of 8 cm is just welded with a piece of iron wire. If a cuboid frame with a length of 10 cm and a width of 7 cm is welded with this piece of iron wire, how high should it be?
Ridge length sum = 8 × 12 = 96cm
Cuboid edge length sum = 4 (length + width + height) = 4 (10 + 7 + height) = 96cm
Height = 24-17 = 7 cm
(5) If each section is 15 decimeters long, the cross section is a rectangle, 1 decimeter long and 0.6 decimeter wide
To make a section of water pipe, at least use iron sheet = 2 × (1 + 0.6) × 15 = 48 square decimeters
(6) A swimming pool, 25 meters long, 10 meters wide, 2.4 meters deep, in the pool around and pool bottom tile, if the side length of the tile is 2 decimeters square
Then at least this kind of ceramic tile is needed = [25 × 10 + 2 × (25 + 10) × 2.4] / (0.2 × 0.2) = 10450 pieces
(7) A cuboid 4 decimeters long, 3 decimeters wide and 2 decimeters high,
It covers an area of the largest = 0.4 × 0.3 = 0.12 square meters
Surface area = 2 (4 × 3 + 4 × 2 + 3 × 2) = 52 square decimeter = 0.52 square meter