When {1, e} satisfies Lagrange's theorem, the following function is a: 2 / 2-x B: ln (X-5) C: 3 / e ^ 2-ln ^ x D: 3 times the root of X-2

When {1, e} satisfies Lagrange's theorem, the following function is a: 2 / 2-x B: ln (X-5) C: 3 / e ^ 2-ln ^ x D: 3 times the root of X-2

1. Continuous on closed interval [a, b]
2. Derivable in the open interval (a, b)
A. There is breakpoint 2, discontinuous
B. X > = 5, not in domain
C. Yes
D. The domain is x > = 2, which is not satisfied

The function y = x (3-x under the root sign) satisfies the ξ of Lagrange mean value theorem on [0,3]

F（x)= x √(3-x)
F'(x)= √(3-x) [ 1- 1/ 2(3-x)]
Lagrange mean value theorem, f '(ξ) = (f (3) - f (0)) / (3-0)
That is √ (3 - ξ) [1 - 1 / 2 (3 - ξ)] = 0
The solution is ξ = 5 / 2

The radius of the big circle is equal to the diameter of the small circle, and the circumference ratio of the big circle to the small circle is______ What is the area ratio of the big circle to the small circle______ A.2：1   B.1：2   C.1：4   D.4：1．

Let the radius of the small circle be r, then the diameter of the small circle be 2R, and the radius of the large circle be 2R, then: (1) [2 × π× (2R)]: (2 π R), = 4 π R: 2 π R, = 2:1; (2) π (2R) 2: π R2, = 4 π R2: π R2, = 4:1; answer: the ratio of the circumference of the large circle to the circumference of the small circle is 2:1, and the ratio of the surface product of the large circle to the area of the small circle is 4:1

A times 5 / 6 = B times 2 / 3 = C times 4 / 5 = D times 3 / 8. What's ABCD
ABCD () > () > () > () fill in

In ABCD (d) > (b) > (c) > (a)

How to expand polynomials in MATLAB
How to expand P (s) = [(s ^ 2 + 1)] ^ 3 * (s + 5) ^ 2 * (s ^ 4 + 4 * s ^ 2 + 7)

Syms SPS = ((s ^ 2 + 1)) ^ 3 * (s + 5) ^ 2 * (s ^ 4 + 4 * s ^ 2 + 7) PS1 = expand (PS) result: PS = (s ^ 2 + 1) ^ 3 * (s + 5) ^ 2 * (s ^ 4 + 4 * s ^ 2 + 7) PS1 = 175 + 70 * s + 632 * s ^ 2 + 875 * s ^ 4 + 584 * s ^ 6 + 197 * s ^ 8 + 220 * s ^ 7 + 340 * s ^ 5 + 250 * s ^ 3 + S ^ 12 + 32 * s ^ 10 + 10 * s ^ 11 + 70 * s ^ 9

Given the chord length and arch height of an arc, how to calculate its radius? For example, 100cm, the arch height is 50cm, I want to calculate how to calculate the center point of its circle!

The calculation formula of arc length: l = 2 π R n / 360 ° = π R n / 180 ° (r = radius * n = absolute value of arc angle) here is the lack of N, unknown r!

How to use dislocation subtraction?
Please give me an example of dislocation subtraction. It's better to be more detailed. What's left in the end?
It is the dislocation subtraction of the sum of sequence

Is the dislocation subtraction of a sequence
Example: sum Sn = 3x + 5x square + 7x cubic + .. + (2n-1) times x to the power of n-1 (x is not equal to 0)
When x = 1, Sn = 1 + 3 + 5 + .. + (2n-1) = n square
When x is not equal to 1, Sn = Sn = 3x + 5x square + 7x third power + .. + (2n-1) times x to the power of n-1
So xsn = x + 3x square + 5x third power + 7x fourth power .. + (2n-1) times x to the nth power
So (1-x) Sn = 1 + 2x (1 + X + x square + X third power +. + X n-2 power) - (2n-1) times x n power
Simplify: SN = (2n-1) times x to get n + 1 power - (2n + 1) times n power of X + (1 + x) / (1-x) square

Solution of equation 4 * (x-1.5) = 10
To be exact, it's 4 times x minus 1.5, etc

4*(x-1.5)=10
4*（x-1.5)/4=10/4
(x-1.5)=2.5
x-1.5+1.5=2.5+1.5
x=4

Write about what happened between you and your parents, experience their love for you from little things, and express their true feelings

I always firmly believe that I am the happiest child in the world. Because, no matter where I go, there will always be a strong supporter behind me. They are my father and mother. My family is not very rich, but my father and mother have created a happy world for me. It is my paradise. The wall is covered with pink wallpaper

The simplest ratio of 8 / 25:2 / 3 is (), and the ratio is ()
That's the whole story

8:25:2:3 the simplest integer ratio = 12:25
The ratio of this ratio is 12 / 25