It needs 20 ways of simplification, 20 ways of rational number calculation and 20 ways of solving equations And I'm in grade one I forgot to ask for an answer. Don't risk an answer

I'm a freshman, too

A mathematical calculation problem: first simplify, then evaluate
((1 / X-Y) + (1 / x + y)) / (2Y / x ^ 2-2xy + y ^ 2), where x = 1 + root 2, y = 1-root 2

[1 / (X-Y) + 1 / (x + y)] / [2Y / (x ^ 2-2xy + y ^ 2)] = {[(x + y) + (X-Y)] / [(x + y) (X-Y)]} * (x ^ 2-2xy + y ^ 2) / 2Y = {2x / [(x + y) (X-Y)]} * {(X-Y) ^ 2 / 2Y} = (x / y) * (X-Y) / (x + y) x = 1 + radical 2, y = 1-radical 2, X-Y = 2 times radical 2, x + y = 2, substituting the original formula = [(1 + radical 2) / (1-radical

1-2,2-3,3-4,4-5. Write its general formula

What a strange topic
an=n-（n+1）=-1
It's a constant column

Allegorical sayings: Cart pull pancakes -- 9 times bracket X-Y square plus bracket x minus y square plus 4 times bracket x plus y square equal to how much

Basically, expand the polynomials and then merge them

What's 10 / 7 times 10 / 3?

100/21

(1-6 / 1 * 5 / 2) / 9 / 7 =? Formula? 12 / 11 / (9 / 1 + 12 / 5) =? 25 / (8 / 7-6 / 5) =?

(1-6 / 1 * 5 / 2) / 9 / 7
=(1-1 / 15) / 7 / 9
=17 / 15 / 7 / 9
=3/5
11 / 12 / (1 / 9 + 5 / 12)
=11 / 12 / 19 / 36
=33/19
25 / (7 / 8-5 / 6)
=1 / 25 / 24
=600

The solution of absolute value equation with one variable and one degree
|The answer given by X-1 | + | X-5 | = 4 is 1 ≤ x ≤ 5,

Just go to the absolute value
When X5, it is reduced to X-1 + X-5 = 2x-6 = 4, x = 5
In conclusion, the solution is 1 ≤ x ≤ 5

Three tenths of a ton is a few tenths of a kilogram

Three tenths of a ton is 300 kilograms
1000x3 / 10 = 300kg

What is the maximum value of the function f (x) = log3 (x ^ 2-x + 1) in the interval [- 1,3 / 4]

g(x)=x^2-x+1=(x-1/2)^2+3/4
The axis of symmetry is x = 1 / 2 with the opening upward
－1

It needs 20 ways of simplification, 20 ways of rational number calculation and 20 ways of solving equations And I'm in grade one I forgot to ask for an answer. Don't risk an answer