There are 50 problems in the operation of rational numbers, 50 problems in solving equations, and 30 problems in simplifying evaluation,

There are 50 problems in the operation of rational numbers, 50 problems in solving equations, and 30 problems in simplifying evaluation,

Best answer 3.3ab-4ab + 8ab-7ab + ab=______ ．
4．7x-(5x-5y)-y=______ ．
5．23a3bc2-15ab2c+8abc-24a3bc2-8abc=______ ．
6．-7x2+6x+13x2-4x-5x2=______ ．
7．2y+(-2y+5)-(3y+2)＝______ ．
11．(2x2-3xy+4y2)+(x2+2xy-3y2)=______ ．
12．2a-(3a-2b+2)+(3a-4b-1)=______ ．
13．-6x2-7x2+15x2-2x2＝______ ．
14．2x-(x+3y)-(-x-y)-(x-y)＝______ ．
16．2x+2y-[3x-2(x-y)]=______ ．
17．5-(1-x)-1-(x-1)=______ ．
18．( )+(4xy+7x2-y2)=10x2-xy．
19．(4xy2-2x2y)-( )=x3-2x2y+4xy2+y3．
21. Given a = x3-2x2 + x-4, B = 2x3-5x + 3, calculate a + B=______ ．
22. Given a = x3-2x2 + x-4, B = 2x3-5x + 3, calculate a-b=______ ．
23. If a = - 0.2, B = 0.5, the value of the algebraic formula - (| A2B | - | AB2 |) is______ ．
25. Subtract 3m4-m3-2m + 5 from a polynomial to get - 2m4-3m3-2m2-1, then the polynomial is equal to______ ．
26．-(2x2-y2)-[2y2-(x2+2xy)]=______ ．
27. If - 3a3b2 and 5ax-1by + 2 are of the same kind, then X=______ ,y=______ ．
28．(-y+6+3y4-y3)-(2y2-3y3+y4-7)＝______ ．
29. The result of simplifying the algebraic expression 4x2 - [7x2-5x-3 (1-2x + x2)] is______ ．
30．2a-b2+c-d3=2a+( )-d3=2a-d3-( )=c-( )．
31．3a-(2a-3b)+3(a-2b)-b=______ ．
32. The reduced algebraic formula X - [y-2x - (x + y)] is equal to______ ．
33．[5a2+( )a-7]+[( )a2-4a+( )]=a2+2a+1．
34．3x-[y-(2x+y)]=______ ．
35. Simplify | 1-x + y | - | X-Y | (where x ＜ 0, y ＞ 0) to be equal to______ ．
36. It is known that x ≤ y, x + Y - | X-Y|=______ ．
37. Given x < 0, y < 0, simplify | x + y | - | 5-x-y|=______ ．
38．4a2n-an-(3an-2a2n)＝______ ．
39. If a polynomial is added with - 3x2y + 2x2-3xy-4, then
2x2y+3xy2-x2+2xy,
Then the polynomial is______ ．
40．-5xm-xm-(-7xm)+(-3xm)=______ ．
41. When a = - 1, B = - 2,
[a-(b-c)]-[-b-(-c-a)]＝______ ．
43. When a = - 1, B = 1, C = - 1,
-[b-2(-5a)]-(-3b+5c)＝______ ．
44．-2(3x+z)-(-6x)+(-5y+3z)=______ ．
45．-5an-an+1-(-7an+1)+(-3an)＝______ ．
46．3a-(2a-4b-6c)+3(-2c+2b)=______ ．
48．9a2+[7a2-2a-(-a2+3a)]=______ ．
50. When 2y-x = 5, 5 (x-2y) 2-3 (- x + 2Y) - 100=______ ．
（2） Choice
[ ]
A．2；
B．-2；
C．-10；
D．-6．
52. In the following formulas, the result of - 7x-5x2 + 6x3 is []
A．3x-(5x2+6x3-10x)；
B．3x-(5x2+6x3+10x)；
C．3x-(5x2-6x3+10x)；
D．3x-(5x2-6x3-10x)．
53. Merge (- X-Y) + 3 (x + y) - 5 (x + y) to get []
A．(x-y)-2(x+y)；
B．-3(x+y)；
C．(-x-y)-2(x+y)；
D．3(x+y)．
54.2a - [3b-5a - (2a-7b)] is equal to []
A．-7a+10b；
B．5a+4b；
C．-a-4b；
D．9a-10b．
55. Minus - 3M equals 5m2-3m-5, the algebraic formula is []
A．5(m2-1)；
B．5m2-6m-5；
C．5(m2+1)；
D．-(5m2+6m-5)．
56. Combining the similar terms in the polynomial 2ab-9a2-5ab-4a2, it should be []
A．(9a2-4a2)+(-2ab-5ab)；
B．(9a2+4a2)-(2ab-5ab)；
C．(9a2-4a2)-(2ab+5ab)；
D．(9a2-4a2)+(2ab-5ab)．
57. When a = 2, B = 1, - A2B + 3ba2 - (- 2a2b) is equal to []
A．20；
B．24；
C．0；
D．16．
The right choice is []
A. There is no similar item;
B. (2) and (4) are similar terms;
C. (2) and (5) are similar terms;
D. (2) is not the same as (4)
59. If both a and B are quintic polynomials, then A-B must be []
A. Decadal polynomial;
B. Zero degree polynomial;
C. Polynomials of degree not higher than five;
D. A polynomial of degree less than five
60. - {[- (x + y)]} + {- [(x + y)]} equals []
A．0；
B．-2y；
C．x+y；
D．-2x-2y．
61. If a = 3x2-5x + 2, B = 3x2-5x + 6, then the size of a and B is the same
[ ]
A．A＞B；
B．A=B；
C．A＜B；
D. I'm not sure
62. When m = - 1, - 2M2 - [- 4m2 + (- m2)] is equal to []
A．-7；
B．3；
C．1；
D．2．
63. When m = 2, n = 1, the polynomial - M - [- (2m-3n)] + [- (- 3M) - 4N] is equal to []
A．1；
B．9；
C．3；
D．5．
[ ]
65. - 5an-an - (- 7An) + (- 3an) is equal to []
A．-16an；
B．-16；
C．-2an；
D．-2．
66. (5a-3b) - 3 (a2-2b) is equal to []
A．3a2+5a+3b；
B．2a2+3b；
C．2a3-b2；
D．-3a2+5a-5b．
67. X3-5x2-4x + 9 equals []
A．(x3-5x2)-(-4x+9)；
B．x3-5x2-(4x+9)；
C．-(-x3+5x2)-(4x-9)；
D．x3+9-(5x2-4x)．
[ ]
The result of 69.4x2y-5xy2 should be []
A．-x2y；
B．-1；
C．-x2y2；
D. None of the above answers is correct
（3） Simplification
70．(4x2-8x+5)-(x3+3x2-6x+2)．
72．(0.3x3-x2y+xy2-y3)-(-0.5x3-x2y+0.3xy2)．
73．-{2a2b-[3abc-(4ab2-a2b)]｝．
74．(5a2b+3a2b2-ab2)-(-2ab2+3a2b2+a2b)．
75．(x2-2y2-z2)-(-y2+3x2-z2)+(5x2-y2+2z2)．
76．(3a6-a4+2a5-4a3-1)-(2-a+a3-a5-a4)．
77．(4a-2b-c)-5a-[8b-2c-(a+b)]．
78．(2m-3n)-(3m-2n)+(5n+m)．
79．(3a2-4ab-5b2)-(2b2-5a2+2ab)-(-6ab)．
80．xy-(2xy-3z)+(3xy-4z)．
81．(-3x3+2x2-5x+1)-(5-6x-x2+x3)．
83．3x-(2x-4y-6x)+3(-2z+2y)．
84．(-x2+4+3x4-x3)-(x2+2x-x4-5)．
85. If a = 5a2-2ab + 3B2, B = - 2B2 + 3ab-a2, calculate a + B
86. Given a = 3a2-5a-12, B = 2A2 + 3a-4, find 2 (a-b)
87．2m-{-3n+[-4m-(3m-n)]｝．
88．5m2n+(-2m2n)+2mn2-(+m2n)．
89．4(x-y+z)-2(x+y-z)-3(-x-y-z)．
90．2(x2-2xy+y2-3)+(-x2+y2)-(x2+2xy+y2)．
92．2(a2-ab-b2)-3(4a-2b)+2(7a2-4ab+b2)．
94．4x-2(x-3)-3[x-3(4-2x)+8]．
（4） Simplify and evaluate the following expressions
97. Given a + B = 2, A-B = - 1, find the value of 3 (a + b) 2 (a-b) 2-5 (a + b) 2 × (a-b) 2
98. Given a = A2 + 2b2-3c2, B = - b2-2c2 + 3a2, C = C2 + 2a2-3b2, find (a-b) + C
99. Find (3x2y-2xy2) - (xy2-2x2y), where x = - 1, y = 2
101. Given | x + 1 | + (Y-2) 2 = 0, find the value of algebraic formula 5 (2x-y) - 3 (x-4y)
106. When p = A2 + 2Ab + B2, q = a2-2ab-b2, find p - [q-2p - (P-Q)]
107. Find the value of 2x2 - {- 3x + 5 + [4x2 - (3x2-x-1)]}, where x = - 3
110. When x = - 2, y = - 1, z = 3, find the value of 5xyz - {2x2y - [3xyz - (4xy2-x2y)]}
113. Given a = x3-5x2, B = x2-6x + 3, find A-3 (- 2b)
（5） Comprehensive exercises
115. Remove brackets: {- [- (a + b)]} - {- [- (a-b)]}
116. Remove brackets: [- (- x) - y] - [+ (- y) - (+ x)]
117. Given a = X3 + 6x-9, B = - x3-2x2 + 4x-6, calculate 2a-3b, and put the result in the brackets with a "-"
118. Calculate the following formula and put the result in the brackets with a "-" sign in front of it:
(-7y2)+(-4y)-(-y2)-(+5y)+(-8y2)+(+3y)．
119. Remove the brackets, merge the similar items, arrange the results according to the ascending power of X, and put the last three items in the brackets with a "-" sign
120. Without changing the value of the following formula, change the sign before each bracket into the opposite sign: (X3 + 3x2) - (3x2y-7xy) + (2y3-3y2)
121. The cubic term of polynomial 4x2y-2xy2 + 4xy + 6-x2y2 + x3-y2 is put in the brackets with a sign of "-" in front, the quadratic term is put in the brackets with a sign of "+", and the quartic term and constant term are put in the brackets with a sign of "-"
122. Remove the brackets of the following polynomials, merge the similar terms, and put all the items in the brackets with a "-" sign in front of them, and then calculate the value of 2x-2 [3x - (5x2-2x + 1)] - 4x2, where x = - 1
123. Merge similar items:
7x-1.3z-4.7-3.2x-y+2.1z+5-0.1y．
124. Merge the same kind: 5m2n + 5mn2 Mn + 3m2n-6mn2-8mn
126. Remove brackets and merge similar items:
(1)(m+1)-(-n+m)；
(2)4m-[5m-(2m-1)]．
127. Simplification: 2x2 - {- 3x - [4x2 - (3x2-x) + (x-x2)]}
128. Simplification: - (7x-y-2z) - {[4x - (X-Y-Z) - 3x + Z] - x}
129. Calculation: (+ 3a) + (- 5A) + (- 7a) + (- 31a) - (+ 4a) - (- 8a)
130. Simplification: a3 - (a2-a) + (a2-a + 1) - (1-a4 + a3)
131. Merge the similar terms of x2-8x + 2x3-13x2-2x-2x3 + 3, and then evaluate, where x = - 4
132. Fill in the appropriate items in brackets: [() - 9y + ()] + 2Y2 + 3y-4 = 11y2 - () + 13
133. Insert the appropriate item in brackets:
(-x+y+z)(x+y-z)=[y-( )][y+( )]．
134. Insert the appropriate item in brackets:
(3x2+xy-7y2)-( )=y2-2xy-x2．
135. Fill in the appropriate items in brackets:
(1)x2-xy+y-1=x2-( )；
(2)[( )+6x-7]-[4x2+( )-( )]=x2-2x+1．
136. Calculate the value of 4x2-3 [x + 4 (1-x) - x2] - 2 (4x2-1)
137. Simplification:
138. Vertical calculation
(-x+5+2x4-6x3)-(3x4+2x2-3x3-7)．
139. Given a = 11x3 + 8x2-6x + 2, B = 7x3-x2 + X + 3, find 2 (3a-2b)
140. Given a = x3-5x2, B = x3-11x + 6, C = 4x-3, find
(1)A-B-C；
(2)(A-B-C)-(A-B+C)．
141. It is known that a = 3x2-4x3, B = x3-5x2 + 2
(1)A+B；
(2)B-A．
142. Known x ＜ - 4, simplify | - x | + | - x + 4 | - | - x-4 |
146. Find the sum of the difference of two algebraic expressions - 1.56a + 3.2a3-0.47,2.27a3-0.02a2 + 4.03a + 0.53 and 6-0.15a + 3.24a2 + 5.07a3
-0.3,y=-0.2．
150. Given (x-3) 2 + | y + 1 | + Z2 = 0, find the value of x2-2xy-5x2 + 12xz + 3xy-z2-8xz-2x2

10 rational number calculation, 10 equation solution, 10 simplified evaluation

Go and find out for yourself
Simplify evaluation
solve equations
If you want to calculate rational numbers, just use a calculator to punch a few

The perimeter of a cube increases by 20%, and the area of the cube increases by ()%

Perimeter increases by 20%, that is, side length increases by 20%. 1 + 20% = 1.21.2 * 1.2 = 1.44
1.44-1 = 0.44 = 44% the cube area increased (44)%

Given that both a and B are acute angles and COS (a + b) = 12 / 13, cos (a + 2b) = 3 / 5, the value of cosa is obtained

1 / 3 x / 2 / 5 = 10
fast

1 / 3 x △ 2 / 5 = 10
1 / 3 x = 2 / 5 * 10
1 / 3 x = 4
X=4*3
X=12

Given that the equation 2x & # 178; + MX + 3 = 0 is a binomial equation, then M =?

Delta = b2-4ac = m2-24 ＞ 0, the value of M can only be calculated in the range, otherwise there should be some conditions

As shown in the figure, F1 and F2 are the focal points on the ellipse x2 / A2 + Y2 / B2 = 1 (a > b > 0), P is the point on the ellipse, Pf1 ⊥ ox axis, and OP is the vertex a of a major axis of the ellipse
Parallel to line ab of vertex B of minor axis
1. Find the eccentricity e of ellipse
2. If q is any point on the ellipse, it is proved that ∠ f1qf2 ≤ π / 2

1、
Let p be the point on the ellipse above the x-axis, and the F1 coordinate be (C, 0)
Pf1 ⊥ ox axis, then the coordinates of point P are (C, B & # / a)
kOP=b²/ac=kAB=b/a
Then B = C
a²=b²+c²=2c²
e=c/a=√2/2
2、
When the Q point is at the vertex of the minor axis, the maximum is ∠ f1qf2
F2Q=F1Q=b²+c²=2c²
F1F2=(2c²)=4c²
F2Q²+F1Q²=F1F2²
∠F1QF2=π/2
Therefore, f1qf2 ≤ π / 2

Simple calculation of 1 000 △ 1.25 × 25

1000÷（1.25×25）
=1000÷1.25÷25
=800÷25
=8×100÷25
=8×4
=32

Solve the following equation: (1) (x-3) square = 2x-6
(2) (4x-1) square-10 (4x-1) - 24 = 0

(x-3)²-2(x-3)=0
(x-3)(x-3-2)=0
(x-3)(x-5)=0
x=3,x=5
Let a = 4x-1
Then a & # 178; - 10-24 = (A-12) (a + 2) = 0
a=12,a=-2
4x-1=12,4x-1=-3
x=13/4,x=-1/2

It is known that the eccentricity of the ellipse G: x ^ 2 / A ^ 2 + y ^ 2 / b ^ 2 = 1 (a ＞ B ＞ 0) is √ 6 / 3, the distance from one end point of the minor axis to the right focus is √ 3, and the straight line L: KX + m intersects the ellipse at two different points a and B
(1) The equation of finding ellipse
(2) If the distance between the coordinate origin O and the line L is √ 3 / 2, the maximum AOB area of the triangle is obtained

(1) The distance from one end point of the minor axis to the right focus is √ 3, we can get: A ^ 2 = B ^ 2 + C ^ 2 = 3, a = √ 3 and E = C / a = √ 6 / 3, we can get: C = √ 2, B = 1, so the elliptic equation is: x ^ 2 / 3 + y ^ 2 = 1 (2) y = KX + m into the elliptic equation is x ^ 2 / 3 + y ^ 2 = 1, we can simplify it to: (3K ^ 2 + 1) x ^ 2 + 6kmx + 3M ^ 2-3 = 0