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Fractional addition and subtraction (2+3x)/(4-9x^2)-(1+3x)/(2-3x)-2/(3x-2)
(2+3x)/(4-9x^2)-(1+3x)/(2-3x)-2/(3x-2)
=(2+3x)/(2+3x)(2-3x)-(1+3x)/(2-3x)-2/(3x-2)
=1/(2-3x)-(1+3x)/(2-3x)+2/(2-3x)
=(1-1-3x+2)/(2-3x)
=1
Calculation of addition and subtraction of fractions with different denominators. 1 △ (x + 2) - 2 ± (X-2) x-2-x ^ 2 ^ (X-2) calculation (4 / A ^ 2-4) + (1 / 2-A)
1÷（x+2）-2÷（x-2）
x-2-x^2÷（x-2）
(4/a^2-4)+(1/2-a)
1÷（x+2）-2÷（x-2）
=[(x-2)-2(x+2)]÷[(x+2)(x-2)
=(-x-6)/(x²-4)
x-2-x^2÷（x-2）
=[(x-2)²-x²]÷(x-2)
=(-4x+4)/(x-2)
(4/a^2-4)+(1/2-a)
=[4-(a+2)]/(a²-4)
=(2-a)/(a+2)(a-2)
=-1/(a+2)
If each student is divided into 5 apples, there are 12 apples left; if each student is divided into 7 apples, one student is divided into less than 7 apples but more than 2 apples, there are [] apples in this batch and there are [] people in this dormitory
According to the meaning of the question, we get 5x + 12 = y, 2
Solution equation: 5x + 8 (20-x) = 136
5x+8(20-x)=136
5x + 160 - 8x = 136
-3x = -24
x = 8
It is known that the set M = {x | - 2 > = x | = a} is a nonempty set, and the set P = {Y / y = 2x + 3, X belongs to m}
The set t = {Z / z = X2, X belongs to m}. If t is the proper subset of P, then the value range of real number a is 0
To analyze
From m being nonempty, we get a > = - 2 and set P = {- 1
If the square of X - M + 4 is a complete square formula, then M=
x^2-m+4=(x±2)^2
So m = ± 4x
The domain of the function y = SiNx is___ ．
From the meaning of the question, we can get SiNx ≥ 0, 2K π + 0 ≤ x ≤ 2K π + π, K ∈ Z, so the definition domain of the function is [2K π, 2K π + π], K ∈ Z, so the answer is: [2K π, 2K π + π], K ∈ Z
Simplify the square of: (2a-4b) (4B + 2a) - 4 (a + b)
Original formula = square of 4A - square of 16b - 4 (square of a + square of 2Ab + square of B)
=The square of 4A - the square of 16b - the square of 4A - the square of 8ab-4b
=-The square of 20b-8ab
There is a "220V, 5A" electric energy meter, which can be connected with "220, 40W" electric lamps () a.25 b.27 c.28 d.30 as required
27
In this paper, we change f (x) and f (x) in Cauchy mean value theorem from closed interval to open interval,
No, if the function is meaningless at the breakpoint, the theorem cannot be used
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