Mr. Green will give us a lecture tomorrow

Mr. Green will give us a lecture tomorrow

Mr Green will give us a speech tomorrow.

What is Tan (Wu - a) equal to

Tan (Wu - a) is equal to - Tana
Odd variable even constant, positive and negative look at quadrant

The equation 2x ^ 2-3x-k = 0 has a real root in the range of [- 1,1]. Find the range of K

∵ 2x ^ 2-3x-k = 0 has real roots in the range of [- 1,1]
Ψ 2x ^ 2-3x = k has real roots in the range of [- 1,1]
Let y = 2x & sup2; - 3x
∵y=2[x²-3x/2+(3/4)²]-(9/8)
=2[x-(3/4)]²-(9/8)
∵x∈[-1,1]
When x = - 1, y is the maximum, y (max) = 5
When x = 3 / 4, y is the minimum, y (min) = - 9 / 8
The range of y = 2x & sup2; - 3x is [- 9 / 8,5]
If the equation 2x & sup2; - 3x = k has a solution, then the value range of K is
-9/8≤k≤5
∴k∈[-9/8,5]

Simple calculation 274 times 150 + 950 times 822 153 times 46 + 71 times 54 + 82 times 54 364 into 56 + 88 into 182 0.47 times 28 + 0.36 times 94

274×150+950×822=822×50+950×822=822×（50+950）=820×1000=820000153×46+71×54+82×54=153×46+（71+82）×54=153×46+153×54=153×（46+54）=153000.47×28+0.36×94=0.47×28+36×0.94=0.47×28+72×0.47...

Finding the limit of 1 / (1-x) - 1 / LNX when x approaches 1

lim(x→1)[ 1/(1-x) -1/lnx]
=lim(x→1)[ lnx-(1-x)]/[(1-x)lnx]
=lim(x→1) [lnx+x-1]' / [lnx-xlnx]'
=lim(x→1)[1/x+1]/[1/x-lnx-1]
=∞

(5 / 12-3 / 7) - (4 / 7-7 / 12) simple calculation

5/12-3/7-4/7+7/12
=5/12+7/12-(3/7+4/7)
=1-1
=0

1. Decomposition factor: B & # 178; - (a-b + C) &# 178; = the fourth power of Y-1 = to use the square difference formula, to use the process

b²-(a-b+c)²=
=（b-a+b-c）（b+a-b+c）
=（2b-a-c）（a+c）
The fourth power of Y-1=
=y^4-1²
=（y²-1）（y²+1）
=（y+1）（y-1）（y²+1）

7.2 divided by x = 21.6

7.2 ÷ x = 21.6
x = 7.2 ÷ 21.6
X = 1 / 3 (1 / 3)

If a (- 3, - 5) and B (5,1) are known, then the equation of the circle with the diameter of line AB is______ ．

It can be seen from the meaning that the midpoint of a and B is the center of the circle, so the center of the circle is: (− 3 + 52, − 5 + 12), that is, (1, - 2), the distance between AB is equal to the diameter = (− 3 − 5) 2 + (− 5 − 1) 2 = 10, the radius of the circle is 5, the equation of the circle is: (x-1) 2 + (y + 2) 2 = 25, so the answer is: (x-1) 2 + (y + 2) 2 = 25

21.5 minus three 1 / 2 difference divided by 3 / 5 quotient is how much to solve the equation: 2 / 3 + 5 / 6x = 3 / 4, x minus 3 / 5x = 24
Simple algorithm: 5 / 7 times 3 / 5 divided by 6 / 7, 5 / 8 divided by (2 / 3 divided by 2 / 5), 8 / 13 divided by 7 + 1 / 7 times 5 / 13, 48 times (5 / 6 + 7 / 8), 2 divided by [(1 + 2 / 5) times 3 / 7], (2 / 3 + 1 / 9) divided by (4 / 5 minus 2 / 3)

2 / 3 + 5 / 6x = 3 / 45 / 6x = 3 / 4-2 / 3x = (9 / 12-6 / 12) * 6 / 5x = 5 / 12 * 6 / 5x = 1 / 2x minus 3 / 5x = 242 / 5x = 24x = 24 * 5 / 2x = 605 / 7 multiplied by 3 / 5 divided by 6 / 7 = 3 / 7 * 7 / 6 = 1 / 25 / 8 divided by (2 / 3 divided by 2 / 5