① The vertex of the parabola is the origin of the coordinate_______ ② The vertex of the parabola is on the y-axis________ ③ Parabola The vertex coordinates of the parabola are (h, K), and the analytic expression is______ ⑤ The abscissa of the two intersection points of parabola and X-axis are respectively x 1 x 2___________ ⑥ If the parabola passes through three points in the coordinate plane, the analytic formula can be set as________ What should I fill in these blanks?

① The vertex of the parabola is the origin of the coordinate_______ ② The vertex of the parabola is on the y-axis________ ③ Parabola The vertex coordinates of the parabola are (h, K), and the analytic expression is______ ⑤ The abscissa of the two intersection points of parabola and X-axis are respectively x 1 x 2___________ ⑥ If the parabola passes through three points in the coordinate plane, the analytic formula can be set as________ What should I fill in these blanks?


① The vertex of the parabola is the origin of the coordinate___ y=ax²____ ② The vertex of the parabola is on the y-axis____ y=ax²+c____ ③ If the vertex of the parabola is on the x-axis, the analytic expression can be set as___ y=(x+m)²____ ④ The vertex coordinates of the parabola are (h, K)



Using zero point segmentation method to simplify: | 2x + 1 | + | x-3|


It is to judge the 0-point segment of 2x + 1 and x-3
That is: 2x + 1 = 0, x = - 1 / 2
x-3=0 x=3
1) When x > = 3, both 2x + 1 and x-3 are greater than or equal to 0. After simplification, 2x + 1 + x-3 = 3x-2
2) When x > = - 1 / 2 and X



Fraction reduction calculation
(1) Partition-24a ^ 2B ^ 3C ^ 2 / 16ab ^ 2C ^ 2 m ^ 2-2m / 4-m ^ 2
(2) Calculation (- 64a ^ 3b) / (- 24a ^ 2x)
(3) First simplify and then evaluate 2A ^ 2-2ab / A ^ 2-2ab + B ^ 2, where a = 1 / 2 and B = - 1 / 2
(4) Given x = 3Y, find 2x ^ 2-4xy / x ^ 2-4xy + 4Y ^ 2


(1) The original formula of - 3AB / 2 = m (m-2) / (M + 2) (2-m) = - M / (M + 2)
(2)8ab/3X
(3) The original formula = 2A (a-b) / (a-b) ^ 2 = 2A / (a-b) takes in the value and gets 1 / 1 = 1
(4) The original formula = 2x (x-2y) / (x-2y) ^ 2 = 2x / (x-2y) brings in = 6y / y = 6



Application of quadratic equation of one variable
1. There is a trapezoidal steel plate ABCD, ab ∥ CD, ∠ a = 90 °, ab = 6m, CD = 4m, ad = 2m. Now a rectangular iron plate aefg is cut out from the trapezoid so that e is on AB, f is on BC, and G is on ad. if the area of the rectangular iron plate is 5 m2, calculate EF on one side of the rectangle
2. There is an iron bar with a length of 10m. If it is bent into a rectangle with the largest area, what is the length and width of the rectangle?
Solving quadratic equation with one variable


1. The angle ABC is 45 degrees
So let EF be X
Then be = x, then AE = 6-x
X*(6-X)=5
The solution is x = 1, x = 5
2. Let the length be x and the width be 5-x
S=X(5-X)
=-(X-5/2)^2+25/4
So when x = 5 / 2, the area of the rectangle is the largest
At this time, the length and width are 5 / 2



Inequality XX + 3x + 3 / XX + 2x + 5


From XX + 2x + 5 we get (x + 1) 2 + 4 greater than 0, so we can directly get xx + 3x + 3



5 x minus 2 minus 10 x plus 3 minus 3 2x minus 5 plus 3 = 0


From X / 5-2-x / 10 + 3-2x / 3-5 + 3 = 0 = > x / 5-x / 10-2x / 3 = 1 = > 6x / 30-3x / 30-20x / 30 = 1 = > - 17x / 30 = 1 = > x = - 30 / 17



The determinant of coefficient of non-homogeneous linear equations is equal to zero, and there are several solutions


No solution or multiple solutions



If the function f (x) = a ^ / X / (a > 0, and a is not equal to 1) is greater than or equal to 1, then the relationship between F (- 4) and f (1) is? A.f (- 4) > F (1) B.F (- 4) = f (1
If the range of function f (x) = a ^ / X / (a > 0, and a is not equal to 1) is greater than or equal to 1, then the relationship between F (- 4) and f (1) is?
A.f(-4)>f(1)
B.f(-4)=f(1)
C.f(-4)


If the range of exponential function is ≥ 1, a is greater than 1, and the function increases at (0, positive infinity)
For any X1 > x2 > 0, f (x1) > F (x2) > 1
Since the original function f (- x) = f (x), the,
So f (- 4) = f (4) > F (1)
So a is right



The absolute value of minus 1 and 1 / 5 times (1 / 4 minus 1 / 3) divided by minus 1 / 4


-1.2 × (1 / 4 minus 1 / 3) × 1 / 4
Equal to - 1.2 × minus one twelfth × four
Equal to - 1.2 x minus one third
Equal to 0.4
The absolute value is also equal to 0.4



Addition subtraction elimination method for solving bivariate linear equation: 7x-4y = 4,5x-4y = - 4


7x-4y-5x+4y=4-(-4)
2x=8
x=4
y=6