My father is the assistant of the manager for many years

My father is the assistant of the manager for many years

My father has been the manager's right-hand man for many years
Exchange "years" and "Deli"

I played the song "where is spring" at home all night yesterday
Another is: the instructor said, "anyway, we'll cross the snow mountain together."

I played "where is spring" at home last night
Instructor said, no matter what, they also want to cross the snow mountain together

Through Robinson's edification, "Friday" has become his good helper
Come on, I'm in a hurry

To pass through or remove from

Let x > 3Y > 0, 2log3 (x-3y) = log3 (3x + y) + log3y, and find the value of X / y

2log3 (x-3y) = log3 (3x + y) + log3ylog3 (x-3y) ^ 2 = log3 [y (3x + y)] (x-3y) ^ 2 = y (3x + y) x ^ 2-6xy + 9y ^ 2 = 3xy + y ^ 2x ^ 2-9xy + 8y ^ 2 = 0 (X-Y) (x-8y) = 0x = y, x = 8yx > 3Y > 0, then x = y obviously does not hold, so x = 8yx / y = 8

If the length of one side of an isosceles triangle is 5cm and an external angle is 120 °, the perimeter of the triangle is ()
How the first day of junior high school is so difficult, dizzy, please give me an analysis process

The circumference is 15cm!
Because this isosceles triangle is actually an equilateral triangle. The sum of the three inner angles of the triangle is 180 ° and the two waists are equal. If 120 ° is the outer angle of the vertex, then the vertex angle is 60 ° and the two base angles are equal. If 120 ° is the outer angle of the foot, then the two base angles are also 60 ° and each angle is 60 ° and the three sides are equal, right~

The rated voltage of a small bulb is 8V, and the current passing through it is 0.4A when it normally emits light. Now connect the small bulb to a 12V power supply. How to connect a large resistance to make it emit light normally?

Series resistance has the function of voltage division. Because the bulb still lights normally, the current in the circuit is I = 0.4A, the voltage at both ends of the resistance is u = 12v-8v = 4V; ∵ I = ur, ∵ the resistance value of series resistance is r = UI = 4v0.4a = 10 Ω; a: a 10 Ω resistance should be connected in series

Let u = {2,3,5}, a = {a-5}, CUA = {5}, then the value of a is?
There's a wrong number on it
Let u = {2,3,5}, a = {a-5}, 2}, CUA = {5}, then the value of a is?

∵ a ∈ u and∵ CUA = {5},
∴A={2,3}
A = {a-5 |, 2},
∴|a-5|=3
If the absolute value is removed, then
(1) A-5 = 3, that is, a = 3 + 5 = 8
(2) - A + 5 = 3, that is - a = - 2, a = 2
I'm a freshman in senior high school. Haha, how are you~

Let C be the midpoint of AB and d be the point on CB. If ad = 6 and DB = 4, find the length of CD

AB=AD+DB=10
AC=0.5AB=5=BC
CD=BC-BD=5-4=1

It is proved that the product of two upper triangular matrices is still an upper triangular matrix

To tell you the truth, this kind of proof problem really needs you to prove by yourself. It's not very difficult, but you have to do it by yourself. Sometimes the problem seems simple, but after you write it out, you will find that it's not so difficult in our mind, so it's very important to do it by yourself!

Y = x & # 178; - 2x + 3 x belongs to the range of [0,3]

y=(x-1)²+2
Axis of symmetry x = 1
So x = 1, y = 2
x=3,y=6
Range [2,6]