Reading extracurricular books often can improve our knowledge and correct the wrong sentences
Reading extracurricular books often can improve our knowledge
We can improve our knowledge by reading extra-curricular books
We can increase our knowledge by reading extracurricular books
The perimeter of the rectangle is 240 meters, and the ratio of length to width is 5:3. How many square meters is the area of the rectangle?
5 + 3 = 8240 △ 2 = 120 (m) length: 120 × 58 = 75 (m) width: 120 × 38 = 45 (m) area: 75 × 45 = 3375 (M2). Answer: the area of this rectangle is 3375 m2
What is the octave of a plus the octave of B?
If the equation 2A = | AX-1 | (a > 0 and a ≠ 1) has two real roots, the value range of a is obtained
If the equation 2A = | AX-1 | (a > 0 and a ≠ 1) has two real roots, then the image of function f (x) = | AX-1 |, and the line y = 2A have two intersections. As shown in the figure, the combination of number and shape can get 0 < 2A < 1, and the solution can get 0 < a < 12, so the range of a is (0, 12)
Xinxin's tabletop is a circle with a radius of 5 decimeters. She wants to lay a tablecloth with a diameter 3 decimeters larger than the diameter of the table on the table. What's the area of the tablecloth?
2 times 5 + 3 = 13 (decimeter) 13 divided by 2 = 2 / 2 of 13 (decimeter) 13 / 2 square × 3.14 = 132.665 (square decimeter)
The volume of a cone is 32 cubic decimeters, its bottom area is 8 square decimeters, what's the height of the cone
32 / 1 / 3 / 8 = 12
Because V-cone = one-third sh, V divided by one-third s = H
Who's going to fill in the problem of operation symbols?
3333=1
6666=22
9999=333
Add appropriate operation symbols to the numbers on the left side of the equal sign to form the formula of 1, 22333. Who will have a try?
1、 3333 = 1, 14:
33/33=1,(3+3-3)/3=1,(3+3)/(3+3)=1,3+3/3-3=1,3-3+3/3=1,(3-3+3)/3=1,3-(3+3)/3=1
3*3/3/3=1,3/3+3-3=1,3/(3+3-3)=1,3/3-3+3=1,3/(3-3+3)=1,3/3*3/3=1,3/3/3*3=1
2、 6666 = 22, no solution
3、 9999 = 333, no solution
Derivation of Higher Mathematics: (LN (sin2x)) '
This is the derivative of a composite function
Let t = 2x
Let u = sin t
Let v = ln U
that
v'x = v'u * u't * t'x
= 1/u * cost * 2
= 1/(sin(2x)) * cos (2x ) * 2
It is known that the density of iron is 7.9x1000kg/m3. There is an iron ball with a mass of 1.59kg and a volume of 300 cubic centimeter
V Fe = m Fe / ρ Fe = 1.58kg / (7.9 × 10 ᦉ 179; kg / m ᦉ 179;) = 2 × 10 ᦉ 710; (- 4) m ᦉ 179; = 200cm ᦉ 179;
V iron < V, so the ball is hollow
V air = V-V iron = 300cm & # 179; - 200cm & # 179; = 100cm & # 179;