Through reading, the students broaden their horizons

Through reading, the students broaden their horizons

1. Reading broadens students' horizons
2. Through reading, students broaden their horizons
I recommend the first one

Through reading, the students broaden their horizons and correct the wrong sentences

Cause: the use of "Shi" leads to the lack of subject
Answer 1:
Through reading, students broaden their horizons
Answer 2:
Reading broadens students' horizons
Pro*^__ ^*If you are satisfied, please click Set as satisfied,

More reading can enrich and improve our knowledge accumulation

More reading can enrich our knowledge

In the sequence {an}, A1 = 1, an + 1 = 2an2 + an (& nbsp; n ∈ n *), then a2011 is equal to______ ．

∵ an + 1 = 2an2 + an (& nbsp; n ∈ n *), 2An + 1 + an + 1An = 2An ∵ 2An + 1 − 2An = 1 & nbsp;; sequence {2An} is an arithmetic sequence with 1 as tolerance, 2A1 = 2 ∵ 2An = 1 + n ∵ an = 21 + n ∵ a2011 = 11006, so the answer is 11006

The floor area of the room is 15.4 square meters. The floor is paved with 0.4 meter long square bricks. Is 100 such bricks enough? (no loss)
This is a math problem. If you get it right, I'll offer you a reward of 10
It's a formula. It's a unit!

The side length is 0.4m, and the area is 0.4 × 0.4 = 0.16m2
100 pieces is 0.16 × 100 = 16 square meters > 15.4 square meters, which is enough

The magnificent China is in full bloom with the flowers of more than fifty-six nationalities

Compare nation to flower

Calculation (3 / Sin & # 178; 20) - (1 / cos & # 178; 20) + 64sin & # 178; 20

Original form
=[3(cos20)^2-(sin20)^2]/(sin20)^2(cos20)^2+64(sin20)^2
=[(√3cos20+sin20)(√3cos20-sin20)]/(sin20cos20)^2+64(sin20)^2
=[2sin(60+20)*2sin(60-20)]/[(sin40)/2]^2+64(sin20)^2
=16sin80sin40/sin40*sin40+64(sin20)^2
=16sin80/sin40+64(sin20)^2
=32sin40cos40/sin40+64(sin20)^2
=32cos40+64(sin20)^2
=32[1-2(sin20)^2]+64(sin20)^2
=32

The length of three sides of a right triangle is 3cm, 4cm and 5cm respectively. The perimeter of the right triangle is () and the area is ()

Where there is a formula, area = bottom x height / 2, and = sum of three sides
Please accept

Solve several high school mathematics problems
The first question. As long as the answer
The line L passing through point (1,2) intersects with the positive half axis of X axis and the positive half axis of Y axis at two points a and B respectively. O is the coordinate origin. When the area of triangle AOB is the smallest, the equation of line L is?
The second question. Or as long as the answer
If the circle centered on the right focus of the ellipse A2 / x2 plus B2 / Y2 equal to 1 (a greater than b greater than o) passes through the origin O and intersects with the right directrix of the ellipse at two points a and B, and it is known that the triangle OAB is an equilateral triangle, then the eccentricity of the ellipse is?

First question
Let the equation of the straight line be Y-2 = K (x-1)

Find the differential 2 x 1, find the differential 4 x 1 / 2 or 2 x 1 / 2, never mind the sign

Is 1 / 2 * x to the - 1 power
So the derivative is to the - 1-1 power of 1 / 2 * (- 1) * X
=-(2x & # 178;) 1 / 2