Xiaogang is 3.64kg heavier than Xiaoming, and Xiaoli is 2.8kg lighter than Xiaoming. Who is heavier, Xiaogang and Xiaoli? How many kg? There should be steps,

Xiaogangzhong
Weight 3.64 + 2.8 = 6.44kg

Known: as shown in the figure, ∠ 2 + ∠ d = 180 ° and ∠ 1 = ∠ B, verification: ab ‖ EF

It is proved that ∵ 2 + ∵ d = 180 °, ∵ EF ∥ DC, ∵ 1 = ∵ B, ∵ ab ∥ DC, ∵ ab ∥ EF

As shown in the figure, in the quadrilateral ABCD, ∠ bad = ∠ BCD = 90 ° AB = ad, if the area of the quadrilateral ABCD is 24cm2, then the AC length is______ cm．

Extend CD to point E, make de = BC, connect AE, ∫ bad = ∠ BCD = 90 °, ∫ 2 + ∠ B = 180 °, ∫ 1 + ∠ 2 = 180 °, ∫ 2 + ∠ B = 180 °, ∫ 1 = ∠ B. in △ ABC and △ ade, ∫ ab = ad ∠ 1 = ∠ BDE = BC, ≌ ABC ≌ ade (SAS), ≌ ead = BAC, AC = AE, s △ AEC = s, quadrilateral ABCD ∫ bad = 90 °, ∫ EAC = 90 °, ∫ ace is an isosceles right triangle, ∫ The area of quadrilateral ABCD is 24cm2, ∧ 12ac2 = 24, the solution is AC = 43 or - 43, ∵ AC is a positive number, ∧ AC = 43

The odd number sequence is divided into groups according to (1.3), (5.7.9), (11.13), (15.17.19). 1) to make the sum of the first k items of the sequence exceed 1000 at first, which group is the K item in? (2) what are the sum of the numbers in group 19 and group 20

Every two items are recombined into a sequence, that is BN = (a2n-1, A2N)
b1=(1 3 5 7 9)
b2=(11 13 15 17 19)
.
Let cn be the sum of five numbers of BN, we can see that CN is the arithmetic sequence
C1 = 25 tolerance d = 50
Sn=nc1+n(n-1)d/2=25n+25(n²-n)>1000
The minimum value of N & sup2; > 40 n is 7
b7=(61 63 65 67 69)
S6=25*6+25(6*6-6)=900
So it's over 1000 by 63
a(2*7-1)=a13=(61 63)
Answer to the first question: the second number in the first 13
a19=a(2*10-1)
a20=a(2*10)
b10=(a19,a20)=(91 93 95 97 99)
So A19 = (91 93)
a20=(95 97 99)

Ask for English right and wrong questions!
Write T for true or F for false in the spae provided.
1.German shepherds are not as intelligent as Seeing Eye doge.
2.Blind people should go to special schools to learn how to train Seeing Eye dogs to help them.
3.On the bus ,the Seeing Eye dog forced a man to stand up and left his seat to the blind owner.
4.The dog pushed the people on each side of the seat with his nose in order to get more space.
5.People on the bus were not friendly and laughed at the dog and the blind man.

You should have a piece of film, or an article to prompt, right?
How else do I know if they laugh?

As shown in the figure, fold the square ABCD in half, and the crease is Mn. Fold vertex d to a point P on Mn, and the crease is CE. Fold vertex a to the same point on Mn, and the crease is BF. Please answer the following questions: (1) what is the relationship between line segments PC and Pb and the side length of the square? (2) What is the degree of CPB? (3) What other angles do you know? Please point it out

(1) According to the characteristics of folding transformation, we can know that the side length of line segments PC and Pb is equal to that of square; (2) ∵ PC = Pb = BC, ∵ CPB = 60 °; (3) from (2), we can know: ∵ DCP = ∵ ABP = ∵ PEF = ∵ PFE = 30 °, ∵ ped = ∵ AFP = 150 °

First simplify and then calculate the ratio of 1 / 4 to 1 / 5

Simplification before ratio
One in four to one in five
=（1/4）×20:(1/5)×20
=5:4;
=5/4;
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Who can give me 100 exercises of quadratic radical operation? My operation is too bad
Let's do some basic problems, polynomial, addition, subtraction, multiplication and division,
50 will do

12 under root plus 8 under root plus 9 under root plus 16 under root divided by 18 under root plus 225 under root plus 14 under root minus 22 under root minus 66 under root plus 12 under root plus 85 under root plus 45 under root plus 545 under root plus 25 under root plus 86 under root plus 8 under root plus 5 under root plus 44 under root plus 66 under root minus 748 under root plus 35 under root plus 212 under root 568 under root number multiplied by 4 under root number divided by 25 under root number subtracted by 5 under root number subtracted by 8 under root number subtracted by 12 under root number, How much is 18 under the root sign and 1 / 4 under the root sign

As shown in the figure, in rectangle ABCD, ab = 6cm, BC = 15cm, e and F are the midpoint of the edge, and the shadow area is calculated

Suppose that BD intersects AE and G, AF intersects dB and h, because be is parallel to AD and equal to 12 of AD, so BG: GD = be: ad = 1:2, then BG: BD = 1:3, the same method can be obtained: DH: BD = 1:3, so BG = DH = 13bd, so BG = GH = HD, so the area of triangle ABG and triangle AGH is equal, △ ABG area + △ Bge area = △ AGH area + △ Bge area, △ AGH surface The area of product + △ Bge = △ Abe = 12 × 6 × 152 = 452; because the height of DF side of △ DFH = 13 × BC = 5, the area of △ DFH = 12 × 3 × 5 = 152; that is, the area of shadow part = 452 + 152 = 30 (square centimeter). A: the area of shadow part is 30 square centimeter

If M is a positive real number and m-1m = 3, then M + 1m = 3___ ．

From m-1m = 3 square, we can get: M2 + 1m2-2 = 9, M2 + 1m2 + 2 = 13, that is, (M + 1m) 2 = 13, and M is a positive real number, so the answer is 13

Xiaogang is 3.64kg heavier than Xiaoming, and Xiaoli is 2.8kg lighter than Xiaoming. Who is heavier, Xiaogang and Xiaoli? How many kg? There should be steps,