Xiao Ming went to school from home. After walking at the speed of 50 meters per minute for two minutes, he found that he would be 8 minutes late if he walked at this speed Xiao Ming went to school from home. He walked at a speed of 50 meters per minute for two minutes. He found that he would be 8 minutes late if he walked at this speed. So he accelerated his pace and walked 10 meters more per minute. As a result, when he got to school, he had five minutes to go. What's the distance between Xiao Ming's home and school?

Xiao Ming went to school from home. After walking at the speed of 50 meters per minute for two minutes, he found that he would be 8 minutes late if he walked at this speed Xiao Ming went to school from home. He walked at a speed of 50 meters per minute for two minutes. He found that he would be 8 minutes late if he walked at this speed. So he accelerated his pace and walked 10 meters more per minute. As a result, when he got to school, he had five minutes to go. What's the distance between Xiao Ming's home and school?


Suppose Xiaoming takes X minutes from home to school at a speed of 50 meters
50*x=50*2 (50 10)*(x-2-8-5)
The result is: x = 80
So Xiaoming's home to school: 50 * 80 = 4000 meters



There are 15 questions in total, 8 points for each right question, 4 points for each wrong question, and 72 points for Xiao Ming. How many questions did he do right?


8x-4 (15-x) = 72



Divide a polynomial [(17x2-3x + 4) - (AX2 + BX + C)] by (5x + 6), the quotient is (2x + 1), and the remainder is 0?


A polynomial [(17x2-3x + 4) - (AX2 + BX + C)] is divided by (5x + 6), and the quotient is (2x + 1), and the remainder is 0. Find ABC =? (5x + 6) (2x + 1) = 10x ^ 2 + 17x + 6 (17x2-3x + 4) - (10x ^ 2 + 17x + 6) = 7x ^ 2-20x-2, a = 7, B = - 20, C = - 2abc = 7 * (- 20) * (- 2) = 280



A simple algorithm of 72 * 53 + 41 * 24


72*53+41*24
=24*3*53+41*24
=(159+41)*24
=200*24
=4800



What are the points on the curve X & # 178; + xy-y & # 178; + 1 = 0


(0,1), (0, - 1) etc



(Mathematics of senior one) given that the solution set of inequality ax + b > 0 is (- ∞, 3), find the solution set of inequality (AX + b) / X ≤ 0


The solution set of (AX + b) / X ≤ 0 is the difference between X and (AX + b)
When ax + b > 0, X is needed



Vertical calculation of 124 times 17


1 2 4
× 1 7
————
8 6 8
1 2 4
————
2 1 0 8



lim(x→-∞)e^xsinx


e^xsin(x),
When x tends to negative infinity, e ^ x tends to e ^ (negative infinity) = 1 / e ^ (negative infinity). Because the denominator tends to infinity, the fractional value tends to 0;
At the same time, sin (x) oscillates between - 1 and 1. There is no limit, but it is a finite value;
How much is 0 times a finite value?
Obviously 0



In the quadratic equation 4x + 3Y = 7, if x and y are opposite numbers, then x = [], y = []


x=7,y=-7



1+12+123+1234… +What's 123456789?


137174205