If 4x ^ 2 + X + m is a complete square, then M= I heard that there are many answers I only got 1 / 16 I'll do it I forgot it at the end of the term How did you figure it out on the third floor.

answer:
m=1/16
m=-x
m=x+1/4
m=-3x²+x+1
m=x^4-x+4
There are a lot of things that are not listed one by one

If the length of a square is reduced by 5cm and the area is reduced by 20cm, if the width is increased by 3cm and the area is increased by 30cm, what is the area of the original rectangle?

Let the original rectangle be a in width and B in length
The equations can be obtained from the two known conditions in the title
ab-a(b-5)=20
(a+3)b-ab=30
(the above two equations can be reduced to linear equations with one variable)
A = 4; b = 10
Original rectangle area = AB = 40 square centimeter

In the same plane rectangular coordinate system, if the intersection of the line y = 3x-1 and the line y = x-k is in the fourth quadrant, then the value range of K is ()
A. K ＜ 13b. 13 ＜ K ＜ 1C. K ＞ 1D. K ＞ 1 or K ＜ 13

The solution of the system of equations y = 3x − 1y = x − k about X and Y is: x = 1 − k2y = 1 − 3k2 ∵ the intersection point is in the fourth quadrant ∵ the system of inequalities 1 − K2 > 01 − 3k2 < 0 is obtained; the solution is 13 ∵ K < 1, so B is selected

Let f'x and f'y of the partial derivative of the function of two variables in a neighborhood U (P0) of point P0 be bounded, and prove that f is continuous in U (P0)

Estimate with differential mean value theorem of single variable
|f(x,y)－f(x0,y0)|

If the probability of employee a participating in the Expo is 2 / 3, that of employee B is 2 / 3, that of employee C is 1 / 2, and that of employee D is 1 / 2, there are exactly 2 out of these 4 people participating in the Expo

A. 2 / 3 * 2 / 3 * 1 / 2 * 1 / 2 = 1 / 9
B. A or B to, C or D to (a total of 4 cases): 1 / 3 * 2 / 3 * 1 / 2 * 1 / 2 = 1 / 18
C. 1 / 3 * 1 / 3 * 1 / 2 * 1 / 2 = 1 / 36
So the probability of two people going is 1 / 9 + 1 / 18 * 4 + 1 / 36 = 13 / 36

The range problem of quadratic function
Y=X｛2｝—2X+2
2 is the square of X

Formula = (x-1) ^ 2 + 1 (x-1) ^ 2 > 0 (x-1) ^ 2 + 1 > 1 range [1, + infinity]

It is known that parabola y ^ 2 = 4x and ellipse x ^ 2 / 8 + y ^ 2 / M = 1 have common focus
1, find the value of M
2. There is a moving point P on the parabola. When the distance AP between the moving point P and the fixed point a (3,0) is the smallest, the coordinates of P and the minimum value of PA are obtained

M = 8 has a solution
Let P (x, y) two-point distance formula [(x-3) ^ 2 + y ^ 2] ^ 2 = | PA |, the parabolic equation is brought in, and the equation (x-3) ^ 2 + 4x under the root sign is obtained, then the minimum value of this equation is obtained in the case of x > = 0

What is the factorization of (1-a2) (1-b2) - 4AB

(1-a²)(1-b²)-4ab
=1-a²-b²+a²b²-4ab
=(1-2ab+a²b²)-(a²+b²+2ab)
=(1-ab)²-(a+b)²
=[(1-ab)+(a+b)][(1-ab)-(a+b)]
=(1+a+b-ab)(1-a-b-ab)

As shown in the figure, it is known that the vertical bisectors of AB and AC on both sides of △ ABC intersect BC at D and e respectively. If the length of BC is 8cm, the perimeter of △ ade is______ ．

The vertical bisectors of AB and AC on both sides of ∵ ABC intersect BC at D and e respectively, ∵ ad = BD, AE = CE, ∵ side BC is 8cm long, and the perimeter of ∵ ade is: AD + de + AE = BD + de + CE = BC = 8cm

How high was Yizhang in ancient times?

One foot is about 500 meters. One foot is ten feet. Now one meter is equal to 100cm. In different periods of ancient times, one foot is 16.95cm in length. According to this scale, a person is about one foot tall, so he is called "husband". In Zhou Dynasty, one foot is 23.1cm in height. In Qin Dynasty, one foot is 23.1cm in length. In Han Dynasty, one foot is big

If 4x ^ 2 + X + m is a complete square, then M= I heard that there are many answers I only got 1 / 16 I'll do it I forgot it at the end of the term How did you figure it out on the third floor.