If x, I, J and K are all int type variables, then the value of X after calculating the expression x = (I = 4, j = 16, k = 32) is___ ?

If x, I, J and K are all int type variables, then the value of X after calculating the expression x = (I = 4, j = 16, k = 32) is___ ?

As long as you remember that the value of the comma expression is the result of the last sentence, and the last formula k is equal to 32 after assignment, then this sentence is equivalent to I = 4; J = 16; k = 32; X = k; so x is finally assigned to 32

Please write a brief history story of civilization and etiquette you collected
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Zeng zibixi "Zeng zibixi" comes from the book of filial piety, which is a very famous story. Zeng Zi is a disciple of Confucius. Once he sat beside him, Confucius asked him: "in the past, the king of sages had the supreme virtue and the subtle theory, which was used to teach the people under heaven, so that people could live in harmony, and there was no dissatisfaction between the king and his subordinates, Do you know what they are? "After listening, Zeng Zi understood that the teacher Confucius wanted to teach him the most profound principles, so he immediately stood up from the mat he was sitting on, went outside the mat, and replied respectfully," I'm not smart enough, where can I know? Please teach me these principles. "Here," avoiding the mat "is a very polite behavior, When Zeng Zi heard that the teacher was going to teach him, he stood up and went to the mat to consult the teacher, in order to show his respect for the teacher

Let a = 1 + 2 * x to the fourth power, B = 2 * x to the third power + X to the square, X be a real number, and find the size relation of A.B

What is the first proof
(1+2x^4)-(2x³+x²)
=1-x²-2x³+2x^4
=(1-x)(1+x)+2x³(x-1)
=(x-1)(2x³-x-1)
=(x-1)[(x³-x)+(x³-1)]
=(x-1)[x(x-1)(x+1)+(x-1)(x²+x+1)]
=(x-1)²(x²+x+x²+x+1)
=(x-1)²(2x²+2x+1/2+1/2)
=(x-1)²[2(x+1/2)²+1/2]
Bracket greater than 0
(x-1)²>=0
So 1 + 2x ^ 4 > = 2x & sup3; + X & sup2;

Solve the equation x-x * 1 / 4 + (120 + x) + X * 1 / 4 = 120
The experimental middle school plans to buy 120 football and basketball. Later, due to the court problem, it was necessary to replace 25% of the number of football with basketball. In this way, the ratio of the number of football and basketball purchased was 1: what was the number of football originally planned to buy? How many are there in basketball?

X + 120 + x-x * 1 / 4 + X * 1 / 4 = 1202x + 120 = 1202x = 0x = 0 let's suppose that the original football is x, then basketball is 120-x (1-1 / 4), then basketball is 120-x (1-1 / 4) basketball is three times of football, so 120-x (1-1 / 4) = 3x (1-1 / 4) 120 - (3 / 4) x = (9 / 4) x (9 / 4 + 3 / 4) x = 1203x = 40120-x = 80

What is the cuboid volume and area formula

If the three sides of a cuboid are a, B and C, then
Volume v = a * b * C
Surface area | 2 (AB + BC + Ca)

It is known that cos (A-30) = 4 / 5 a belongs to (30,90), so it is necessary to find cosa

cos(a-30°)=4/5 ,0°≤a-30°≤60°
So sin (A-30 °) = 3 / 5
So cosa = cos (A-30 ° + 30 °)
=cos(a-30°)cos30°-sin(a-30°)sin30°
=4/5 * √3/2 - 3/5 * 1/2
=（4√3 -3）/10

9: 8 = (5 / 12 of X-12): X

9: 8 = (5 / 12 of X-12): X
9x=8（x-5/12）
x=-10/3

The quadratic function y = 3x ^ 2-12x + 12 is known
(1) Write out the symmetry axis and vertex coordinates of the quadratic function image
(2) Judge whether the point (- 1,27) is on the image of the quadratic function, and explain the reason

① X = - B / 2A = 12 / 2 × 3 = 2, y = C-B & sup2; - 4A = 12-12 & sup2; - 4 × 3 = 0. The axis of symmetry is: straight line x = 2, vertex coordinate is (2,0). ② when x = - 1, y = 3 × (- 1) & sup2; - 12 × (- 1) + 12 = 27

If there is a point P (a, - 2A) on the image with inverse scale function y = 1-2m / x, then the value range of M is

First, P (a, - 2A) is introduced into the inverse scale function to obtain a quadratic function of one variable with respect to a, and M is regarded as a parameter. Then, it is solved according to the limitation of quadratic equation of one variable

Calculation: 2 * 4 / 1 + 4 * 6 / 1 + 6 * 8 / 1... + 48 * 50 / 1
Please answer by 8:00 this evening

1/(2*4)+1/(4*6)+1/(6*8)+.+1/(48*50)
=1/2*[2/(2*4)+2/(4*6)+2/(6*8)+.+2/(48*50)
=1/2*[(4-2)/(2*4)+(6-4)/(4*6)+(8-6)/(6*8)+.+1/(48*50)
=1/2*[1/2-1/4+1/4-1/6+1/6-1/8+.+1/48-1/50]
=1/2[1/2-1/50]
=1/2*12/25
=6/25