Conversion of punctuation on keyboard The use of punctuation

General computer default is the symbol above the key, if you want to use the following punctuation, you need to use shift + this key

Every punctuation on the keyboard
I want to look up some things and need some punctuation marks. Excuse me, smart people, where can I find the black full stop? It's not an ordinary full stop, but a bigger and darker one. I've been looking for it for a long time, but I can't find it. Please,

shft＋K ،
shft＋P ؛
shft＋L /
The symbol is shft + qwerasx (each letter corresponds to a symbol, try it for yourself)

Given f (x) = (2 ^ (x + 1)) / (2 ^ x + 2), find f (1 / 100) + F (2 / 100) + F (3 / 100) +... + F (100 / 100)

F (1-x) = [2 ^ (1-x + 1)] / [2 ^ (1-x) + 2] = [2 ^ (2-x)] / [2 ^ (1-x) + 2] = (2 ^ 2) / [2 + 2 ^ (1 + x)] = 2 / (1 + 2 ^ x) calculate f (x) + F (1-x), get f (x) + F (1-x) = 2, so the original formula = [f (1 / 100) + F (99 / 100)] + [f (2 / 100) + F (98 / 100)] + +[f(49/100)+f(51/100)]+f(50/100)+f(1...

Equation application question 4 (5 20:58:25)
&#It is also shown that the 35;; \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\thisis the first time of the first time of \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\it's 160; & # 160; & # 160; & # 160; & # 160; & # 160; & # 160; & # 160; & # 160; & # 160; & # 160; & # 160; & # 160; & # 160; & # 160; & # 160; & # 160; & # 160; the second time
The purpose of this paper is to determine the number of vehicles, the number of vehicles, the number of vehicles, the number of vehicles, the number of vehicles, the number of vehicles, the number of \35;#35;35;35;35;35;35;35;35;#35;#\35\35\\35\\ \\\\\\\\\\j 160;;; 160;; \\\\\\\\\\\\\\\theresults show that it is #;; \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\35;160;, & #160;, & #160;, & #160;, & #160;, & #160;, & #160;, & #160;, & #160;, & #160;, & #160;, & #160;, & #160;, & #160; 5
The purpose of this paper is to determine the number of trucks and the number of vehicles of the number of vehicles of the number of vehicles of the number of vehicles of the number of vehicles of this kind of truck \\35;35;#35;35;35;35;35;35;##\35\\\\35\\ \\\\\\\\\\\\ \\\\\\\\\\\\\\theresults show that it is #;; \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\35;160;, & #160;, & #160;, & #160;, & #160;, & #160;, & #160;, & #160;, & #160;, & #160;, & #160;, & #160;, & #160;, & #160; 6
The purpose of this paper is to determine the total tonnage of \\\\\\\\\\\\\\\\\\ \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\theresults show that it is #;; \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\35;160; 100
Now we hire three A-type trucks and five B-type trucks from the company. We just finished the shipment at one time. If the freight is 200 yuan per ton, how much is the total freight payable?

The tonnage of freight cars of a and B is set as X and Y respectively
2x+3y=46
5x+6y=100
Solution
x=8
y=10
So 3x + 5Y = 24 + 50 = 74 (tons)
200 * 74 = 14800 yuan

Let a = 22 (sin17 ° + cos17 °), B = 2cos213 ° - 1, C = 32, then the size relation of a, B, C is______ ．

∵ a = sin (17 ° + 45 °) = sin 62 °, B = cos 26 ° = sin 64 °, C = sin 60 °, C < a < B, so the answer is: C < a < B

Acceleration a = 4-v to find the distance expression

The first inverse derivative of acceleration is velocity, and the first inverse derivative of a = 4-v is v = 4x-vx + C; the inverse derivative of velocity is distance, and the inverse derivative of V = 4x-vx + C is s = 2x ^ 2-1 / 2vx ^ 2 + CX; because C in the formula is an indefinite constant, other conditions are needed!

How to solve the equation of (2 / 5x + 4) / (x + 4) = 5 / 11
heh

Double 11 (x + 4)
11(2/5x+4)=5(x+4)
22/5x+44=5x+20
5x-22/5x=44-20
3/5x=24
x=24÷(3/5)
x=40
The fractional equation needs to be tested
After testing, x = 40 is the solution of the equation

∫(2x+x²) dx

∫(2x+x²) dx
＝x^2+1/3x^3+C

The vertex of image with quadratic function y = 0.8x & # - 0.2x-1 is

Y=4/5X^2-1/5X-1
=4/5［X^2-1/4X+(1/8)^2］-4/5×1/64-1
=4/5(X-1/8)^2-81/80,
Vertex (1 / 8, - 81 / 80)

Given that the point m (3p-15,3-p) is an integer of the third quadrant (both abscissa and ordinate are integers), the coordinate of the whole point m is?

Because m is the point of the third quadrant, the abscissa and ordinate are negative
3P-15 P3
And because the coordinates are integers, only p = 4
To sum up, the coordinates of point m are m (- 3, - 1)

Conversion of punctuation on keyboard The use of punctuation