It is known that the height of a cone is 4cm, the radius of the bottom circle is 3cm, the volume is, the surface area is, and the side area is?

It is known that the height of a cone is 4cm, the radius of the bottom circle is 3cm, the volume is, the surface area is, and the side area is?

3/2=1.5cm
Volume: 1.5 * 1.5 * 3.14 * 4 / 3 = 9.42

Write a program to calculate s = 2 + 3 / 2 + 4 / 3 + 5 / 4 + +51/50.

VB program private sub command1_ Click() Dim a,i As Integer i = 1 While i < 50 s = s + (i + 1) / i i = i + 1 Wend Print "s="; s End Sub

Circle C passes through three different points P (k, 0), q (2, 0) and R (0, 1). It is known that the tangent slope of circle C at point P is 1. Try to find the equation of circle C

Suppose that the equation of circle C is x2 + Y2 + DX + ey + F = 0, then K and 2 are two of x2 + DX + F = 0, ∧ K + 2 = - D, 2K = f, that is, d = - (K + 2), f = 2K, and then circulates over R (0, 1), so 1 + e + F = 0. ∧ e = - 2k-1

It is known that A1, A2, A3, A4 and A5 are five different integers satisfying the condition a1 + A2 + a3 + A4 + A5 = 9. If B is the integer root of the equation (x-a1) (x-a2) (x-a3) (x-a4) (x-a5) = 2009 about X, then the value of B is______ ．

Because (b-a1) (b-a2) (b-a3) (b-a4) (b-a5) = 2009, and A1, A2, A3, A4, A5 are five different integers, all b-a1, b-a2, b-a3, b-a4, b-a5 are also five different integers

Given that real numbers x and y satisfy x ^ 2 / 4 + y ^ 2 = 1, find the minimum value of 2x + 3Y

Let s = 2x + 3Y
Substituting y = (s-2x) / 3 into X & # 178 / 4 + Y & # 178; = 1, we get
x²/4+(s-2x)²/9=1
After finishing, we have to
25x²-16sx+4s²-36=0
△=(16s)²-4*25*(4s²-36)≥0
-144s²+3600≥0
|s|≤5
-5≤s≤5
The minimum value of 2x + 3Y is - 5

The reciprocal of a number is 2 / 3. What is 5 / 12 of this number
Come on, prawns

If the reciprocal is 2 / 3, then this number is 3 / 2, and 5 / 12 of this number is 3 / 2 * 5 / 12 = 5 / 8

x+y+z=5 5x+4y+z=19 3x+y-4z=4
I'm helping a few. 3x+4z=17-y x+y=7-z y+3z-9=0
The second 2x + 4Y + 3Y = 11 3x-2y + 5Z = 9 5x-6y + 7z = 11

To solve the original system of equations, ① system x + y + Z = 5 5x + 4Y + Z = 19 3x + y-4z = 4, ② system 3x + 4Z = 17-y x + y = 7-z, y + 3z-9 = 0, ③ system should be 2x + 4Y + 3Z = 11 3x-2y + 5Z = 9 5x-6y + 7z = 11, a set of positive integer solutions are obtained as follows: ① system x = 2, y = 2, z = 1, ② system x = 2, y = 3, z = 2, ③ system x = 2, y = 1, z = 1

As a logarithm algorithm: LG (a + b) = LGA + LGB (a > 0, b > 0) is incorrect. But it is true for some special values, such as LG (2 + 2) = LG2 + LG2. Then, for all a that make LG (a + b) LGA + LGB (a > 0, b > 0) true, B should satisfy the function a = f (b) expression as___ ．

According to the known condition LG (f (b) + b) = LGF (b) + LGB = LG [BF (b)], so f (b) + B = BF (b), f (b) = Bb-1, according to the definition field of logarithmic function, b > 0 and F (b) = Bb-1 > 0, so b > 1, a = Bb-1 (b > 1)

It is known that the quadratic function f (x) = ax square + BX (a, B are constants, and a ≠ 0) satisfies the condition f (x + 1) = f (1-x), and the equation f (x) = x has equal roots
(1) Find out if there is real number m, n (m) in the analytic expression (2) of F (x)

(1) If f (x) = a (x ^ 2) + BX satisfies f (x + 1) = f (1-x), then: X (2a + b) = 0, that is, 2A + B = 0. If f (x) = x has equal roots, then: (B-1) ^ 2 = 0, that is, B = 1. So: a = - 1 / 2, so: F (x) = (- 1 / 2) (x ^ 2) + X (2) exists

According to the known conditions, the analytic expression of the following function is determined. The vertex of the parabola is known to be on the x-axis and passes through the point (1,0) (- 2,4)

So let y = ax & # 178; + BX;
Bring in (1,0) a + B = 0;
The results show that (- 2,4) 4a-2b = 4;
6a=4;
a=2/3;
b=-2/3;
∴y=2x²/3-2x/3;
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