In the romance of the Three Kingdoms, Zhuge Liang, a military strategist, is the incarnation of a wise man. Many of his well-known deeds are recorded in the book, such as burning what?

In the romance of the Three Kingdoms, Zhuge Liang, a military strategist, is the incarnation of a wise man. Many of his well-known deeds are recorded in the book, such as burning what?


You want to ask, burning red cliff? This should be the most famous one



The incarnation of Zhongwen in the romance of the Three Kingdoms is (). As we know, his loyalty, righteousness and pride are (), the wise incarnate as a military adviser (), and his affairs
()()()


The incarnation of loyalty and righteousness is Guan Yu, riding alone for thousands of miles, Huarong daoyishi (Cao Cao), flooding the seven armies,
The incarnation of the wise is Zhuge Liang, who burns red cliff with fire, borrows arrow from straw boat, borrows east wind, three Qi, Zhou Yu, and seven catches Meng Huo,



What is the limit power of 380V industrial power?


380 times root 2



Given that the sequence {an} satisfies A1 = 1, A2 = a (a ≠ 0) an + 2 = P × (an + 1) & # / an (other p is a non-zero constant, n ∈ n *), judge that the sequence {an + 1 / an} is not an equal ratio sequence (2) find an, (3) when a = 1, let BN = Nan + 2 / an, Sn be the sum of the first n terms of BN, find SN





Aluminum blocks with length, width, height of 10cm, 5cm and 2cm, density of (2.7 * 10 ^ 3) kg / m ^ 3. Put them in the center of the desktop with an area of 1m ^ 2, and calculate the maximum pressure of the aluminum block on the desktop
There is an aluminum block with the length, width and height of 10cm, 5cm and 2cm respectively, and the density is (2.7 * 10 ^ 3) kg / m ^ 3. Put the aluminum block in the center of the horizontal desktop with an area of 1m2, and calculate the maximum pressure of the aluminum block on the desktop. (G is 10N / kg)


The maximum pressure is gravity
The maximum pressure must be the minimum contact area
The pressure of 2cm * 5cm surface on the desktop is the highest



______ It's called the first level operation______ It's called the second level operation


According to the definition of four operations, addition and subtraction are called first level operations, multiplication and division are called second level operations



When a student used two range voltmeters (0 ~ 3V and 0 ~ 15V) to measure the voltage of the battery pack composed of two dry batteries in series, he recorded 15V
The cause of the error is () the actual voltage should be () v


When a student used two range voltmeters (0 ~ 3V and 0 ~ 15V) to measure the voltage of the battery pack composed of two dry batteries in series, he recorded 15V. The reason for his error was that (the range was selected as 0 ~ 15V) the actual voltage should be (3) v



1 / 3-2 / 15 + 3 / 35-4 / 63 + 5 / 99-6 / 143 = simple algorithm,


1/3-2/15+3/35-4/63+5/99-6/143=[1/3-2/(3×5)]+[3/(5×7)-4/(7×9)]+[5/(9×11)-6/(11×13)]=1/3×(1-2/5)+1/7×(3/5-4/9)+1/11×(5/9-6/13)=1/3×3/5+1/7×7/45+1/11×11/117=1/5+1/45+1/117=2/9+1/117=1/9...



4 Calculation questions
1. (- 36) * (5 / 4 - 5 / 6 - 11 / 12)
2.-4*7-(-3)*6+5
3. - 1 - [1 - (1-0.5 * one third)] * 6
4. (1 / 2-5 / 9 + 7 / 12) * - 72


1.18
2.-5
3.-2
4.-38



Known hyperbola: x ^ 2 / 4-y ^ 2 / 12 = 1, whether there is a chord of hyperbola with a (1,1) as the midpoint, if there is, ask for the equation of the straight line, if not, explain the reason


Y-1 = K (x-1) y = KX + 1-k is substituted into 3x & sup2; - Y & sup2; = 12 (3-K & sup2;) x & sup2; - 2K (1-k) x - (1-k) & sup2; - 12 = 0x1 + x2 = 2K (1-k) / (3-K & sup2;) midpoint abscissa = (x1 + x2) / 2 = K (1-k) / (3-K & sup2;) = 1k-k & sup2; = 3-K & sup2; k = 3, so existence is 3x-y-2 = 0