Factorization of 2 (A-3) & # - a = 3

Factorization of 2 (A-3) & # - a = 3

2（a-3)²-a-3
(-5 + a) (-3 + 2 a)
A = 5 or 3 / 2

How many grams is one cow?

9.8 N / kg 9.8 N / 1000 g, so 1 n equals 1000 divided by 9.8 is about 100 g

It is known that 31 = 3, 32 = 9, 33 = 27, 34 = 81, 35 = 243, 36 = 729, 37 = 2187, 38 = 6561 Find (3-1) (3 + 1) (32 + 1) (34 + 1) · · (332 + 1) + 2

The original formula = (3-1) (3 + 1) (32 + 1) (34 + 1) (38 + 1) (316 + 1) (332 + 1) + 2 = (32-1) (32 + 1) (34 + 1) (38 + 1) (332 + 1) + 2 = (34-1) (34 + 1) (38 + 1) (316 + 1) (332 + 1) + 2 = (38-1) (38 + 1) (316 + 1) (332 + 1) + 2 = (316-1) (316 + 1) (332 + 1) + 2 = (332-1) (332 + 1) + 2 = 364-1 + 2 = 364 + 1, 64 △ 4 = 16, so 364 and 3 The four digits are the same as 1, so (3-1) (3 + 1) (32 + 1) (34 + 1) · · (332 + 1) + 2 is 1 + 1 = 2

For example, a voltmeter measures the voltage of a sliding rheostat [bzq], and then increases the resistance of bzq and decreases the current. Does the voltage of bzq increase?
As I understand it, I = u divided by R, I decrease, R increases, and then because r increases, u also increases
Under the analysis,

Your understanding has confused two concepts: 1. In the case of constant voltage, the current is inversely proportional to the resistance; 2. In the case of constant current, the voltage is directly proportional to the resistance, and your concept I = u divided by R I decreases, R rises is right, and because r rises, so u also rises is wrong, because this is the conclusion in the case of constant current

Given two points n (0,1), m (0, - 1), the projection of the moving point P on the x-axis is h, and the vector PM × vector PN = 4 / 3, the vector pH ^ 2
(1) The equation for finding the locus C of the moving point P

Let P (x, y); then the coordinates of vector PM = (x, y + 1); PN = (x, Y-1); pH ^ 2 = y ^ 2;
Vector PM × vector PN = 4 / 3, vector pH ^ 2; that is: x ^ 2 + (y + 1) (Y-1) = (4 / 3) y ^ 2
That is, the equation of the trajectory C of the obtained point P: x ^ 2-y ^ 2 / 3 = 1

Junior high school physics formula_ Junior high school physics formula

11. The velocity formula of uniform linear motion: velocity: v = s / T distance: S = VT time: T = s / V
2. The velocity formula of variable speed linear motion: v = s / T
3. Relationship between weight and mass: g = Mg (g = 9.8N / kg)
5. Calculation and weighing method of buoyancy: F floating = G-F formula method: F floating = g row = ρ row V row g floating method: F floating = g substance (V row < V substance) suspension method: F floating = g substance (V row = V substance)
6. Lever balance condition: f1l1 = f2l2
7. Definition of work: w = FS
8. Power definition: P = w / T for uniform linear motion: P = Fv (F is power)
9. Mechanical efficiency: η = w useful / W total for lifting objects: W useful = GH (H is the height) w total = FS 10, slope formula: FL = GH 11, heat absorption and heat release when the object temperature changes, Q absorption = cm Δ t (Δ t = t-t0) Q discharge = cm Δ t (Δ t = t0-t) 12, calculation of heat release from fuel combustion: Q discharge = QM
13. Heat balance equation: Q suction = q discharge 14, heat engine efficiency: η = w useful / Q discharge (Q discharge = QM) 15, current definition formula: I = q / T (q is electric quantity, unit is Coulomb)
16. Ohm's Law: I = u / R deforming for voltage: u = IR deforming for resistance: r = u / I 17. Characteristics of series circuit: (take two pure resistance electrical appliances in series as an example) relationship of voltage: u = U1 + U2 relationship of current: I = I1 = I2 relationship of resistance: r = R1 + R2. These experiments can be found in VCM simulation experiment, and can be operated
18. Characteristics of parallel circuit: (take two pure resistance type electrical appliances in parallel as an example) voltage relationship: u = U1 = U2, current relationship: I = I1 + I2, resistance relationship: 1 / r = 1 / R1 + 1 / r2 19, electric power calculation: w = uit 20, definition formula of electric power: P = w / T, common formula: P = u

When the amplitude is a, the maximum pressure of the object on the spring is 1.5 times of the gravity of the object. What is the minimum elastic force of the object on the spring? If the object does not leave the spring in vibration, how much can the amplitude not exceed? The answer is that when a = G at the highest point, it is the critical condition, Objects will fly out. Why? I can't think of it!

Because the object and the spring are not connected, the object is on the spring, when the hand of the object is under gravity, the acceleration is g. at this time, the spring does not exert force on the object. If the object rises, the spring will not be elongated, and the object will leave the spring, so at that point a = g, and it is the highest point
In this case, the resultant force of the end objects at both ends of the simple harmonic motion is the same and the direction is opposite, so at the low end, the resultant force is 0.5mg vertically upward. At the top, if the resultant force is 0.5mg vertically downward, it is 0.5mg upward spring force. At this time, the resultant force is 0.5mg vertically downward, and the minimum spring force is 0.5mg at the highest point
If the object does not leave the spring in vibration, the highest point is the moment when the object and the spring will leave. At this time, the object is only subject to gravity, Hollysys g, so the resultant force at the bottom is also g, so the bottom must have a vertical upward force of 2mg to make the resultant force mg and vertical upward. If the elastic force is proportional to the compression distance of the spring, then 2:1.5 = s: a
S=4/3*A

1kW is equal to several kilowatts of electricity. How long does it take to consume 1kW

One kilowatt hour (kW. H) is one kilowatt hour electricity consumption of a 1kW power consumer

A balance and a spring dynamometer are used to measure the same object on the earth and the moon respectively
A. Balance spring dynamometer measures the same B. balance measures the same, spring dynamometer measures different C. balance measures different, spring dynamometer measures the same D. balance, spring dynamometer measures are different

(1) If the balance works under the condition of lever balance, the mass of the object and the weight remain unchanged, and the gravity becomes the original 16. The lever is still balanced, so the measured mass remains unchanged, so the measurement results are the same. (2) the gravity of the object from the earth to the moon becomes the original 16, the tension of the object on the spring becomes the original 16, and the indication of the spring dynamometer becomes the original 16 16, so the measurement results are different

A cylindrical bucket with a diameter of 30cm and a height of 60cm is used to add water to the bucket. The volume of water in the bucket is V (cubic meter) and the height of water is cm
Also, what is the function of the independent variable and what is the value range of the independent variable

V=πR^2h
=πX15^2h
=225 π H (CC)
=2.25 π H x 10 ^ (- 4) (M3)
The range of independent variable H is 0 ≤ h ≤ 60 cm