Translation of an English essay I have some good frends who live in Hilltop Village.I like to go there to play with them.We like to play in the park,which is called Central Park.Ken Road goes along one side of the park,and Green Street goes along another side of the park.Green Street joins Ken Road.On the corner of the Ken Road and Green Street is Sally`s house.Helen lives next to Sally.Across the street from Sally and Helen is Jenny`s house.She lives next to Mary.Across the street from Mary`s house is a small hotel called the Golden Dragon.It is on the corner of Green Street and Ken Road,next to the hospital. Please translate this passage for me, add 100 points correctly

Translation of an English essay I have some good frends who live in Hilltop Village.I like to go there to play with them.We like to play in the park,which is called Central Park.Ken Road goes along one side of the park,and Green Street goes along another side of the park.Green Street joins Ken Road.On the corner of the Ken Road and Green Street is Sally`s house.Helen lives next to Sally.Across the street from Sally and Helen is Jenny`s house.She lives next to Mary.Across the street from Mary`s house is a small hotel called the Golden Dragon.It is on the corner of Green Street and Ken Road,next to the hospital. Please translate this passage for me, add 100 points correctly


I have some good friends who live in hilltop. I like to go there and play with them. We like to go to a park called central park. Kent road is along one side of the park, green street is along the other side of the park. At the intersection of Kent road and green street is Sally's home. Helen lives next to Sally's home. Jenny lives opposite Sally's and Helen's home, Next door to Mary. Opposite Mary's house is a small hotel named Jinlong. It's located at the junction of Green Street and Kent Road, next to the hospital



English translation
Whales are found in open seas throughout the world and occasionally in coastal waters,as well.Certain species migrate,while others remain yearround in the same habitats.The skin of whales is usually black,gray,tan and white.Their skin texture is smooth,but like other mammals,whales have hair at some point in their developmet.In adutls it's ustally foumd only gn the head area,and in some spdcies only in the fetus.Whales store energy in an underskin layer of fat,or blubber.the ability to store "fuel" in the form of blubber helps wiales survive during long periods of starvation.Except for having horizontal tails that move up and down,rather than side to side, whales have tie general shape of fish,though in certain species the head is greatly enlarged.Over millions of years,hind limbs remain.Whales breathe through lungs,with some large species remaiming under water for as long as two hours.(1)what dose thd text mianly tell us?(not more than 10 words)





The problem of selecting free variables
I know that nonprincipal elements are usually listed as free variables, but it should be OK. I want to know what the principle is, for example, there is such a problem
1 -1 2 0 3
0 0 1 3 -2
0 0 0 0 6
Ask you if you can't take a free variable
A x4.x5 B x2,x3 C x2,x4 D x1,x3
Because the first three columns are linearly related, then the answer means that the free variables you choose should make the rest irrelevant, and then you can choose according to the principle that the number of free variables = n-ra?


The answer is wrong!
This should be (c)
The variables (x1, X3, x5) corresponding to the columns (1, 3, 5) of the first non-zero element of non-zero rows (1, 2, 3) are constraint variables,
The rest (X2, x4) are free unknowns
I don't know if I understand



How much is the square of X - 5x + 4 = 0?


X ^ 2-5x + 4 = 0, that is, (x-1) (x-4) = 0, so x = 1 or x = 4



If the set a = {y | y = x & # 178; + 2x = 1, X ∈ r}, B = {y | y = x & # 178; - 2x, X ∈ r}, then a ∩ B=_________
RT
Please write the answer and the solution, thank you!


A={y|y=x²+2x+1,x∈R}={y|y=(x+1)^2>=0}={y|y>=0}
B={y|y=x²-2x,x∈R}={y|y=(x-1)^2-1>=-1}={y|y>=-1}
Then a ∩ B = {y | Y > = 0}



How to calculate 18N + [n (n-1) / 2] * (- 3) = 54,


18n+[n(n-1)/2]*(-3)=54
36n-3n(n-1)=108
36n-3n^2+3n=108
-3n^2+39n=108
3n^2-39n=-108
n^2-13n=-36
n^2-13n+169/4=-36+ 169/4
(n- 13/2 )^2=25/4
n- 13/2 =±5/2
n=±5/2+ 13/2
N = 9 or n = 4



Given the function FX = x + A / x, and F1 = 21, find a 2, and prove by definition that the function FX = x + 1 / X is in the interval [1,
Given the function FX = x + A / x, and F1 = 21, find A2, prove by definition that the function FX = x + 1 / X is an increasing function in the interval [1, + infinity]





It is known that the coordinates of three vertices of a triangle are a (8,5), B (4, - 2), C (- 6,3). The equations of three straight lines passing through two kinds of points are obtained


The midpoint of AB is d (6,1.5)
The midpoint of BC is e (- 1,0.5)
The midpoint of AC is f (1,4)
The De is y = 1 / 7X + 9 / 14
The EF is y = 1.75x + 3.5
DF is y = - 0.5x + 4.5



The electric energy meter says: 3000r / kW. H. If the turntable turns 30 times in 6min, the total power of the connected electric appliance is___ .


3000r / kW · h means to turn 3000 circles to walk 1kW · h, then 30 circles is 30 / 3000 = 1 / 100kW · h, 6 minutes = 6 / 60 hours = 1 / 10h, then the total power of the connected electrical appliances is p = w / T = (1 / 100) / (1 / 10) = 0.1kw = 100w3000r / kW. H. If the turntable turns 30 circles in 6min, then the total power of the connected electrical appliances is_ 0.1K...



If | A-1 | + (B + 2) is quadratic = 0, find the value of (a + b) to the power of 208 + A to the power of 201


|The second power of A-1 | + (B + 2) = 0
So: A-1 = 0
b+2=0
So: a = 1, B = - 2
(a + b) to the power of 208 + A to the power of 201
=1 + 1
= 2
If you don't understand, you can continue to ask this question
Please select it as a satisfactory answer in time,